CHEMISTRY HIGH SCHOOL

A + c = r solve for a

Answers

Answer 1

Answer:

Answer: A = -c + r

Explanation:

Answer 2

Answer:

Answer:

a = r-c. its that simple I guess

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Which of these elements has an electron configuration of [Kr]5s2?barium

calcium

rubidium

strontium

Answers

Given this abbreviated electron configuration, we begin from the row of the periodic table that contains Krypton (Kr). Then since the remaining electrons are 5s2 (which indicates 2 electrons in the 5s orbital), we check the next row (the 5th row) and find the 2nd element, which would contain two electrons. The first element is rubidium, while the second is strontium, so this means that Sr is the final answer.

The element which has an electron configuration of [Kr] 5s² is calcium .

It is defined as a substance which cannot be broken down further into any other substance. Each element is made up of its own type of atom. Due to this reason all elements are different from one another.

Elements can be classified as metals and non-metals. Metals are shiny and conduct electricity and are all solids at room temperature except mercury. Non-metals do not conduct electricity and are mostly gases at room temperature except carbon and sulfur.

The number of protons in the nucleus is the defining property of an element and is related to the atomic number.All atoms with sameatomic numberare atoms of same element.

Learn more about element,here:

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What is the correct molar mass for the compound CaBr3

Answers

CaBr₃ = 40 + 80 * 3 = 280 g/mol

hope this helps!

methane and hydrogen sulfide form when hydrogen reacts with carbon disulfide. identify the excess reactant and calculate how much remains after 36 L o fH2 reacts with 12 L of CS2 all at STP

Answers

At STP, 1 mol of gas occupies 22.4 L of volume. Using this conversion we the starting amounts of the reactants:
1.6071 mol H2
.5357 mol CS2
The balanced equation is:
4H2 + CS2 -> CH4 + 2H2S
This means that 4 moles of H2 reacts with 1 mole of CS2.
Multiplying this ratio with each of the amounts of the reactants:
required CS2 based on amount of H2 = 0.4018 mol CS2
required H2 based on amount of CS2 = 2.1428 mol H2
Therefore, the excess reactant is CS2. To calculate how much is left, we simply subtract the amount of the reactant CS2 with the required amount based on the amount of H2:
0.5357 mol - 0.4018 mol = 0.1339 mol

How many moles of chlorine, cl, are there in 8 moles of carbon tetrachloride, ccl4?

Answers

Moles are the amount of substance

the break down of CCl₄ is as follows

CCl₄ --> C + 4 Cl

in the compound CCl₄ - 1 mol of CCl₄ contains 4 mol of Cl

so for every 1 mol of CCl₄ there are 4 mol of Cl

then in 8 mol of CCl₄ - there are 4 x 8 = 32 mol of Cl

so 8 mol of CCl₄ contains 32 mol of Cl

answer is 32 mol of Cl

$\boxed{{\text{32 moles}}}$ of chlorine are present in 8 moles of ${\text{CC}}{{\text{1}}_{\text{4}}}$ .

Further Explanation:

Mole is a measure of the amount of substance. It is defined as the mass of a substance that has the same number of fundamental units as there are atoms in 12 g of carbon-12. Such fundamental units can be atoms, molecules or formula units.

In ${\text{CC}}{{\text{l}}_4}$ , both carbon and chlorine are non-metals. Carbon has four valence electrons whereas chlorine has seven valence electrons. Both share two electrons with each other and a single covalent bond is formed between a carbon and a chlorine atom. So carbon forms four single bonds with four chlorine atoms in order to complete its octet and the octet of chlorine is also fulfilled. This bond is formed due to sharing of the electrons and therefore ${\text{CC}}{{\text{l}}_4}$ is a covalent compound. (Refer to the attached image)

${\text{CC}}{{\text{l}}_4}$ is a covalent compound. So 1 mole of ${\text{CC}}{{\text{1}}_{\text{4}}}$ contains 1 mole of carbon and 4 moles of Cl.

Number of moles of Cl in 1 mole of ${\text{CC}}{{\text{l}}_4}$ = 4

So the number of moles of Cl in 8 moles of ${\text{CC}}{{\text{l}}_4}$ is calculated as follows:

$\begin{aligned}{\text{Moles of Cl}}&=\left({8\;{\text{mol}}\;{\text{CC}}{{\text{l}}_4}}\right)* \left({\frac{{4\;{\text{mol}}\;{\text{Cl}}}}{{1\;{\text{mol}}\;{\text{CC}}{{\text{l}}_4}}}}\right)\n &=\boxed{32\;{\text{mol}}}\n\end{gathered}$

So 8 moles of ${\mathbf{CC}}{{\mathbf{l}}_{\mathbf{4}}}$ contain 32 moles of Cl.

Learn more:

1. Identification of ionic bonding: brainly.com/question/1603987

2. Which is a covalent compound? brainly.com/question/2083444

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Ionic and covalent compounds

Keywords: covalent compounds. chlorine, carbon, mole, non-metal, mutual sharing, molecular bond, hydrogen, chlorine, CCl4, brittle, enthalpy of fusion, heat, electricity, conductors, boiling points, positively charged, negatively charged.

Which compound is an example of a binary ionic compound?

Answers

Examples of binary ionic compounds include calcium chloride (CaCl2), sodium fluoride (NaF), and magnesium oxide (MgO), whilst examples of binary covalent compounds include water (H2O), and sulfur hexafluoride (SF6).Hope this helps!!!

MgF2 is a compound, i hope this helps people

Maggie is solving a chemistry riddle her clue is to take the number of valence electrons in halogens and subtract it by the number of valence electrons in alkali metals. what is the answer to the riddle maggie is solving?

Answers

The answer to the riddle Maggie is solving is 6

To determine the answer to the riddle Maggie is solving,

We will subtract the number of valence electrons in halogens by the number of valence electrons in alkali metals.

First, let us define what is meant by valence electrons

Valence electrons are those electrons that reside in the outermost shell surrounding an atomic nucleus.

Now, we will the determine the respective number of valence electrons in halogens as well as the number of valence electrons in alkali metals.

For Halogens

Halogens are the group 17 (group 7A) elements in the periodic table. Examples are Fluorine, Chlorine, Bromine etc.

Halogens have 7 electrons in their outermost shell

For Alkali metals

Alkali metals are the group 1 metals. Examples are Lithium, Sodium, Potassium etc.

Alkali metals have 1 electron in their outermost shell

Now, for the answer to the riddle,

Answer to the riddle = Number of valence electrons in halogens - Number of valence electrons in Alkali metals

Answer to the riddle = 7 - 1

∴ Answer to the riddle = 6

Hence, the answer to the riddle Maggie is solving is 6

Learn more here: brainly.com/question/9392364

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