MATHEMATICS HIGH SCHOOL

What will be the linear equation for the shown table?

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What will be the linear equation for the shown table? - 1

Answers

Answer 1
Answer:

Answer:

y=2x+5

Step-by-step explanation:

To find a linear equation you must find the slope and y intercept to create an equation in y=mx+b form (slope-intercept form)

So slope is = y2-y1 / x2-x1 [2 and 1 are subscripts] so 11-7/3-1 so m=4/2 = 2

Slope = 2, now find b

So using y = mx + b, substitute what you know so 7 = 2(1) + b so b=7-2 = 5

Put it all together y = 2x + 5

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I need help please Find the value of numerical expression can you explain it to me please
2^4

Answers

2^4 is saying that your multiplying 2 X 2 X 2 X 2
so 2X2 = 4 X2 = 8 X 2 = 16
you can also just use a calculator

The sum of three numbers is 2100. The first number (x) is equal to the sum of the other two (y and z) which are equal to each other. What are the three numbers (x, y, and z)? A) (1050, 525, 525) B) (1050, 524, 525) C) (1050, 526, 523) D) (1051, 525, 524)

Answers

Answer:

Let's solve the problem step-by-step:

We are given that the sum of three numbers is 2100. Let's call the first number x and the other two numbers y and z.

From the information given, we know that x = y + z, and y = z (the other two numbers are equal to each other).

Substituting y = z into x = y + z, we have x = 2z.

We are also given that the sum of the three numbers is 2100. So, we can write the equation x + y + z = 2100.

Substituting x = 2z and y = z, we have 2z + z + z = 2100.

Simplifying the equation, we have 4z = 2100.

Dividing both sides of the equation by 4, we find z = 525.

Substituting z = 525 back into y = z, we find y = 525.

Finally, substituting z = 525 and y = 525 back into x = 2z, we find x = 1050.

Therefore, the three numbers are x = 1050, y = 525, and z = 525.

Among the options provided, the correct answer is A) (1050, 525, 525).

A triangular banner has an area of 351cm2. The length of the base is two centimeters longer than four times the height. Find the height and length of the base.

Answers

Answer:

h = 13cm and b= 54cm.

Step-by-step explanation:

We have that the area A=351cm^2 and the base is two centimeters longer than four times the height, that is

b = 2+4h

where b is the base and h the height. Now, the area is

A=(b*h)/(2)

351=((2+4h)h)/(2)

702=2h+4h^2

4h^2+2h-702=0.

Now, we are going to use the general formula to solve quadratic ecuations:

h=(-b\pm√(b^2-4ac))/(2a)

where a=4, b= 2 and c= -702.

h=(-2\pm√(2^2-4(4)(-702)))/(2*4)

h=(-2\pm√(4+11232))/(8)

h=(-2\pm106)/(8)

h=(-2+106)/(8) or h=(-2-106)/(8)

As we are searching for the lenght, we choose the positive result:

h=(-2+106)/(8)=13cm

b=2+4h = 2+52 = 54cm.

Which value, when placed in the box, would result in a system of equations with infinitely many solutions?y=2x-5
2y - 4x =
10
5
10

Answers

Answer: -10

Step-by-step explanation:

What is 85 percent of a 28 year prison sentence?

Answers

Answer:

23.8 years

Step-by-step explanation:

85% can be written as 0.85

0.85 * 28 = 23.8 years

PLEASE HELP, DUE AT MIDNIGHT >>>>>

Answers

Answer:

BELOW

Step-by-step explanation:

7.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-8,\:-11\right),\:\left(x_2,\:y_2\right)=\left(17,\:4\right)\n\nm=(4-\left(-11\right))/(17-\left(-8\right))\n\nm = (4+11)/(17+8)= (15)/(25) \n\mathrm{Refine}\n\nm=(3)/(5)

8.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(10,\:-15\right),\:\left(x_2,\:y_2\right)=\left(13,\:-17\right)\n\nm=(-17-\left(-15\right))/(13-10)\n\nm = (-17+15)/(13-10)\n \nm = (-2)/(3)\n \nSimplify\nm=-(2)/(3)

9.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-6,\:-7\right),\:\left(x_2,\:y_2\right)=\left(5,\:-7\right)\n\nm=(-7-\left(-7\right))/(5-\left(-6\right))\n\nm = (-7+7)/(5+6)\n \nm = (0)/(11)\n \nSimplify\nm=0

10.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-4,\:-3\right),\:\left(x_2,\:y_2\right)=\left(2,\:-9\right)\n\nm=(-9-\left(-3\right))/(2-\left(-4\right))\n\nm = (-9+3)/(2+4)\n \nm = (-6)/(6) \n\nSimplify\nm =-1

11.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\mathrm{When\:}y_1\ne \:y_2\mathrm{\:and\:}\:x_1=x_2\mathrm{\:the\:slope\:is\:}\infty \n\nm = \infty

12.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-5,\:3\right),\:\left(x_2,\:y_2\right)=\left(19,\:-6\right)\n\nm=(-6-3)/(19-\left(-5\right))\n\nm = (-6-3)/(19+5)\n \nm = (-9)/(24)\n \nSimplify\nm=-(3)/(8)

13.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-7,\:-12\right),\:\left(x_2,\:y_2\right)=\left(1,\:-16\right)\n\nm=(-16-\left(-12\right))/(1-\left(-7\right))\n\nm = (-16+12)/(1+7) \n\nm = (-4)/(8) \n\nSimplify\nm=-(1)/(2)

14.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-18,\:0\right),\:\left(x_2,\:y_2\right)=\left(-13,\:1\right)\n\nm=(1-0)/(-13-\left(-18\right))\n\nm = (1-0)/(-13+18)\n \nm = (1)/(5) \n

15.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(1,\:-11\right),\:\left(x_2,\:y_2\right)=\left(-2,\:-4\right)\n\nm=(-4-\left(-11\right))/(-2-1)\n\nm = (-4+11)/(-2-1)\n \nm = (7)/(-3) \n\nSimplify\nm=-(7)/(3)
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