Which particles are equal in number for an atom with a neutral charge? ​

Answers

Answer 1
Answer: electrons and protons

Related Questions

What energy transfer happens when wood is burning?
A student pipets 5.00 mL of a 5.103 M aqueous NaOH solution into a 250.00 mL volumetric flask and dilutes up to the mark with distilled water. What is the final molarity of the dilute solution?
Complete combustion of 4.20 g of a hydrocarbon produced 12.9 g of CO2 and 6.15 g of H2O. What is the empirical formula for the hydrocarbon?
Soil is an essential component of the earth's crust. It enabled life to exist andprovides the services necessary for human survival. What is the effect of soilerosion? What will you do to protect the community?​
Identify the catalyst-containing systems below as homogeneous or heterogeneous. Catalysts (4 items) (Drag and drop into the appropriate area below) NO(g) for the oxidation of SO2(g) to SO3(g)KI(aq) for the decomposition of H2O2(aq)H2(g) bonded to a metal surfacePd(s) coating that converts noxious gas to less harmful gases

The theoretical yield for CuCO3.Cu(OH)2+2h2SO4 ®2CuSO4+2H2O+3CO2

Answers

Answer:

bxnhdjxjdjvxjsj sbdhhxhchdbd

Chemistry work here. Please help as soon as possible. I have allot of questions that needs to be answered. Can someone do it for me?

Answers

Answer:

I dont know about the yield but I think mno2 is the limiting reactant

Which step would help a student find the molecular formula of a compound from the empirical formula? Multiply the subscripts of the empirical formula by the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound. Subtract the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound from the subscripts of the empirical formula. Divide the subscripts of the empirical formula by the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound. Add the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound to the subscripts of the empirical formula..

Answers

Answer:

Multiply the subscripts of the empirical formula by the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound.

Explanation:

got it right on edge 2020 :)

Answer:

Multiply the subscripts of the empirical formula by the value of the ratio of the molar mass of the compound to the empirical molar mass of the compound.

Explanation:

In chemical reactions, what does the law of conservation of mass mean?Group of answer choices

Matter is not created nor destroyed.

The total mass of the products is greater than the total mass of the reactants.

The total mass of the reactants is less that the total mass of the products.

Matter is not changed.

Answers

Answer

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

Which species is a conjugate acid of OH-?

Answers

It seems that you have missed the necessary options for this answer, but anyway, the answer for this would be H20. The specie that is a conjugate acid of OH- is H20. H20 is the conjugate acid and OH- is the conjugate base. Hope this answers your question. Have a great day!

Answer:

Water.

Explanation:

Hello,

In this case, you are referring to the dissociation or formation of water at the equilibrium, that is:

H^++OH^-<-->H_2O

In such a way, the water is the conjugate acid of the hydroxile ion as long as it  gains a proton.

Best regards.

Consider the following unbalanced equation for the combustion of hexane: αC6H14(g)+βO2(g)→γCO2(g)+δH2O(g) Part A Balance the equation. Give your answer as an ordered set of numbers α, β, γ, ... Use the least possible integers for the coefficients. α α , β, γ, δ = nothing Request Answer Part B Determine how many moles of O2 are required to react completely with 5.6 moles C6H14. Express your answer using two significant figures. n n = nothing mol Request Answer Provide Feedback

Answers

Answer:

2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O

α =2

β = 19

γ = 12

δ = 14

53.2moles of O₂

Explanation:

Proper equation of the reaction:

                    αC₆H₁₄ + βO₂ → γCO₂ + δH₂O

This is a combustion reaction for a hydrocarbon. For the combustion of a hydrocarbon, the combustion equation is given below:

         CₓHₙ + (x + (n)/(4))O₂ → xCO₂ + (n)/(2)H₂O

From the given combustion equation, x = 6 and n = 14

Therefore:

β = x + (n)/(4) = 6 + (14)/(4) = 6 + 3.5 = 9(1)/(2)

γ = 6

δ = (n)/(2) = (14)/(2) = 7

The complete reaction equation is therefore given as:

                   C₆H₁₄ + 9(1)/(2)O₂ → 6CO₂ + 7H₂O

To express as whole number integers, we multiply the coefficients through by 2:

                  2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O

Problem 2

           From the reaction:

2 moles of hexane are required to completely react with 19 moles of O₂

∴ 5.6 moles of hexane would react with k moles of O₂

This gives:     5.6 x 19 = 2k

                        k = (5.6 x 19)/(2)

                        k = 53.2moles of O₂