Does dissolved potassium chloride affect the surface tension between water molecules?

Answers

Answer 1
Answer:

Answer:

Inorganic impurities present in the bulk of a liquid such as KCl tend to increase the surface tension of water.

Explanation:

As potassium chloride (KCl) dissolves in water, the ions are hydrated. ... When ionic compounds dissolve in water, the ions in the solid separate and disperse uniformly throughout the solution because water molecules surround and solvate the ions, reducing the strong electrostatic forces between them.

hope it helps you

mark me as brainliest!!


Related Questions

Atmospheric pressure arises due to the force exerted by the air above the Earth. At higher altitudes, the mass of the air above the Earth is _____ than at sea level, and atmospheric pressure therefore _____ with altitude.
Jaxson needs to react 16.3 moles of copper (II) nitrate, Cu(NO3)2, in a chemical reaction. How many grams of crystalsdoes he need to weigh out?
Convection currents in the atmosphere influence many weather patterns. What property of the air has the most influence on convection currents?1. The direction of the wind2. The velocity of the wind3. The temperature of the air4. The mass of the air
Identify which location in the periodic table you would have thelargest atomic radii.
Consider the generic chemical equation below. X + Ymc021-1.jpg W + Z Reactant X contains 199.3 J of chemical energy. Reactant Y contains 272.3 J of chemical energy. Product W contains 41.9 J of chemical energy. If the reaction loses 111.6 J of chemical energy as it proceeds, how much chemical energy must product Z contain?

Draw an arrow-pushing mechanism for the elimination reaction between NaOH in ethanol and each of the following haloalkanes: (E1/E2)(i) 1-bromobutane;
(ii) 2-bromo-2-methylpentane.

Answers

Answer:

The mechanisms for the elimination reactions between NaOH in ethanol and the halogenoalkanes are demonstrated in the figure attached.

Explanation:

(i) 1-bromobutane will suffer elimination to for an alkene. The mechanism will be E2, which means that the attack and the elimination will occur simultaneously. This is the preferred mechanism because the bromine is in a primary carbon.

(ii) 2-bromo-2-methylpentane will suffer elimination to for an alkene. The mechanism will be E1, which means that the attack and the elimination will occur in two different steps. The bromine will be eliminated in the first step with the formation of a carbocation and in a second step the double bond will be formed after the anionic attack. This is the preferred mechanism because the bromine is in a terciary carbon which is able to stabilize the carbocation formed.

According to the equation below, which of the following will cause the concentration of H2SO4 to increase? 2NaHCO3 (s) + H2SO4 (aq) ⇄ Na2SO4 (aq) + 2H2O (l) + 2CO2 (g) View Available Hint(s) According to the equation below, which of the following will cause the concentration of H2SO4 to increase? 2NaHCO3 (s) + H2SO4 (aq) ⇄ Na2SO4 (aq) + 2H2O (l) + 2CO2 (g) addition of some NaHCO3 (s) addition of some Na2SO4 (aq) removal of some H2O (l) removal of some CO2 (g)

Answers

Answer:

Addition of some Na₂SO₄ (aq).

Explanation:

2NaHCO₃ (s) + H₂SO₄ (aq) ⇄ Na₂SO₄ (aq) + 2H₂O (l) + 2CO₂ (g)

According to the Le Chatelier's principle, the addition of Na₂SO₄ to the reaction would lead to shift to the direction of the reaction that consumes Na₂SO₄, in order to reestablish equilibrium. Since the reaction that consumes Na₂SO₄ is the reaction that produces H₂SO₄, the concentration of H₂SO₄ would increase.

What is the empirical formula of a compound that is 64.3 % c, 7.2 % h, and 28.5 % o by mass?

Answers

Asnwer : Empirical formula of a compound is : C_(3)H_(4)O

Given information : C = 64.3 % , H = 7.2 % , O = 28.5 %

Step 1 : Convert the given percentage (%) to grams.

Explanation : Let the total mass of the compound be 100 grams.

Mass of C = 64.3 g

(100g)* ((64.3percent))/((100percent)) = 64.3g

Mass of H = 7.2 g

(100g)* ((7.2percent))/((100percent)) = 7.2g

Mass of O = 28.5 g

(100g)* ((28.5percent))/((100percent)) = 28.5g

Step 2 : Convert the grams of each compound to moles.

Moles = (Grams)/(Molar mass)

Molar mass of C = 12.0g/mol  

Molar mass of H = 1.0 g/mol

Molar mass of O = 16.0g/mol

Moles of C = (64.3g)/(12.0(g)/(mol))

Moles of C = 5.36 mol

Moles of H = (7.2g)/(1.0(g)/(mol))

Moles of H = 7.2 mol

Moles of O = (28.5g)/(16.0(g)/(mol))

Moles of O = 1.78 mol

Step 3 : Find the mole ratio of C , H and O

Mole ratio is calculated by dividing the mole values by the smallest value.

Mole of C = 5.36 mol , Mole of H = 7.2 mol , Mol of O = 1.78 mol

Out of the three mole values , mole value of O that is 1.78 mol is less , so we divide all the mole values by 1.78 mol.

Mole of C = (5.36mol)/(1.78mol) = 3.0

Mole of H = (7.2mol)/(1.78mol) = 4.0

Mole of O = (1.78mol)/(1.78mol) = 1.0

C : H : O = 3 : 4 : 1

So empirical formula of the compound is C_(3)H_(4)O_(1) or C_(3)H_(4)O

Please Please! help help! so stress

Answers

I AM STRESSED AS WELL

What action is NOT necessary before lighting a Bunsen burner?A)Make sure there are no holes in the hose connected to the burner.
B)Leave the gas stop open for a few minutes before lighting to clear the line.
C)Clear the burner area of flammable materials such as solvents and papers.
D)Check that the gas regulator and air inlet on the burner can be adjusted.

Answers

The Bunsen burner is a heating apparatus used to heat samples in the laboratory. The correct answer is option B: )Leave the gas stop open for a few minutes before lighting to clear the line.

A Bunsen burner is commonly used as a heating apparatus. It contains a gas that can be controlled using a gas regulator.

It is necessary to do the following before lighting the Bunsen burner;

  • Make sure there are no holes in the hose connected to the burner.
  • Clear the burner area of flammable materials such as solvents and papers.
  • Check that the gas regulator and air inlet on the burner can be adjusted.

So, it is not necessary to Leave the gas stop open for a few minutes before lighting to clear the line before lighting a Bunsen burner.

Learn more: brainly.com/question/743920

Answer:

the answer is opetuon B

Which element has a complete valence electron shell?selenium (Se)
oxygen (0)
fluorine (F)
argon (Ar)
Mark this and return
Viewers/AssessmentViewer/Activit
Save and Exit
Nexh
Submit

Answers

Final answer:

Argon (Ar) has a complete valence electron shell.


Explanation:

The element that has a complete valence electron shell is argon (Ar).


Learn more about complete valence electron shell here:

brainly.com/question/2725863