Compared to H2S, the higher boiling point of H2O is due to the1.
greater molecular size of water
2.
stronger hydrogen bonding in water
3.
higher molarity of water
4.
larger gram-formula mass of water
Answers
has higher boiling point than
, as there has been stronger hydrogen bonding in
. Thus, option 2 is correct.
The boiling point has been the temperature at which the liquid has been converted to the gaseous form. The boiling point has been based on the intemolecular attractions between the atoms.
Higher boiling point
Based on the intermolecular interactions, the compound with higher intermolecular force required more energy to break the bond and change the state, and thus have high boiling point.
The hydrogen sulfide and water has hydrogen bonding. The hydrogen bonding has been based on the electronegativity of the atom involved. The more electronegative atom, stronger will be hydrogen bonding and thereby higher boiling point.
In and
, the oxygen has been more electronegative than sulfur and thus results in stronger hydrogen bonding.
Thus, has higher boiling point than
, as there has been stronger hydrogen bonding in
. Thus, option 2 is correct.
Learn more about boiling point here:
Answer:
2, stronger hydrogen bonding
Explanation:
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out of barium, chlorine, iodine, and strontium which atom has the strongest attraction for electrons in a bond formation?
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b. in each electron shell
c. the outer electron shell
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Answers
Valence electrons occur in the outermost shells of an atom.
>> Valence electrons are electrons that are associated with an atom, and that can participate in the formation of a chemical bond.
Answers
To determine whether a chemical formula represents a compound or element that will not combust, you need to consider the elements present in the formula and their respective properties.
How we can determine combustibility?
First, check if the formula contains only one type of element. If it does, then it represents an element, and the question of whether it will combust or not is irrelevant, as elements do not combust.
If the formula contains two or more different elements, then it represents a compound. To determine if the compound will combust, you need to look at the properties of its constituent elements.
Some elements, such as noble gases (e.g., helium, neon, argon), have very low reactivity and are unlikely to combust under normal conditions. Therefore, if the compound contains only noble gases, it is unlikely to combust.
Other elements, such as metals, are more reactive and can combust under certain conditions, such as exposure to heat or oxygen. Therefore, if the compound contains a metal, you need to check the reactivity of that metal to determine if the compound will combust.
Similarly, non-metals can also be combustible under certain conditions, such as exposure to heat or other reactive substances. Therefore, if the compound contains a non-metal, you need to check the reactivity of that non-metal to determine if the compound will combust.
Overall, to determine if a compound or element will combust, you need to consider the properties of its constituent elements and any external conditions that may affect its reactivity.
Find more on combustible gases:
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Answers
N2 +3 I2 = 2NI3
We are given the amount of product formed. This will be the starting point of our calculations.
3.58 g NI3 ( 1 mol NI3 / 394.71 g NI3 ) ( 3 mol I2 / 2 mol NI3 ) = 0.014 mol I2.
Thus, 0.014 mol of I2 is needed to form the given amount of NI3.
Answer:
Answer is 0.0136.
Explanation:
Pb + Cu(CIO), → Pb(ClO3)2 + Cu
Answers
Answer:
No.
Explanation:
Pb (lead) is higher on the activity series than Cu (copper). Since Cu is lower, no reaction forms.
Answers
C + 2Cl2 ➡️ CCl4
I decided this because I believe this is the only way you could make this a balanced equation. To be a balanced equation Both sides of the equation has the same number of atoms for each element. Carbon has 1 atom and chlorine has 4.
False