GIVING BRAINLY!!!!! PLSSSSS HELPPPPthe sum of two whole numbers is 63 . The difference between these 2 whole numbers is less than 10. FInd all the possible pairs

Answers

Answer 1
Answer:

Answer:

(32, 31) (33,30) (34, 29) (35, 28) (36,27) (37, 26)

Step-by-step explanation:

Answer 2
Answer:

Final answer:

The pairs of whole numbers that add to 63 and have a difference less than 10 are (27, 36), (28, 35), (29, 34), (30, 33), and (31, 32).

Explanation:

This problem is based in the domain of basic algebra. Essentially, you are being asked to find pairs of whole numbers that, added together, equal 63, with the condition that the difference between these two numbers is less than 10.

Starting from the number 32 (as any larger number plus any number greater than 0 would exceed 63), you can begin to list pairs, subtracting one number from the total of 63 while simultaneously adding that same amount to the other half of the pair. This will ensure that the sum always equals 63.

Here are the pairs satisfying the given conditions: (27, 36), (28, 35), (29, 34), (30, 33), (31, 32). For these pairs, the difference between the two numbers in each pair is less than 10.

Learn more about Number Pairs here:

brainly.com/question/35870312

#SPJ3


Related Questions

You buy a gym membership for $60 and then pay $40 each month. If you have atmost $210 to spend on the membership, how many months can you use thegym?​
What is the next number after 3 -6 12 4 20
Given the expression 2x(y + z)2, which is TRUE? A) The factor 2x depends on (y + z)2. B) The factor (y + z)2 depends on 2x. C) The factors 2x and (y + z)2 are dependent of each other. D) The factors 2x and (y + z)2 are independent of each other.
Evaluate each function.k(a) = |-2a + 3| - 1; Find k(3).g(x) = 4^2x-1 + 7; Find g(1).f(x) = |8x^2 - 5x + 3|; Find f(-2).h(x) = -3x + 9; Find h(-1 + x).f(n) = 5n - 1, Find f(- 3n).
F(x) =x2 + x + 16(x-4)SEREg(x) = x2+x+18(x-4)Which statement comparing the oblique asymptotes of the functions f(x) and g(x) is true?The oblique asymptote for g(x) is steeper than for f(x).Both functions have the same oblique asymptote.The oblique asymptote for f(x) is steeper than for g(x).Both functions have parallel oblique asymptotes.

6.2.Find the triangle bounded by the y-axis the line f(x)=9- 6/7x and the line perpendicular to it that passes through the origin

Answers

First.

We need to find the triangle bounded by the y-axis the line f(x)=9-(6)/(7)x and the line perpendicular to it that passes through the origin.

This triangle is illustrated in the First Figure bellow. The triangle has been dotted with black dots. So, let's identify each part of this graph:


  • The y-axis has been identified by the green line.
  • The linef(x)=9-(6)/(7)x has been identified by the red line.
  • To plot the line perpendicular to the previous one that passes through the origin, we need to know that the product of the slopes of two perpendicular lines is m_(1)m_(2)=-1 \therefore Since \ m_(1)=-(6)/(7) \ then \ m_(2)=(7)/(6)

        Therefore, this line is the blue one and is written as:

         f(x)=(7)/(6)x


Second.

a.

To find y(t) we need to find the slope and y-intercept. So, taking two points:

P_(1)(15,150) \ and \ P_(2)(25,450) \n \nm=(450-150)/(25-15)=30


So:

Using \ P_(1)(15,150) \n\ny=30t+b\n\n150=30(15)+b \therefore b=-300 \n\n\boxed{y(t)=30t-300}


Third.

b.

The y-intercept is b=-300 and has been calculated above. This value represents the profit in thousands of dollars in 1980, that is, there is no any profit or there is a lost of $300.000.


Fourth.

c.

The x-intercept can be found when y=0 (year 1980), that is:

y(t)=30t-300 \n\n0=30t-300 \therefore t=10


This value shows that there is no any profit for the company at the year that represents t=10 (year 1990), because at this point the company starts earning money.


Fifth.

d.

The slope of this function is m=30


This value tells you that the profit increases $30.000 each year.

Hello,

Please, see the attached files.

Thanks.

Change 11/5 from an improper fraction to a mixed number

Answers

Solution: 11/5 as a mixed number is 2 1/5.

What is the area of a circular pool with a diameter of 36 ft?

Answers

Answer:

1,017.36ft^2

Explanation:

Area of the circular pool = \pi r^2

r is the radius of the pool

Given

r = d/2

r = 36/2

r = 18ft

Area of the circular pool = 3.14(18)^2

Area of the circular pool = 3.14 * 324

Area of the circular pool = 1,017.36ft^2

Josie bought 750 bags of peanuts for $375 he intends to sell each bag for $.15 more than you paid how much should he charge for each bag

Answers

Step-by-step explanation:

Jose bought 750 bags for $375.00

Each bag cost $375/750= $0.50

He  intends to sells them for $0.15 more

He should charge : $0.5 +$0.15=$0.65

Help me pls thank you

Answers

Answer:

7

Step-by-step explanation:

To solve this, we have to solve for h.

We can use order of operations to figure this one out.

18h-9h-7h+3=17\n18h-9h-7h=14

Now that every variable on the left side of the equation has an h, we can factor.

h(18-9-7)=14\nh=(14)/(18-9-7) \nh=(14)/(2) \nh=7

Answer:

6

I just did some trial and error with the numbers

186-96-76+3=17

Unless I did it wrong, then just ignore this answer

Find the first derivative for y = f(x). fox ) 3x² -5x-1 at a Pocat where a = 4​

Answers

Answer:

Step-by-step explanation:

f(x) = 3x² -5x - 1

f'(x) =2*3x - 5*1 +0

     = 6x - 5

f'(4) = 6*4 - 5

      = 24 - 5

      = 19

Other Questions