Factors and multiplesfor 8 yes or no

Answers

Answer 1

Answer: factors 1,2,3,4 and 8
multiples are 8,16,24,32,40,48,56,64,72,80,88,96,104,112,120,128,136,144,152,160,168,176,184,1

hope this helps.

Answer 2

Answer: the factors of 8 are : 1 , 2 , 4 , 8

multiples of 8 : 8 , 16 , 24 ,32 , 40 , 48 , 56 , 64 , 72 , 80 , 88 , 96 , 104 , 112 etc..........

hope this helps you

Related Questions

Write the equation of the line, given the y- and x-intercepts. x-intercept (–6, 0), y-intercept (0, –8)
Listed in the Item Bank are key terms and expressions, each of which is associated with one of the columns. Some terms may display additional information when you click on them. Drag and drop each item into the correct column. Order does not matter.Item Bank: Blue graph | Green graph | Red graph | Table 1 | Table 2 | Table 3Linear | Non-Linear
1-4x = 3-4y___ ____ 2+x y if y is a non zero constant, which equation represents the value of x in the given equation? A) x=3y-2 B)x=3y+2 C)x=9y-6 D)x=9y+6 I have no idea how to solve.
A square has sides 10x. write and simplify an expression for the perimeter of that square
Renee is a sales associate at a store. She earns $80 a week plus a 15% commission on her sales. Last week, she sold $200 worth of items. What is the total amount Renee earned for the week? How much did she earn from commission? Renee earned a total of $____ for the week.a. 93b. 110c. 122d. 295The amount she earned from commission was $____a. 12b. 15c. 30d. 42PLEASE HELP!! REALLY STUCK!

In the rhombus ABCD diagonal DB is congruent to side AD what is the measure of angle A

Answers

All sides of a rhombus are equal ⇒ AD = AB

AD = AB and AD = DB ⇒ AD = AB = DB ⇒ ΔABD is equilateral ⇒∠A = 60°

Which choice gives the solution of this inequality? 3t+ < 28

Answers

Answer:

its 9.33 reapetting or just 9.33

Step-by-step explanation:

Kevin is looking at two brands of washing machines. Between water and electricity, a Brand C washer uses about $0.65 per load, and a Brand D washer uses about $0.27 per load. Kevin averages about five loads of laundry per month. After one year, how much more would the utility costs for a Brand C washer be than the utility costs for a Brand D washer?a.
$22.80
b.
$16.20
c.
$7.60
d.
$19.00

Answers

Answer:

a. $22.80

Step-by-step explanation:

Given :

Brand C washer uses about $0.65 per load

Brand D washer uses about $0.27 per load

Kevin averages about five loads of laundry per month.

To Find :how much more would the utility costs for a Brand C washer be than the utility costs for a Brand D washer after one year?

Solution :

The utility cost of Brand C washer per load = $0.65

Since she uses 5 loads per month

So, she uses loads in 12 months(=1year) = 5*12 =60 loads

Now cost of 60 loads is 60*0.65 = $39

Thus the utility cost of Brand C for 1 year is $39

The utility cost of Brand D washer per load = $0.27

Since she uses 5 loads per month

So, she uses loads in 12 months(=1year) = 5*12 =60 loads

Now cost of 60 loads is 60*0.27 = $16.2

Thus the utility cost of Brand D for 1 year is $16.2

The difference between their 1 year costs = $39-$16.2 = $22.8

Thus the utility costs for a Brand C washer will be $22.8 more than the utility costs for a Brand D washer.

Hence Option A is correct.

The correct answer is A. $22.80.

Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The three pens are to have the same area. Express the area function for the three pens in terms of x. Determine the domain and range for the area function

Answers

Answer:

The area function is

$A=(135)/(2)x-(9)/(2)x^2$ .

The domain and range of A is $(0,15m)$ and $(0, 253.125 m^2]$ .

Step-by-step explanation:

The given length of fencing is $90 m$ .

Let the length and width of each pen be $x$ and $y$ respectively as shown in the figure.

As there are 3 pens, so, the total area,

$A= 3 xy \;\cdots (i)$

From the figure the total length of fencing is $6x+4y$ .

Here, for a significant area for the animals, $x>0$ as well as $y>0$ as $x$ and $y$ are the sides of ben.

From the given value:

$6x+4y=90\;\cdots (ii)$

$\Rightarrow y=\frac {45}{2}-(3x)/(2)$

Now, from equation (i)

$A=3x\left(\frac {45}{2}-(3x)/(2)\right)$

$\Rightarrow A=(135)/(2)x-(9)/(2)x^2\;\cdots (iii)$

This is the required area function in the terms of variable $x$ .

For the domain of area function, from equation (ii)

$x=15-(2y)/(3)$

$\Rightarrow x<15 m$ [as y>0]

So, the domain of area function is $(0,15m)$ .

For the range of area function:

As $x \rightarrow 0$ or $y\rightarrow 0$ , then $A\rightarrow 0$ [from equation (i)]

$\Rightarrow A>0$

Now, differentiate the area function with respect to $x$ .

$\frac {dA}{dx}=(135)/(2)-9x$

Equate $\frac {dA}{dx}$ to zero to get the extremum point.

$\frac {dA}{dx}=0$

$\Rightarrow (135)/(2)-9x=0$

$\Rightarrow x=(15)/(2)$

Check this point by double differentiation

$\frac {d^2A}{dx^2}=-9$

As, $\frac {d^2A}{dx^2}<0$ , so, point $x=(15)/(2)$ is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

$A=(135)/(2)* \frac {15}{2}-(9)/(2)* \left(\frac {15}{2}\right)^2$

$\Rightarrow A=253.125 m^2$

Hence, the range of area function is $(0, 253.125 m^2]$ .

Final answer:

The area of each pen can be expressed as A(x) = x * (90 - 2x) / 3. The domain of this function is 0 < x < 45, and the range is 0 < A(x) < 300

Explanation:

In this problem, since Pam has to divide the petting zoo into three parts, we can consider the width of each pet pen to be x and the total length of the three pens to be (90 - 2x)/3, given that the total fence is 90m and we have two fences that are x meters long separating the pens. So, the area, A of each pen can be expressed as a function of x: A(x) = x * (90 - 2x) / 3. The domain of this function, or the possible values of x, would be all the values that make the area positive, which are 0 < x < 45. For the range of the function, we analyze the quadratic function which will have a maximum value at x = 15, as the area will be largest when the space is divided evenly, so the maximum area is A(15)= 15 * (60) / 3 = 300. Therefore, the range of the function is 0 < A(x) < 300.

Learn more about Area and Functions here:

brainly.com/question/29292490

#SPJ11

Find the limit of the function algebraically. limit as x approaches negative six of quantity x squared minus thirty six divided by quantity x plus six.