MATHEMATICS COLLEGE

What is the best description of the relation in Item 2? a function that is one-to-one a function that is many-to-one a function that is one-to-many a relation that is not a function​

Answers

Answer 1
Answer:

Answer:

One input(x-value) can only have one output(y-value) in order to be a function.

Step-by-step explanation:
Answer 2
Answer:

Final answer:

One-to-one functions yield unique outputs for each input. Many-to-one functions can yield the same output for different inputs. The term one-to-many does not typically apply to functions, and a relation is not a function if one input yields multiple outputs. To answer the question specifically about Item 2, additional information or a visual representation is needed.

Explanation:

To determine the type of a function or relation, we need to understand what it means for a function to be one-to-one, many-to-one, one-to-many, or not a function.

A function is one-to-one (also known as injective) if every element of the range corresponds with exactly one element of the domain. In simpler terms, no two different inputs (x-values) yield the same output (y-values).

A function is many-to-one if there are at least two elements in the domain associated with the same value in the range. This means, two or more different inputs (x-values) can yield the same output (y-value).

The term one-to-many typically does not apply to functions in the strictest mathematical sense. Functions by definition associate one, and only one output with each input.

Lastly, a relation is not a function if at least one element in the domain is associated with more than one value in the range. That is, there is atleast one input (x-value) that yields more than one output (y-value).

Without further specific information or visual representation (like a graph) of Item 2, it's difficult to definitively state what type of relation or function it is.

Learn more about Types of Functions here:

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A welding drawing shows that the​ weld-root reinforcement cannot exceed ​" in thickness. Your weld measurement tools are​ metric, so this value needs to be converted to millimeters. You know that one inch equals 2.54 centimeters. What is the maximum​ weld-root reinforcement allowed in​ millimeters? Round your answer to the nearest tenth of a millimeter.

Answers

Answer:

3.2 millimeters

Step-by-step explanation:

1/8*2.54 *10 = 3.175

= 3.2 millimeter. (rounded to nearest tenth)

Final answer:

To convert the thickness from inches to millimeters, the given value (in inches) should be multiplied by 25.4 and the result rounded to the nearest tenth of a millimeter.

Explanation:

The subject of this question is a conversion of units from inches to millimeters. In such conversions, one of the basic knowledge is that 1 inch is equivalent to 2.54 centimeters (cm). However, in this case, we need the answer in millimeters (mm), not cm. Keep in the back of your mind that 1 centimeter (cm) is equal to 10 millimeters (mm). This means, 1 inch will be equivalent to 2.54 cm, which further converts to 25.4 mm.

To find out the maximum value of weld-root reinforcement in millimeters, we simply need to apply the conversion factors. To convert the given thickness in inches to millimeters, you multiply the given value (in inches) by 25.4. Round your answer to the nearest tenth of a millimeter.

Learn more about Unit Conversion here:

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IfGeometry SOHCAHTOA

Answers

In geometry, sohcahtoa is an easy way to remember what sine, cos and tan stand for



Soh is sine, which is equal to opposite over hpotenuse


Cah is cos which is equal to adjacent over hypotenuse


Toa is tan which is equal to opposite over adjacent

A study published in 1993 found that babies born at different times of the year may develop the ability to crawl at different ages! The author of the study suggested that these differences may be related to the temperature at the time the infant is 6 months old. (Benson and Janette, Infant Behavior and Development [1993]. The study found that 32 babies born in January crawled at an average age of 29.84 weeks, with a standard deviation of 7.08 weeks. Among 21 July babies, crawling ages averaged 33.64 weeks, with a standard deviation of 6.91 weeks. Is this difference significant?

Answers

Answer:

t=\frac{(29.84-33.64)-0}{\sqrt{(7.08^2)/(32)+(6.91^2)/(21)}}}=-1.939  

p_v =2*P(t_(51)<-1.939)=0.0580  

Comparing the p value with the significance assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the difference between the two groups is NOT significantly different at 1% of significance.  

Step-by-step explanation:

Data given

\bar X_(1)=29.84 represent the mean for sample January

\bar X_(2)=33.64 represent the mean for sample July

s_(1)=7.08 represent the sample standard deviation for 1  

s_(2)=6.91 represent the sample standard deviation for 2  

n_(1)=32 sample size for the group 2  

n_(2)=21 sample size for the group 2  

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:  

Null hypothesis:\mu_(1)-\mu_(2)=0  

Alternative hypothesis:\mu_(1) - \mu_(2)\neq 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_(1)-\bar X_(2))-\Delta}{\sqrt{(\sigma^2_(1))/(n_(1))+(\sigma^2_(2))/(n_(2))}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=32+21-2=51  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

t=\frac{(29.84-33.64)-0}{\sqrt{(7.08^2)/(32)+(6.91^2)/(21)}}}=-1.939  

P value  

Since is a bilateral test the p value would be:  

p_v =2*P(t_(51)<-1.939)=0.0580  

Comparing the p value with the significance assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the difference between the two groups is NOT significantly different at 1% of significance.  

Suppose you have 18 objects (10 of type A, 5 of type B, and 3 of type C). Objects of type A are indistinguishable from each other; objects of type B are indistinguishable from each other; and objects of type C are indistinguishable from each other. In how many ways can you Pick 5 of the 18 objects (order does not matter)

Answers

Answer:

\binom{18}{5}= 8568

Step-by-step explanation:

Note that we have in total 18 items. Even though we are given information regarding the amounts of items per type, the general question asks the total number of ways in which you can pick 5 out of the 18 objects, without any restriction on the type of chosen items. Therefore, the information regarding the type is unnecessary to solve the problem.

Recall that given n elements, the different ways of choosing k elements out of n is given by the binomial coefficient \binom{n}{k}).

Therefore, in this case the total number of ways is just \binom{18}{5}=8568

Answer:

Given:

Number of objects: n = 18

Type A objects: 10

Type B objects: 5

Type C objects: 3

To find:

In how many ways can you Pick 5 of the 18 objects (order does not matter)

Step-by-step explanation:

When the order does not matter we use Combination.

Formula to calculate combination:

C(n,r) = n! / r! ( n - r )!

n = 18

r = 5

Putting the values:

C(n,r)

= C(18,5)

= 18! / 5! ( 18 - 5 )!

= 18! / 5! ( 13 )!

= ( 18 * 17 * 16 * 15 * 14 * 13 * 12 * 11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 ) / ( 5 * 4 * 3 * 2 * 1 ) * (13 * 12 * 11 * 10 *9* 8 * 7 *6 * 5 * 4 * 3 * 2 *1 )

Cancel 13!

= (18 * 17 * 16 * 15 * 14 ) / ( 5 * 4 * 3 * 2 * 1 )

= 1028160 / 120

= 8568

So you can pick 5 of the 18 objects in 8568 ways.

Zoe is helping her grandmother freeze strawberries from the family garden. They have 20 pounds of strawberries to freeze. If they put 1.25 pounds of strawberries into each freezing container, how many containers will they fill?

Answers

Answer:

16

Step-by-step explanation:

1 Container = 1.25 Pounds

? Container = 20 Pounds

  • (Simple crisscross multiplication) 1x20Pounds = 20 = 16 Containers

1.25Pounds 1.25

|)) Which sign makes the statement true?
83.95% ? 83.95%
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=
Submit

Answers

Answer:  =

Step-by-step explanation:

83.95% is equal to 83.95% (look at it)

Answer:

=

Step-by-step explanation:

umm 83.95 = 83.95?
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