Brain dead someone help ​
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Answer 1
Answer:

Answer:

cant see it

Step-by-step explanation:

can you flip it pls


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Caleb's mother said they will drive 1 /4 hour to get there, and they will drive another 1 /4 hour back. Once they arrive, Caleb's brother will be playing in 3 soccer games. Each soccer game takes 3 4 hour, and there is no break in between games. Calculate how long will they be away from home.

Answers

Answer: They are away for 2(3)/(4)\ hours from home.

Step-by-step explanation:

Since we have given that

Time to get there = (1)/(4)

Time to get back = (1)/(4)

Number of soccer games = 3

Time for each soccer games = (3)/(4)

So, total time for 3 games would be

3* (3)/(4)=(9)/(4)

So, the time for which they will be away from home is given by

(1)/(4)+(9)/(4)+\frac{1}4}=(1+9+1)/(4)=(11)/(4)=2(3)/(4)\ hours

Hence, they are away for 2(3)/(4)\ hours from home.

N E V E R M I N D...........

Answers

Answer:

ok

Step-by-step explanation:

Use the four functions below for this question:f(x)
g(x)
h(x)
j(x)
Jesse got $5 from his dad and he makes $2 each time he walks the neighbor's dog.
x
g(x)
–2
–1
2
–9
6
–17
a line going through the point (0, 5) and the point (3, negative 1)
j(x) = 2x – 5
Compare and contrast these four functions using complete sentences. Focus on the slope and y-intercept first, and then on any additional properties of each function.

Answers

From analyzing the information presented we can see that the diagram presents four different ways to express a function verbally, numerically, graphically and algebraically. Please view the attachment where you can observe all four functions for this question.


I hope this helps, Regards.

Show your work !

Thanks

Answers

For 1st. 
you can solve it by general law or , 
since the coefficient of r^2 = 1 
so u should think of 2 number which if u multiple them gives you 27 and sum of them is 12 and those numbers are 9 , 3 
so the answer (x+9)*(x+3) 
2nd problem :
g^2 - 9 = (g-3)*(g+3) 
3rd problem:
2p^3 + 6p^2 + 3p +9 
1st divide it into two parts 
(2p^3 +6p^2)+    (3p+9)
from the 1st part 
take 2p^2 as a common factor and from part 2 take 3 as a common factor and the equation be like 
2p^2(p+3)  + 3(p+3)
then take (p+3) as a common factor
so (p+3)* ( 2p^2 +3 )                                                         
1: (r+3)(r+9). 2: (g+3)(g-2). 3: (2p^2+3)(p+3). FOIL multiply the first, inside, outside, and last terms. add the inside and outside terms together. :)

For f(x) = 3x +1 and g(x) = x2 – 6, find (f- g)(x).

Answers

Answer:

\boxed{\sf (f-g)(x) = -{x}^(2)  + 3x + 7}

Given:

\sf f(x) = 3x + 1 \n \sf g(x) =  {x}^(2)  - 6

To find:

\sf (f - g)(x) = f(x) - g(x)

Step-by-step explanation:

\sf \implies(f - g)x = f(x) - g(x) \n  \n \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = (3x + 1) - ( {x}^(2)  - 6) \n  \n \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = (3x + 1)  + (-  {x}^(2)  + 6) \n  \n \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = 3x + 1 -  {x}^(2)  + 6 \n  \n \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = - {x}^(2)  + 3x + 1 + 6 \n  \n \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    =  -{x}^(2)  + 3x + 7

Factor this expression completely. 8r6 + 27s12

Answers

The factor of the expression 8r⁶ + 27s¹² can be (2r²+3s⁴)(4r⁴-6r²s⁴+9s⁸) after using the identity a³+b³ = (a+b)(a²-ab+b²).

What is an expression?

It is defined as the combination of constants and variables with mathematical operators.

It is given that:

= 8r⁶ + 27s¹²

The above expression can be written as:

8r⁶ + 27s¹² = (2r²)³+(3s⁴)³

After applying the identity:

a³+b³ = (a+b)(a²-ab+b²)

= (2r²+3s⁴)(4r⁴-6r²s⁴+9s⁸)

Thus, the factor of the expression 8r⁶ + 27s¹² can be (2r²+3s⁴)(4r⁴-6r²s⁴+9s⁸) after using the identity a³+b³ = (a+b)(a²-ab+b²).

Learn more about the expression here:

brainly.com/question/14083225

#SPJ5

Answer:

a^3+b^3=(a+b)(a²-ab+b²)

8r^6+27s^12=(2r²)^3+(3s^4)^3=(2r²+3s^4)(4r^4-6r²*s^4+9s^8)

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