Express 0.00419 in standard form

Answers

Answer 1
Answer: the standard form is 4.19•10^-3

Related Questions

Which ordered pair is a solution of the equation y = 5x? (–2, 10) (–5, 25) (–3, 15) (–2, –10)
Can someone help please? asap.
What's the answer 2795÷43
Write the equation in function form4x + y = -10 (I have 11 more of these other kinds of questions) :(
Solve for p. -5 (p + 3/5)= -4 the answer should be a proper or improper fraction

Everett shoveled 31,798 ounces of gravel from a pile to his driveway. How many tons is this?​

Answers

0.994 us tons is the answer

0.994 should be your answer my friend

What is the combined version of the equations 5.2*10^6 and 2.47*10^8

Answers

Answer:To solve the system of equations using substitution, we'll start by solving one equation for one variable, and then substitute that expression into the other equation.

Let's solve the second equation, y = 3x - 7, for y:

y = 3x - 7 (Equation 2)

Now, we can substitute this expression for y in the first equation, 2x + y = 3:

2x + (3x - 7) = 3

Combining like terms, we have:

5x - 7 = 3

Adding 7 to both sides of the equation, we get:

5x = 10

Dividing both sides of the equation by 5, we have:

x = 2

Now that we have the value of x, we can substitute it back into one of the original equations to find the value of y. Let's use Equation 2:

y = 3x - 7

Substituting x = 2, we have:

y = 3(2) - 7

Simplifying the expression, we get:

y = 6 - 7

y = -1

Therefore, the solution to the system of equations is x = 2 and y = -1.

We can also check this solution by substituting the values of x and y back into both original equations to make sure they satisfy both equations.

A pooling equilibrium exists as long as the number of Type H customers in the market is relatively low.

True or False

A pooling equilibrium exists as long as the number of Type H customers in the market is relatively high.

True or False

Brainly Ginny character avatar

AI-generated answer

A pooling equilibrium exists when all customers, regardless of their type, are offered the same product or service. In a pooling equilibrium, the market does not differentiate between different customer types.

Given the statement "A pooling equilibrium exists as long as the number of Type H customers in the market is relatively low," we can analyze its truthfulness:

If the number of Type H customers in the market is relatively low, it means that there are fewer customers of Type H compared to other types. In this scenario, it is more likely that the market will offer a single product or service that caters to the majority of customers, including non-Type H customers. Therefore, it is true that a pooling equilibrium is more likely to exist when the number of Type H customers is relatively low.

On the other hand, if the number of Type H customers in the market is relatively high, it means that there is a significant presence of Type H customers. In this case, the market might be inclined to offer specialized products or services that specifically cater to the needs and preferences of Type H customers. This would result in a segmentation or differentiation of the market, which contradicts the concept of a pooling equilibrium. Therefore, it is false to say that a pooling equilibrium exists when the number of Type H customers is relatively high.

To summarize:

- A pooling equilibrium is more likely to exist when the number of Type H customers in the market is relatively low. (True)

- A pooling equilibrium is less likely to exist when the number of Type H customers in the market is relatively high. (False)

what is the combined version of the equations 5.2*10^6 and 2.47*10^8

Brainly Ginny character avatar

AI-generated answer

To find the combined version of the given equations 5.2*10^6 and 2.47*10^8, we need to add or subtract the numbers and keep the same power of 10.

The numbers in scientific notation have two parts: the coefficient and the power of 10. In this case, we have:

5.2 * 10^6 and 2.47 * 10^8

To combine them, we need to make sure that the powers of 10 are the same. We can do this by adjusting the coefficients.

First, let's adjust the coefficient of 5.2*10^6. We can do this by multiplying it by 10^2:

5.2 * 10^6 * 10^2 = 5.2 * 10^(6+2) = 5.2 * 10^8

Now that we have adjusted the coefficient of 5.2*10^6, we can combine it with 2.47*10^8:

5.2 * 10^8 + 2.47 * 10^8 = (5.2 + 2.47) * 10^8 = 7.67 * 10^8

Therefore, the combined version of the equations 5.2*10^6 and 2.47*10^8 is 7.67*10^8.

6x - 5y= 0 and x - 5y= -25

Answers

This is a simultaneous question that can be solved with elimination.

6x - 5y = 0 ——(1)
x - 5y = -25 ——(2)

(1) - (2):
6x - 5y - (x - 5y) = 0 - (-25)
6x - 5y - x + 5y = 0 + 25
5x = 25
x = 5

Sub x = 5 into (2):
5 - 5y = -25
-5y = -30
y = 6

Hope this helps

Divide: x^10/x^4. thank you very much

Answers

Simple,

you have ( x^(10) )/( x^(4) )

This really means that you have...

(x*x*x*x*x*x*x*x*x*x)/(x*x*x*x)

just cancel out the x's that you have, it's simple...

leaving you x^(6)

Thus, your answer.

During the 2017 Major League Baseball season the Cleveland Indians played 162 games. They won 42 games more than they lost. What was the team's win-loss record that year?

Answers

Answer: The team's win-loss record that year is 1.7

Step-by-step explanation:

During the 2017 Major League Baseball season the Cleveland Indians played 162 games.

Let x = the number of games that the

Cleveland Indians lost during the 2017 Major League Baseball season.

This means that the number of games that the Cleveland Indians won during the 2017 Major League Baseball season would be x + 42.

Total number of games played = sum of games won + sum of games lost. This is expressed as

162 = x + 42 + x

2x + 42 = 162

2x = 162-42 = 120

x = 120/2 = 60

Number of games that the Cleveland Indians lost during the 2017 Major League Baseball season is 60

The number of games that the Cleveland Indians won during the 2017 Major League Baseball season is 60 + 42 = 102

The team's win-loss record that year

would be wins/loses

= 102/60 = 1.7

Write an equation of the line that passes through (4, –3) and is perpendicular to the graph of y=3/7x-5

Answers

Answer:

Parallel lines have the same slope, so any line parallel to y = 7x - 3 will have slope 7. If your y intercept is 5, the line must go through (0,5), giving you y = 7x + 5.

Step-by-step explanation: