I need help!! ASAP please..
I need help!! ASAP please.. - 1

Answers

Answer 1
Answer:

Answer:

164 g

Explanation:


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Answers

The remaining 90% transforms into Hydrogen and Oxygen. The remaining 90% is recombined to maker larger molecules. I think

the ionization constant for dichloroacetic acid HC2HO2Cl2 is 5.0 x 10^-2 . What is the pH of a 0.15 molar solution of this acid?

Answers

Answer: pH = 1.19

Explanation:

The formula for Ka is:  Ka = [H+][A-]/[HA]

where:  [H+] = concentration of H+ ions

[A-] = concentration of conjugate base ions

[HA] = concentration of undissociated acid molecules

Equation of reaction:  Cl₂CHCOOH ---> H+ + Cl₂CHCOO-

From the equation above, dichloroacetic acid dissociates one H+ ion for every Cl₂CHCOO- ion,

so [H+] = [Cl₂CHCOO-].

Let x represent the concentration of H+ that dissociates from HA, then [HA] = C - x where C is the initial concentration.

Substituting these values into the Ka equation:

Ka = x · x / (C -x)

Ka = x²/(C - x)

(C - x)Ka = x²

x² = CKa - Kax

x² + Kax - CKa = 0

Solve for x using the quadratic formula:

x = [-b ± √(b² - 4ac)]/2a

Note: There are two solutions for x. However only the positive value of x is used since x represents a concentration of ions in solution, and so cannot be negative.

x = [-Ka + √(Ka² + 4CKa)]/2

Substitute the values for Ka and C in the equation above:  

Ka = 5.0 x 10^-2

C = 0.15 M  

x = {-5.0 x 10^-2 + √[(5.0. x 10^-2)² + 4(0.15)(5.0 x 10^-2)]}/2

x = (-5.0 x 10^-2 + 1.80 x 10^-1)/2

x = 0.13/2

x = 6.50 x 10^-2

To find pH, we use the formula;

pH = -log[H+]

pH = -log(x)

pH = -log(6.50 x 10^-2)

pH = -(-1.19)

pH = 1.19

Consider an element Z that has two naturally occurring isotopes with the following percent abundances: the isotope with a mass number of 19.0 is 55.0% abundant; the isotope with a mass number of 21.0 is 45.0% abundant. What is the average atomic mass for element Z?Average atomic mass of Z = [mass]

Answers

Answer:

Average atomic mass = 19.9 amu

Explanation:

Isotopes can be defined as two or more forms of a chemical element that are made up of equal numbers of protons and electrons but different numbers of neutrons.

Generally, the isotopes of a chemical element have the same chemical properties because of their atomic number but different physical properties due to their atomic weight (mass number).

Given the following data;

Relative abundance of Z-19 = 55%

Relative abundance of Z-21 = 45%

Atomic mass of Z-19 = 19 amu

Atomic mass of Z-21 = 21 amu

To find the average atomic mass;

Average atomic mass = 19 * (55/100) + 21 * (45/100)

Average atomic mass = 19*0.55 + 21*0.45

Average atomic mass = 10.45 + 9.45

Average atomic mass = 19.9 amu

Therefore, the average atomic mass for element Z is 19.9 amu.

A newspaper article about the danger of global warming from the accumulation of greenhouse gases such as carbon dioxide states that "reducing driving your car by 20 miles a week would prevent release of over 1000 pounds of CO 2 per year into the atmosphere." Is this a reasonable statement? Assume that gasoline is octane (molecular formula is C 8 H 18 ) and that it is burned completely to CO 2 and H 2 O in the engine of your car. Facts (or reasonable guesses) about your car's gas mileage, the density of octane, and other factors will also be needed.

Answers

Answer:

Mass of CO2 produced = 944.43 -lb/year

Since 944.43 -lb is close to 1000 -lb, it is a reasonable statement.

Explanation:

Assumptions:

Car mileage = 20 miles/gallon:

Density of gasoline = 0.702 g/ml

Volume of gallons per week = (20 miles/week) / (20 miles/gallon) = 1 gallon/week

Volume of gasoline per year = 52 weeks * 1 gallon/week = 52 gallons

1 gallon = 3.8 litres or 3800 ml

52 gallons = 52 * 3800 = 197600 ml

Mass of gasoline = volume *density

Mass of gasoline = 197600 ml * 0.702 g/ml

Mass of gasoline = 138715.2 g

Equation of reaction:

2C8H18 + 25O2 ---> 16CO2 + 18H2O

2 moles of octane produces 16 moles of CO2

Molar mass of octane = 114 g/mol; molar mass of CO2 = 44 g/mol

114 * 2 g of octane = 44 * 16 g of CO2

138715. 2 g of octane produces = (138715.2 * 44 * 16) / 114 * 2 of CO2

Mass of CO2 produced = 428313.6 g of CO2 = 428.3136 Kg

Mass of CO2 produced in -lb weight = 428.3136 * 2.205

Mass of CO2 produced per year = 944.43 -lb CO2

Since 944.43-lb is close to 1000 -lb, therefore, it is a reasonable statement.

If 6.81 mol of an ideal gas has a pressure of 2.99 atm and a volume of 94.35 L, what is the temperature of the sample?

Answers

Answer:

504.57 K.

Explanation:

From the question given above, the following data were obtained:

Number of mole (n) = 6.81 moles

Pressure (P) = 2.99 atm

Volume (V) = 94.35 L

Gas constant (R) = 0.0821 atm.L/Kmol

Temperature (T) =.?

Using the ideal gas equation, the temperature of the ideal gas can be obtained as follow:

PV = nRT

2.99 × 94.35 = 6.81 × 0.0821 × T

282.1065 = 0.559101 × T

Divide both side by 0.559101

T = 282.1065 / 0.559101

T = 504.57 K.

Thus, the temperature of the ideal gas is 504.57 K.

Write a balanced chemical equation for the standard formation reaction of gaseous dinitrogen tetroxide

Answers

Answer:

N_2(g)+2O_2(g)\rightarrow N_2O_4(g)

Explanation:

Hello,

In this case, considering the required product which is dinitrogen tetroxide whose molecular formula is N₂O₄, by considering its formation reaction which is starting by both gaseous nitrogen and oxygen as shown below:

N_2(g)+O_2(g)\rightarrow N_2O_4(g)

Nevertheless, it should be balance since four oxygen atoms are present at the right side, thus, we obtain:

N_2(g)+2O_2(g)\rightarrow N_2O_4(g)

Best regards.