A local BBQ restaurants offers 2 side dishes with a lunch plate. There are 7 side dishes. How many choices of side dishes does a customer have

Answers

Answer 1
Answer:

Step-by-step explanation:

This is a question that bothers combination. Combination has to do with selection.

When selecting r objects out of a pool of n objects, the number of ways this can be done is:

nCr = n!/(n-r)!r!

If a local BBQ restaurants offers 2 side dishes with a lunch plate, and there are 7 side dishes, the number of choices that the customer have is expressed as:

7C2 = 7!/(7-2)!2!

7C2 = 7!/(5)!2!

7C2 = 7*6*5!/5! * 2

7C2 = 7*6/2

7C2 = 42/2

7C2 = 21 choices

Hence the customer has 21 choices of side dishes to make


Related Questions

Convert 4.274.27 toimproper fraction​
Please help help help
Which exponential equation is equivalent to this logarithmic equation log x5 + log x12 =7
7. Falls Canyon has an area of 1458 square miles. If the population density of deer is 50 deer per square mile, what is the total population of deer, rounded to the nearest thousand?70,00010,00073,0007,000
Write this fraction in the simplest form 15/25

A boat is heading towards a lighthouse, whose beacon-light is 131 feet above thewater. From point A, the boat's crew measures the angle of elevation to the beacon,
5°, before they draw closer. They measure the angle of elevation a second time from
point B at some later time to be 21°. Find the distance from point A to point B.
Round your answer to the nearest tenth of a foot if necessary.

Answers

Answer:

Step-by-step explanation:

Assuming a flat earth

initial measurement

tan5 = 131 / d₁

d₁ = 131/tan5 = 1,497.3368... ft

d₂ = 131/tan21 = 341.2666674...ft

distance from A to B

1497.3368 - 341.26666 = 1,156.1 ft

Rather daring to specify to the answer to the nearest tenth of a foot when no given measurement accuracy is even close to that same precision.

Final answer:

This is a trigonometry problem that can be solved by using the tangent function to find the distances from the boat to the lighthouse at two different angles of elevation, and then subtracting to find the distance travelled by the boat.

Explanation:

This question involves the concept of trigonometry, specifically inverse trigonometric functions. We can solve it by creating two right triangles and using the trigonometric function known as tangent. Due to the nature of the problem, we will consider the lighthouse as the opposite side while the distance from the boat to the lighthouse will serve as the adjacent side.

When the boat is at point A, we can write the following equation using the tangent of 5° - tan(5°) = 131/DistanceA. Solve this equation to find DistanceA.

Next, do the same when the boat is at point B. The equation for this scenario is - tan(21°) = 131/DistanceB. Resolve this equation to find DistanceB.

The distance from point A to B (which is what the question asks for) is just the difference between DistanceA and DistanceB. Make sure to take the absolute value to avoid a negative distance, and round the result to the nearest tenth of a foot if necessary.

Learn more about Trigonometry here:

brainly.com/question/31896723

#SPJ11

The probabilities of poor print quality given no printer problem, misaligned paper, high ink viscosity, or printer-head debris are 0, 0.3, 0.4, and 0.6, respectively. The probabilities of no printer problem, misaligned paper, high ink viscosity, or printer-head debris are 0.8, 0.02, 0.08, and 0.1, respectively. a. Determine the probability of high ink viscosity given poor print quality.
b. Given poor print quality, what problem is most likely?

Answers

Answer and explanation:

Given : The probabilities of poor print quality given no printer problem, misaligned paper, high ink viscosity, or printer-head debris are 0, 0.3, 0.4, and 0.6, respectively.

The probabilities of no printer problem, misaligned paper, high ink viscosity, or printer-head debris are 0.8, 0.02, 0.08, and 0.1, respectively.

Let the event E denote the poor print quality.

