CHEMISTRY COLLEGE

HELP!!!!!!
I DON'T KNOW THE ORDER!!

Answers

Answer 1

Answer:

Answer:

for 1 solid its freezing.

for 2 solid and liquid its melting

for 6 liquid to gas its evaporation and for 5 gas to liquid its condensation.

Explanation:

hope this helped :)

Answer 2

Answer:

Answer:

solid->liquid= melting

liquid->solid= freezing

gas->liquid= consendation

liquid->gas= evaporation

Related Questions

The partial pressure of O2 in air at sea level is 0.21atm. The solubility of O2 in water at 20∘C, with 1 atm O2 pressure is 1.38×10−3 M. Part A Using Henry's law, calculate the molar concentration of O2 in the surface water of a mountain lake saturated with air at 20 ∘C and an atmospheric pressure of 665 torr . Express your answer using two significant figures. nothing
Does the molarity of the solution change with the change in temperature?Match the words in the left column to the appropriate blanks in the sentences on the right.
2Identify at least two factors which influenceperiodic poperties of elements in groupsand periods
How many molecules are shown in the chemical formula pictured? H3PO4A) 1B) 3C) 4D) 7
The specific spatial arrangement of amino acid residues that are close to each other in the polypeptide chain is called______the structure of a protein.a. primary.b. secondary.c. tertiary.d. quaternary .

What is the question mark

Answers

It is likely asking you to determine the coefficient on the chemical and balance the equation.

Describe how you would make 250 ml of a 3 M solution of sodium acetate (NaOAc = 82.03 g/mol). First figure out how much sodium acetate you would need, then describe how you would make the solution if you were given a bottle of solid sodium acetate, a volumetric flask, and DI water.

Answers

Answer:

You need to do the following conversion to pass from 3M in 250 mL to g of sodium acetate

$3 M (mol/L)*(1L/1000 mL)*(250 mL)*(82.03 g/1 mol)=61.52 g$

Explanation:

First, you need to dissolve 61.52 g of solid sodium acetate (MW 82.03 g/mol) in 200 ml of DI water. Then, using a volumetric flask add water to bring the total volume of the solution to 250 mL.

How many joules of heat energy are absorbed when 80.0 g of water are heated from 10.0°C to 50.0°C? *

Answers

Answer:

13440 J

Explanation:

c ≈ 4200 J / (kg * °C)

m = 80 g = 0,08 kg

$t_(1)$ = 10 °C

$t_(2)$ = 50 °C

The formula is: Q = c * m * ( $t_(2) - t_(1)$ )

Calculating:

Q = 4200 * 0,08 * (50 - 10) = 13440 (J)

Write Lewis structural formulas for the following molecules: NH3 SO2
CH3OH HNO2
N2 CH2O

Answers

Answer : The Lewis-dot structure of the following molecules are shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

(1) The given molecule is, $NH_3$

As we know that hydrogen has '1' valence electron, nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in $NH_3$ = 5 + 3(1) = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

(2) The given molecule is, $SO_2$

As we know that sulfur and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in $SO_2$ = 6 + 2(6) = 18

According to Lewis-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.

(3) The given molecule is, $CH_3OH$

As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in $CH_3OH$ = 4 + 4(1) + 6 = 14

According to Lewis-dot structure, there are 10 number of bonding electrons and 4 number of non-bonding electrons.

(4) The given molecule is, $HNO_2$

As we know that hydrogen has '1' valence electron, nitrogen has '5' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in $HNO_2$ = 1 + 5 + 2(6) = 18

According to Lewis-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.

(5) The given molecule is, $N_2$

As we know that nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in $N_2$ = 2(5) = 10

According to Lewis-dot structure, there are 6 number of bonding electrons and 4 number of non-bonding electrons.

(6) The given molecule is, $CH_2O$

As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in $CH_2O$ = 4 + 2(1) + 6 = 12

According to Lewis-dot structure, there are 8 number of bonding electrons and 4 number of non-bonding electrons.

How do test with crash dummies, seat belts, and air bags illustrate newton's first law of motion??

Answers

Answer:

Newton’s law of inertia is illustrated in tests with crash dummies, seat belts, and airbags, wherein the object stays in motion unless there is an unbalanced force applied to it.

Inertia is the main reason why there are seatbelts and airbags in the car. In this case, when the seatbelt is trapped to the passenger, the passenger experiences the same state of motion as the car. If the car accelerates/decelerates, the passenger experiences it too. When the car experiences collision, an unbalance force is acted upon it. This causes the car to stop abruptly, and the passenger shares the same state of motion because of the seatbelt and the airbags that apply the unbalanced force to stop the passenger to go forward.

Practice the Skill 21.15b When the following ketone is treated with aqueous sodium hydroxide, the aldol product is obtained in poor yields. In these cases, special distillation techniques are used to increase the yield of aldol product. Predict the aldol addition product that is obtained, and propose a mechanism for its formation. For the mechanism, draw the curved arrows as needed. Include lone pairs and charges in your answer. Do not draw out any hydrogen explicitly in your products. Do not use abbreviations such as Me or Ph.