BY what factor does the kinetic energy of a moving body change when its speed is reduced to half? please help i have an exam and i need an answer

Answers

Answer 1
Answer:

Answer:

Kinetic Energy = 1/2 mass*velocity^2

K=1/2mv^2

Therefore if you reduce the speed of an object by 1/2, K reduced to 1/4 its value.


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An increase in which quantity will result in an increase in momentum?A).velocity
B).force
C).gravity
D).distance

Answers

An increase in the velocity of an object will increase the momentum of the object.

What is momentum?

The momentum of an object is determined from the product of mass and velocity of an object.

P = mv

where

  • m is the mass of the object
  • v is the velocity of the object

Thus, an increase in the velocity of an object will increase the momentum of the object.

Learn more about momentum here: brainly.com/question/7538238

Answer:

a. velocity.      PLATO USERS

Explanation:

1.What is true about heat capacity and specific heat?a) Only heat capacity accounts for mass.

b) Both heat capacity and specific heat account for mass.

c) Neither specific heat nor heat capacity accounts for mass.

d) Only specific heat accounts for mass.



2. Which of the following factors is not used in calculating the specific heat of a substance?

a) mass

b) temperature change

c) heat required for a temperature change

d) melting point


3. The amount of heat needed to raise 250 g of a substance by 15 K is 2,930 J. What is the specific heat of the substance ?

a) 0.78

b) 11,000

c) 780

d) 1.1 × 10^7


4. If 50 g of liquid water [C = 4,180 J/(kgK)] changes temperature in a calorimeter from 298 K to 348 K, then how much heat is transferred?

a) 10.5 J

b) 10.5 kJ

c) 72.7 J

d) 100 kJ

Answers

1-c. 2-d. 3-a. and 4 is -b.

If X = 5 and Y = 3, what does Z equal?
2X + 2Z = 10Y

Answers

Z equals 10, when substitute X = 5 and Y = 3 in 2X + 2Z = 10Y.

What are Arithmetic operations?

Arithmetic operations can also be specified by the subtract, divide, and multiply built-in functions.

* Multiplication operation: Multiplies values on either side of the operator

For example 4*2 = 8

/ Division operation: Divides left-hand operand by right-hand operand

For example 4/2 = 2

Given that equation as:

⇒ 2X + 2Z = 10Y

If X = 5 and Y = 3,

Substitute the values of X = 5 and Y = 3,

⇒ 2(5) + 2 (Z) = 10(3)

Apply the multiplication operation

⇒ 10 + 2Z= 30

⇒ 2Z = 20

⇒ Z = 20/2

Apply the division operation

⇒ Z = 10

Hence, Z equals 10, when Substitute  X = 5 and Y = 3 in 2X + 2Z = 10Y

Learn more about Arithmetic operations here:

brainly.com/question/25834626

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2(5) + 2 (z) = 10{3}
10 + 2z= 30
2z=20
z=10

What is intertia? Explain.​

Answers

Answer:

Law of inertia, also called Newton's first law, postulate in physics that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

Hopethisanswerisright!

Answer:

property of matter by which it continues in its existing state of rest or uniform motion in a straight line, unless that state is changed by an external force.

At which point in the life cycle of a star does nuclear fusion begin?A. Black hole
B. Main sequence
C. Nebula
D. Protostar

Answers

I would say B : main sequence is the answer . this is the answer i believe because the star will increase in size and than shine brightly and when it's done , it will get smaller turning into  nebula , eventually exploding sometime around the last stage , but not the last stage of b , c, or d

i really hope that this helps you a lot.

Final answer:

The correct answer is D. Protostar.

Nuclear fusion in a star's lifecycle begins during the protostar stage. This is when the temperature and pressure of the protostar ignite nuclear fusion, transitioning into a main sequence star.

Explanation:

In the life cycle of a star, nuclear fusion begins when the star has reached the protostar stage. The initial stage in the development of a star is the nebula, which is a cloud of dust and gas. Over time, the nebula's materials collapse under gravity to form a hot core known as a protostar.

When the protostar's temperature and pressure rises, it triggers nuclear fusion and the star begins turning hydrogen into helium.

This marks the transition from a protostar to a main sequence star, which is the stage of stable nuclear fusion.

Learn more about Nuclear Fusion in Stars here:

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A car traveling with constant speed travels 150 km in 7200 s. What is the speed of the car?

Answers

75 km/hr, so  in other words 75 km per hour.

7200 s / 60 = 120 min
120 min / 60 =2 hr
so 150 km / 2 hr = 75 km per hour

Answer:

The speed of the car is \boxed{75\,{{{\text{km}}} \mathord{\left/{\vphantom {{{\text{km}}} {{\text{hr}}}}} \right.\kern-\nulldelimiterspace} {{\text{hr}}}}} or \boxed{20.83\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}} .

Further Explanation:

Given:

The distance covered by the car is 150\,{\text{km}}.

The time taken by the car to cover the distance is 7200\,{\text{s}} .

Concept:

The speed of a car is the ratio of the distance covered by the car to the time taken by the car in covering the distance.

The expression for the speed of the car is:

v = (d)/(t)       …… (1)                                      

Here, v is the speed of the car, d is the distance covered and t is the time taken by the car.

Substitute the value of distance and time in the above expression.

 \begin{aligned}v &= \frac{{150\,{\text{km}}}}{{7200\,{\text{s}}\left( {\frac{{1\,{\text{hr}}}}{{60 * 60\,{\text{s}}}}} \right)}}\n&= \frac{{150}}{2}\,{{{\text{km}}} \mathord{\left/{\vphantom {{{\text{km}}} {{\text{hr}}}}} \right.\kern-\nulldelimiterspace} {{\text{hr}}}}\n&= 75\,{{{\text{km}}} \mathord{\left/{\vphantom {{{\text{km}}} {{\text{hr}}}}} \right.\kern-\nulldelimiterspace} {{\text{hr}}}}\n\end{aligned}

The speed of the car in terms of {{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}  can be expressed as.

\begin{aligned}v&=75\,{{{\text{km}}} \mathord{\left/{\vphantom {{{\text{km}}}{{\text{hr}}}}} \right.\kern-\nulldelimiterspace} {{\text{hr}}}}\left( {\frac{{1000\,{\text{m}}}}{{3600\,{\text{s}}}}} \right)\n&=75 *\frac{5}{{18}}\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}\n&= 20.83\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}\n\end{aligned}

Thus, the speed of the car is \boxed{75\,{{{\text{km}}} \mathord{\left/{\vphantom {{{\text{km}}} {{\text{hr}}}}} \right.\kern-\nulldelimiterspace} {{\text{hr}}}}} or \boxed{20.83\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}}\right.\kern-\nulldelimiterspace} {\text{s}}}}.

Learn More:

  1. A test car travels in a straight line along the x axis, the graph in the figure shows brainly.com/question/10772739
  2. A 1500-kg car accelerates from rest to 25 m/s in 7.0 s. What is the average power delivered by the brainly.com/question/7956557
  3. If no friction acts on a diver during a dive, then which of the following statements is true brainly.com/question/4633609

Answer Details:

Grade:Middle School

Chapter:Speed and distance

Subject:Physics

Keywords:Speed, velocity, distance, time, distance of 150 km, in 7200 s, speed of the car, ratio of distance, rate of change of distance.