Let the event A be the no printer problem i.e. P(A)=0.8

Let the event B be the misaligned paper i.e. P(B)=0.02

Let the event C be the high ink viscosity i.e. P(C)=0.08

Let the event D be the printer-head debris i.e. P(D)=0.1

and the probabilities of poor print quality given printers are

P(E|A)=0,\ P(E|B)=0.3,\ P(E|C)=0.4,\ P(E|D)=0.6

First we calculate the probability that print quality is poor,

P(E)=P(A)P(E|A)+P(B)P(E|B)+P(C)P(E|C)+P(D)P(E|D)

P(E)=(0)(0.8)+(0.3)(0.02)+(0.4)(0.08)+(0.6)(0.1)

P(E)=0+0.006+0.032+0.06

P(E)=0.098

a. Determine the probability of high ink viscosity given poor print quality.

P(C|E)=(P(E|C)P(C))/(P(E))

P(C|E)=(0.4* 0.08)/(0.098)

P(C|E)=(0.032)/(0.098)

P(C|E)=0.3265

b. Given poor print quality, what problem is most likely?

Probability of no printer problem given poor quality is

P(A|E)=(P(E|A)P(A))/(P(E))

P(A|E)=(0* 0.8)/(0.098)

P(A|E)=(0)/(0.098)

P(A|E)=0

Probability of misaligned paper given poor quality is

P(B|E)=(P(E|B)P(B))/(P(E))

P(B|E)=(0.3* 0.02)/(0.098)

P(B|E)=(0.006)/(0.098)

P(B|E)=0.0612

Probability of printer-head debris given poor quality is

P(D|E)=(P(E|D)P(D))/(P(E))

P(D|E)=(0.6* 0.1)/(0.098)

P(D|E)=(0.06)/(0.098)

P(D|E)=0.6122

From the above conditional probabilities,

The printer-head debris problem is most likely given that print quality is poor.

Answer:

Answer of Part(a) is 16/49

and Answer of Part(b) is Printer-head debris

Step-by-step explanation:

Answer is in the following attachment

Kelly takes out a loan with the stated rate of 12% interest. If the interest is calculated weekly, how much greater is Kelly’s effective rate (The growth rate of compounded amount) Then her stated rate (the “stated” 12%)? Does the difference in effective rate and stated rate change depending on 1 year or 10 years ? Please answer this step if you can! Greatly appreciate it.

Answers

Answer:

12.73%

Step-by-step explanation:

Given the annual rate is 12% compounded weekly.

Let's assume 1 yr=52weeks.

The effective interest rate is calculated as:

i_m=(1+r/m)^m-1, r=annual\  rate\n\ni_(52)=(1+0.12/52)^(52)-1\n\ni_(52)=0.1273

Hence, the effective rate for 12% compounded weekly is 12.73%

-The effective rate will be different when the number of compounding times is less than or more than 1 year.

- the effective rate is equal to the stated rate if the compounding number of times is once per year.

4,275.50= 391/2 of ____

Answers

Answer:

The required value for the blank is 21.8696

Step-by-step explanation:

Consider the provided information,

4,275.50= 391/2 of ____

Replace blank with x.

4,275.50 = 391/2 of x

Use sign of multiplication for "of".

4,275.50 = (391)/(2) * x

Solve the above expression for x.

x=(4,275.50* 2)/(391)

x=21.8696

Thus, the required value for the blank is 21.8696

Find the surface area of the cone in terms of pie 18 height 12 radius

Answers

144π cm²

Answer:

Solution given:

diameter (d)= 12cm

radius (r)=12/2=6 cm

slant height(l)=18cm

Now

Total surface area of cone=πr(r+l)π*6(6+18)=144π cm²

Help!! Is anyone good at algebra??

Answers

Answer:

h = 20 m

Step-by-step explanation:

So you know volume of a cylinder = π*(r^2) * h

and you also know volume of this cylinder = 180π

(volume is also in meters^3)

you can set these volumes equal to one another

180π = π*(r^2) * h

by dividing by π you get this:

180 = (r^2) * h

you need h so you can divide by r^2 to get this

h = 180 / (r^2)

now you just need to plug in the radius you are given which was 3 meters

h = 180 m^3 / (3 m^2)

h = 180 m^ 3 / 9 m^2

h = 20 m