K20Molar Mass (g/mole)
2(39.10) + 16.00 = 94.20 g/mole
Moles
5.85 moles
Mass (grams)
Particles
K20 Molar Mass (g/mole) 2(39.10) + 16.00 = 94.20 g/mole - 1

Answers

Answer 1
Answer:

Answer:

yes

Explanation:

that is the answer


Related Questions

What occurs when there are oh ions in a solution
What is the three-dimensional shape of the molecule with this Lewis structure?
The complete combustion of ethanol, C₂H₅OH (FW = 46.0 g/mol), proceeds as follows: ; ΔH = −555 kJ What is the enthalpy change for combustion of 15.0 g of ethanol?
Select the correct scientific notation form of this numeral using only 2 significant figures. 5,489.6654
The force of attraction that the earth exerts on all objects is called

The conductors in electrical devices are commonly made of
a. iron.,B.nickel.,C.Cooper.,D.lead.

Answers

Copper - it is bendy can conduct very well and is running out

Answer:

Copper

Explanation:

What is the molarity (M) of a solution that contains .25 moles of a compound in 1.8 L of solution?

Answers

Answer:

The answer to your question is 0.14 M

Explanation:

Data

Molarity = ?

number of moles = 0.25

volume = 1.8 L

Formula

Molarity = (number of moles)/(volume)

Substitution

Molarity = (0.25)/(1.8)

Simplification and result

      Molarity = 0.14 M

Why does an ion have an electrical charge?

Answers

An ion has an electrical charge because it either has more electrons than protons or it has more protons than electrons. Electrons, which are found in the shells of an atom, have a negative charge, while protons, found in the atom's nucleus, have a positive charge.

For the amino acid alanine, the major species in solution at pH 7 is the zwitterionic form, which has a negatively charged carboxylic acid group and a positively charged amino group. There is a less common neutral form in which neither group is charged. The carboxylic acid group of alanine has a p K a of 3 . The amino group of alanine has a p K a of 8 . Estimate the ratio of the concentration of the neutral amino acid species to the zwitterionic species at pH 7 .

Answers

Answer: ratio is 10⁻⁵

Explanation:

From Acid-dissociation equilibrium constant, HA is given thus,

HA + H₂O  ⇄ H₃O⁺ + A⁻

equilibrium constant, Ka = [H₃O⁺] [A⁻] / [HA]

[H₃O⁺]  = Ka [HA] / [A⁻]

from this we have that

pH = -log[H₃O⁺]

and pKa = -logKa

Applying Henderson-Hassel bach equation;

pH = pKa + log  [A⁻]/[HA] ...........(1)

A⁻ rep the salt and HA rep the acid

at a given pH of 7, the pKa value of carboxylic acid COOH is 3

∴ from equation (1).

7 = 3 + log(COO⁻/COOH)

log(COO⁻/COOH) = 4

thus (COO⁻/COOH) = 10⁻⁴ ...................(2)

The ratio of alanine COOH to COO- at pH 7 is  (COO⁻/COOH) = 10⁻⁴

(ii) Also considering the ratio of alanine NH2 to NH3+ at pH 7  we have;

given Pka value is 8,

therefore pH = pKa + log [salt]/[base]

7 = 8 + log (NH₂/NH₃)

(NH₂/NH₃) = 10⁻¹

thus the ratio of the concentration of the neutral amino acid species to the zwitterionic species at pH 7 is;

10⁻⁴ ˣ 10⁻¹ = 10⁻⁵

cheers i hope this helps

Assume that 13.5 g solid aluminum (Al) react with HCl to produce solid aluminum chloride (AlCl3) salt and gaseous hydrogen (H2) at standard temperature and pressure.How many moles of Al react?

How many moles of H2 are produced?

How many liters of H2 are produced?

Answers

0.5 moles\bold {Al} is required for the given reaction to occur. Mole is a constant that represents a certain amount of particles such as atoms, ions, or molecules.

What is the Mole concept?

It is the number or constant that represents a certain amount of particles such as atoms, ions, or molecules.

1 mole = 6.02 * 10^2^3 particles.

n = \frac wm

Where,

n - number of moles

w - given mass = 13.5 g.

m - molar mass = 26.98 g/mol.

Put the values in the formula,

n = \frac {13.5} {26.98}\n\nn = 0.5\rm \ mol.

Therefore, 0.5 moles \bold {Al} is required for the given reaction to occur.

Learn more about Mole concept:

brainly.com/question/7287712

Answer:

1) 0.5 mol.

2) 0.75 mol.

3) 16.8 L.

Explanation:

1) How many moles of Al react?

  • We can calculate the number of moles of Al (n) using the relation:

n = mass / molar mass,

Mass of Al = 13.5 g.

Molar mass mass of Al = 26.98 g/mol.

∴ The number of moles of Al (n) = mass / molar mass = (13.5 g) / (26.98 g/mol) = 0.5 mol.


2) How many moles of H₂ are produced?

  • It is a stichiometry problem.
  • We should write the balanced equation of the reaction:

2Al + 6HCl → 2AlCl₃ + 3H₂.

  • It is clear that 2.0 moles of Al reacts with 6.0 moles of HCl to produce 2.0 moles of AlCl₃ and 3.0 moles of H₂.

Using the cross multiplication:

2.0 moles of Al → 3.0 moles of H₂, from the stichiometry,

0.5 mole of Al → ??? moles of H₂.

∴ The number of moles of H₂ are produced = (0.5 mole)(3.0 mole) / (2.0 mole) = 0.75 mol.


3) How many liters of H₂ are produced?

It is known that at STP, 1.0 mole of any gas occupies a volume of 22.4 L.

Using cross multiplication:

1.0 mole occupies → 22.4 L.

0.75 mole occupies → ??? L.

∴The number of liters of H₂ are produced = (0.75 mole)(22.4 L) / (1.0 mole) = 16.8 L.

Copper metal (Cu) reacts with silver nitrate (AgNO3) in aqueous solution to form Ag and Cu(NO3)2. An excess of AgNO3 is present. The balanced chemical equation is shown below.Cu + 2AgNO3 ---> Cu(NO3)2 + 2Ag

The molar mass of Cu is 63.5 g/mol. The molar mass of Ag is 107.9 g/mol. What mass, in grams, of Ag is produced from reaction of 31.75 g of Cu?

26.95
107.9
215.91
431.82

Answers



we are given the reaction Cu + 2AgNO3 ---> Cu(NO3)2 + 2Ag. This means for every mole Cu used, there are 2 moles of Ag produced. In this case, given 31.75 g Cu, converting to moles through molar mass and using stoichiometric ratio and the molar mass of Ag, the mass Ag produced is 107.9 grams. 

The mass in grams of Ag produced from reaction of 31.75g of Cu is 107.9 grams

calculation

Cu+2AgNO3 ---> Cu(NO3)2 + 2Ag

find the moles of Cu that reacted

moles= mass/molar mass

=31.75 g/63.5 g/mol= 0.5 moles

from the equation above the mole ratio of CU:Ag is 1:2 therefore the moles of Ag=0.5 moles x2 = 1 mole

mass of Ag= moles of Ag x molar mass

= 1 mole x107.9g/mol = 107.9 grams