What is the mass of 1 cm³ of water
Answers
Answer:
approximately one gram
The mass of one cubic centimetre of water at 3.98 °C (the temperature at which it attains its maximum density) is closely equal to one gram. The basic unit of measurement for mass in the metric system; one cubic centimeter of water has a mass of approximately one gram.
Answer:one gram
Explanation:
Related Questions
Describe two reasons why an alpha particle is less penetrating than a beta or gamma particle.
A 2,100 kg car is lifted by a pulley. If the cable breaks at 4.50 m, what is the velocity of the car when it hits the ground
Can someone help with number 4 please
At a temperature of 280k, the gas in a cylinder has a volume of 20.0 liters.If the volume of the gas is decreased to 10.0 liters, what must the temperature be for the gas to remain at a constant pressure?
b) between 1 kW and 10 kW
c) more than 10 kW
Please show calculations!
Answers
The potential energy of each kg of water, before it falls, is
(M G H) = (1kg) (9.8 m/s²) x (30 m) = 294 joules
The potential energy lost by 60 kg of water pouring through is
(60 x 294) = 17,640 joules
The power output of the plant is
(17,640 joules/sec) x (85%) = 14,994 watts
= almost but not quite 15 kW.
(If you used 10 for gravity, it would come out to 15.3 kW)
Answers
⚘ YourAnswers:
A) Valency is the combining capacity of any element. Valence electrons refers to the electrons found in the outermost shell of the atom of the element.
B) Symbol and valency:
- Oxygen(O) = (At. no. 8) = -2(Valency)
- Potassium(K) = (At. no. = 19) = +1(Valency)
C) The reaction would be:
- Reactants = Magnesium and Oxygen
- Products = Magnesium oxide
- Word equation:
━━━━━━━━━━━━━━━━━━━━
Answer:
Oxygen-Symbol-O Potassium Symbol-K
Answers
Answer:
Speed of the bicyclist when going to city = 14 miles per hour.
Speed while return trip = 8 miles per hour.
Explanation:
Let the speed of the bicyclist when going to city = x miles per hour.
Speed while return trip = x - 6 miles per hour.
Total time taken = 11 hrs = Time for the trip to city + time taken for return trip.
Also, Time = Distance / Time.
So,
56 / x + 56 / ( x -6) = 11
11x² -178x + 336 = 0
Solving for x we get:
Acceptable x = 14 miles per hour.
Speed while return trip = x - 6 miles per hour = 8 miles per hour.
Final answer:
To find the average speed on each part of the trip, use the formula Average speed = Total distance/Total time and set up an equation to solve for the unknown speeds.
Explanation:
To find the average speed on each part of the trip, we can use the formula Average speed = Total distance/Total time. Let's assume the average speed on the first part of the trip (56 miles) is x mph. Since the return trip is made at a speed that is 6 mph slower, the average speed on the second part of the trip is (x - 6) mph. We know that the total time for the round trip is 11 hours. So, we can set up the equation:
56/x + 56/(x - 6) = 11
Now, we can solve this equation to find the value of x, which represents the average speed on the first part of the trip. Once we have x, we can find the average speed on the second part of the trip by subtracting 6 from x.
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B. 17,705.1 J
C. 20,075.04 J
D. 51,302.88 J
Please include how you got your answer , thank you.
Answers
Answer:
B. 17,705.1 J
Explanation:
The hear released when the mercury condenses into a liquid is given by:
where
m = 0.06 kg is the mass of the mercury
is the latent heat of vaporization
For mercury, the latent heat of vaporization is , so the heat released during the process is:
So, the closest option is
B. 17,705.1 J
The energy ( in joules ) released when 0.06 kilograms ofmercury is condensed to a liquid at the same temperature is about 697.08 J. inother to solve this problem, should know the latent heat of fusion of mercurywhich is equal to about 11.4 kJ/kg and multiplying by mass of mercury.
Answers
Answer:
1.87 s
Explanation:
Initial speed of throw = 9.20 m/s
Net vertical displacement = 0
The bowling pin would be in free fall i.e. a = 9.8 m/s²
Use the second equation of motion:
s = ut + 0.5at²
0 = (9.20)t-0.5(9.8)(t²)
9.20 = 4.9 t
⇒t = 1.87 s
Thus, the total time of flight, the time elapses before the bowling pin falls in juggler's hand is 1.87 s.
A juggler throws a bowling pin straight up with an initial speed, the time that elapses before the pin reaches the juggler's hands is 1.88 s.
Given:
Initial speed, u = 9.2 m/s
The time can be calculated from the second equation of motion. The second equation of motion provides a relation between height, initial speed, acceleration, and time respectively.
From the second equation of motion:
h = ut + at²
When the ball reaches the hands, the distance becomes zero. Therefore, the time is:
0 = 9.2t -0.5 × 9.8t²
9.8t = 18.4
t = 18.4÷ 9.8
t = 1.88 s
Hence, the time that elapses before the pin reaches the juggler's hands is 1.88 s.
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Answers
That's what was so baffling about it before the particle nature of light
was suspected ... a match with a blue flame might stimulate the
photoelectric effect, but a high-power red searchlight couldn't do it.
Answer: intensity
Explanation: