PHYSICS HIGH SCHOOL

An 8-N force is applied to a 2-kg box to accelerate it to the right across a table. The boxencounters a force of friction of 5 N. What is the acceleration of the object?
(1 Point)
4 m/s2
2.5 m/s2
1.5 m/s2
1 m/s2

Answers

Answer 1

Answer:

Answer:

1.5

Explanation:

resultant force=8-5=3N

using f=ma

a=f/m

=3/2

=1.5

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Two objects are traveling on the same track. for 10 s, object x has an average acceleration of 3.0 m/s/s. if object y has an initial velocity of 0 m/s and a final velocity of 25 m/s after 10 s, how does it acceleration compared to object x's?

Answers

Final answer:

The acceleration of object Y is 2.5 m/s/s which is less than the acceleration of object X which is 3.0 m/s/s.

Explanation:

The acceleration of an object is calculated using the formula: a = (v_f -v_i) / t, where v_f is the final velocity, v_i is the initial velocity and t is time. For object Y, the final velocity is 25m/s, the initial velocity is 0m/s and the time is 10s, hence its acceleration will be (25-0)/10 = 2.5 m/s/s. This indicates that Object Y's acceleration is less compared to Object X's acceleration of 3.0 m/s/s.

Learn more about Acceleration here:

brainly.com/question/12550364

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v=at
v=10a
25/10=a
2.5=a

object x accelerates 0.5m/s faster than object y

What can be known about the density of sodiumhydroxide?
A. It will be 2.54 g/cm².
B. It will be different from the other chemicals.
C. It will be 1.67 g/cm3.
D. It will be the same as the other reactant.

Answers

d? maybe i’m trying to. see if it’s d or b

It’s D. It will be the same as the other reactant

FASTA ball has 116.62 J of gravitational potential energy at a height of 85 m. What is the mass of the ball?

a.0.14 kg
b.0.37 kg
c.11.9 kg
d.21.82 kg

Answers

Answer:

a)0,14 kg

Explanation:

Formula to calculate the gravitational potential energy:

U= m *g*h : equation (1)

U: It's gravitational potential energy in Joules (J)

m: body mass in kilograms (kg)

g= the acceleration of gravity ( $m/s^(2)$ )

h= the body heigt measured from the floor (m)

Known information:

U= 116.62 J

g = 9.8 $m/s^(2)$

h =85m

mass calculation:

We replace the known information in equation 1 :

116.62 = m*9.8*85

m =116.62/(9.8*85)

m= 0,14 kg

The mass of the ball is 0,14 kg

The answer is a. 0.14 kg

PE = mgh
116.62 = m•(9.8)•(85)
m = 116.62/(9.8•85)
= 0.14 kg

The temperature of a sample of water increases from 20°c to 46.6°c as it absorbs 5650 calories of heat what is the mass of the sample?

Answers

M=energy transferred/ (temperature change*specific heat) M= 5650/(26.6*1.0) M=212g

Kendall has an empty graduated cylinder with markings and an identical graduated cylinder partway filled with water. She also has a balance and a marble.Which statement best describes what Kendall can do?

She can measure the volume and mass of the marble, the volume and mass of the water, and the volume and mass of the graduated cylinder.
She can measure the volume and mass of the marble, the volume and mass of the water, and the mass of the graduated cylinder.
She can measure the volume of the marble and water, and the mass of the graduated cylinder.
She can measure the mass of the marble and water, and the volume of the graduated cylinder.

Answers

Answer:

Its B. She can measure the volume and mass of the marble, the volume and mass of the water, and the mass of the graduated cylinder.

Explanation:

I just did it

Answer:

The awnser is actually B.

Explanation:

She can measure the mass of the water, marble and the graduated cylinder with the balance.

The volume of the water can be shown on the marked graduated cylinder, the volume of the marble can be measured by the volume difference of the water before and after the marble is put in.

An experiment is set up to measure the effect of a gasoline additive on fuel consumption rate (miles per gallon, or MPG). What would be the control in this experiment?