The correct option is this: THE FIRST ATOM EMITS LIGHT WITH MORE ENERGY.
In the question given above, the level 1 mentioned in the question refers to the ground state of the electrons while level 2 and level 3 refer to excited states of hydrogen electrons. When an atom is in an excited state, it possess more energy and it is unstable, thus, it tends to return to the ground state after sometime to attain stability. As the atom return to the ground state, it loses its energy by emitting light. The higher the level of excitation, the more the light that will be emitted when the atom is returning to the ground state. Thus, an atom returning to the ground state from level 3 has more energy and will emit more light when returning to the ground state than an electron in level 2.
Answer:
Explanation:
At same temperature and same number of moles, Using Boyle's law
Given ,
V₁ = 10 mL
V₂ = 20 mL
P₁ = 5.85 kPa
P₂ = ?
Using above equation as:
B) the optimum temputure for the enzyme amylase is not 104. F (40.)
C) the substrate for amylase, starch, is not present
Answer:
c
Explanation:
Chemical energy is converted into mechanical energy.
B.
Mechanical energy is converted into light energy.
C.
Light energy is converted into sound energy.
D.
Sound energy is converted into chemical energy.
b. 2
c. 3
d. 4
THe pH of the solution containing NaF and HF would be higher than that of a solution of HF only.
The presence of NaF drives the reaction towards the HF side to reach equilibrium.
The concentration of H+ is higher in an HF solution containing NaF.
The pH of the solution containing NaF and HF would be lower than that of a solution of HF only.
The presence of the dissolved NaF does not affect the HF equilibrium reaction nor the equilibrium concentrations.