How many moles of h2o are produced when 3.25 moles of o2 react in 2c2h6 + 7o2 ---> 4co2 + 6h2o

Answers

Answer 1
Answer:

Answer:

2.78 moles of water are produced.

Explanation:

Given data:

Number of moles of H₂O produced = ?

Number of moles of oxygen react = 3.25 mol

Solution:

Chemical equation:

2C₂H₆ + 7O₂       →     4CO₂ + 6H₂O

Now we will compare the moles of water with oxygen.

                O₂          :          H₂O

                 7            :           6

               3.25        :           6/7×3.25 = 2.78 mol


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A sample containing 4.80 g of O2 gas has an initial volume of 15.0 L. What is the final volume, in liters, when each of the following changes occurs in the quantity of the gas at a constant pressure and temperature?A. A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container.
B. A sample of 2.00 g of O2 is removed.
C. A sample of 4.00 g of O2 is added to the 4.80 g of O2 gas in the container.

Answers

The correct answer for the question that is being presented above is this one: "A. A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container." A sample containing 4.80 g of O2 gas has an initial volume of 15.0 L. The final volume, in liters, when each of the following changes occurs in the quantity of the gas at a constant pressure and temperature is that A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container.

Final answer:

By using the ideal gas law and molar mass calculations, the final volumes are found to be A. 65.0 L, B. 8.75 L, and C. 27.5 L.

Explanation:

To calculate the final volume when additional O2 is added or when some O2 is removed, we can use the concept of the molar mass and the ideal gas law that states that volume is directly proportional to the amount of gas, assuming pressure and temperature is constant.

The molar mass of O2 is approximately 32.00 g/mol.

A. 0.500 moles of O2 is added. This equals 0.500 * 32 g = 16 g. The total mass in the system is now 20.8 g. If the original 15.0 L represented 4.80 g, now 20.8 g would represent 15.0 L * 20.8/4.80 = 65.0 L.

B. 2.00 g of O2 is removed. So, the total mass in the system is now 2.80 g. If the original 15.0 L represented 4.80 g, now 2.80 g would represent 15.0 L * 2.80/4.80 = 8.75 L.

C. 4.00 g of O2 is added. So, the total mass in the system is now 8.80 g. If the original 15.0 L represented 4.80 g, now 8.80 g would represent 15.0 L * 8.80/4.80 = 27.5 L.

Learn more about Gas Laws here:

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In a laboratory experiment, John uses a mesh to separate soil particles from water. Which technique of separation is he using?

Answers

He is using filtration technique

It's a technique which is used for separation of solids and fluids by putting them through a medium which allow only fluid to pass through, leaving the solids (in this case the soil) alone.

The fluid that passed is called the filtrate

What mass of anhydrous solute is needed to prepare 500 mL of 0.032 M NaF(aq)? Answer in units of g.

Answers

Volume 500 mL in liters : 500 / 1000 = 0.5 L

Molar Mass NaF = 41.98 g/mol

Molarity = 0.032 M

Mass = Molarity * molar mass * volume

Mass = 0.032 * 41.98 * 0.5

 = 0.67168 g of NaF(aq)

hope this helps!

Gas burning in an engine is an example of a chemical change

phase change

physical change

nuclear change

Answers

The answer is the first option. Gas burning in an engine is an example of a chemical change. Chemical change is a change where the substance changes in identity or form new substances after undergoing a process. In this case, the gas reacts with oxygen forming combustion products, commonly carbon dioxide and water.

A mixture of uneven distribution and easy separation is called_____. homogeneous heterogeneous a solution a pure substance

Answers

the correct answer is heterogeneous.

Answer:

heterogeneous

Explanation:

Which must be a mixture of substances?
1. solid
2. liquid
3. gas
4. solution

Answers

the one that must be a mixture of substance is : 4. Solutionhere are some examples that proof option 1 - 3 could consist only with a single substance :Solid = Fe ( most commonly known as iron)Gas = He ( Most commonly known as helium)Liquid = Hg (most commonly known as mercury)

4.Solution

Further explanation

Mixtures are materials composed of two or more kinds of substances that still possess their original properties. Mixtures can also be said to represent a combination of several substances, elements or compounds

There are two types of mixtures, i.e., homogeneous mixture (or solution) and heterogeneous mixture.

  • Homogeneous mixture: mixture which each part contains a similar amount of solute, for example, vinegar acid solution, sugar solution, and salt solution.
  • Heterogeneous mixes: mixtures of which each part contains an unequal amount of solute, for example, river water, sewage water, and coffee drinks.

The solution is a homogeneous mixture of two or more substances that dissolve one another and each of the constituent substances cannot be distinguished physically anymore.

  • The solution consists of two components, i.e., solute and solvent.
  • For example, a salt solution consists of salt as a solute and water as a solvent.

In chemistry, we already know the phase of matter or state of matter, i.e., solid (s), liquid (l), gas (g), and aqueous (aq). Every chemical solution in a reaction is labeled as an aqueous phase, e.g, \boxed{ \ NaCl_((aq)) \ } as a salt solution.

Consider the following examples:

  • \boxed{ \ Fe_((s)) \ } as a solid metal iron, an element.
  • \boxed{ \ H_2O_((l)) \ } as liquid water.
  • \boxed{ \ H_2O_((s)) \ } as ice solids.
  • \boxed{ \ H_2O_((g)) \ } as water vapor with a gaseous phase.
  • \boxed{ \ H_2O_((l)), H_2O_((s)), H_2O_((g)) \ } are compounds of the same chemical formula but different phases.

Learn more

  1. About the mass and density of substances  brainly.com/question/4053884
  2. Calculating the pH value of weak base brainly.com/question/9040743
  3. How was the water filtered to remove debris and living organisms?  brainly.com/question/5646770

Keywords: which must be, a mixture of substances, solid, liquid, gas, solution, homogeneous, heterogeneous, phase of matter, state, aqueous, salt, water