When a liquid sample is taken from sea level to a higher elevation, what happens to the external (atmospheric) pressure on the liquid and the boiling point of the liquid

Answers

Answer 1
Answer:

Answer:

The external atmospheric pressure decreases and so does the boiling point of the liquid.

Explanation:

We know that pressure decreases with height. Thus atmospheric pressure decreases at higher elevation.

The implication of this is that, if I take a liquid from sea level to a higher elevation, the external atmospheric pressure on the liquid will decrease and so does its boiling point.

Hence, the liquid boils at a lower temperature when placed at a higher elevation. For this reason, the boiling point of a liquid is lower on the mountain.


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A weather balloon has a volume of 200.0 L at a pressure of 760 mm Hg. As it rises, the pressure decreases to 282 mm Hg. What is the new volume of the balloon? (Assume constant temperature)

Answers

Answer:

The new volume of the balloon is 539 L

Explanation:

As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide less times per unit time against them. This means that the pressure will be less because it represents the frequency of gas strikes against the walls. In this way, pressure and volume are related, determining Boyle's law that says:

"The volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure"

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

o P * V = k

Having an initial state 1 and an final state 2 will be fulfilled:

P1 * V1 = P2 * V2

So, in this case, you know:

  • P1= 760 mmHg
  • V1= 200 L
  • P2= 282 mmHg
  • V2= ?

Replacing:

760 mmHg*200 L= 282 mmHg*V2

Solving:

V2=(760 mmHg*200 L)/(282 mmHg)

V2=539 L

The new volume of the balloon is 539 L

Calculate the pH of a buffer solution made by adding 15.0 g anhydrous sodium acetate (NaC2H3O2) to 100.0 mL of 0.200 M acetic acid. Assume there is no change in volume on adding the salt to the acid. (pKa for acetic acid is 4.74 or Ka is 1.8 x 10-5)3.

Answers

Answer:

pH of Buffer Solution 5.69

Explanation:

Mole of anhydrous sodium acetate = (Given mass)/(Molecular mass)

                                                           = (15)/(82)

                                                           = 0.18 mole

 100 ml of 0.2 molar acetic acid  means

= M x V

= 0.2 x 100

= 20 mmol

= 0.02 mole

Using Henderson equation to find pH of Buffer solution

pH = pKa + log([Salt])/([Acid])

     = 4.74 + log(0.18)/(0.02)

     = 4.74 + log 9

     = 5.69

So pH of the Buffer solution = 5.69

300.0 mL of a 0.335 M solution of NaI is diluted to 700.0 mL. What is the new concentration of the solution?

Answers

Answer: The new concentration of the solution is 0.143 M.

Explanation:

Given:V_(1) = 300.0 mL,    M_(1) = 0.335 M

V_(2) = 700.0 mL,         M_(2) = ?

Formula used is as follows.

M_(1)V_(1) = M_(2)V_(2)

Substitute values into the above formula as follows.

M_(1)V_(1) = M_(2)V_(2)\n0.335 M * 300.0 mL = M_(2) * 700.0 mL\nM_(2) = 0.143 M

Thus, we can conclude that the new concentration of the solution is 0.143 M.

Final answer:

To find the new concentration of the solution, you can use the formula C1V1 = C2V2. Plugging in the given values, the new concentration of the solution is 0.144 M.

Explanation:

To find the new concentration of the solution, we can use the formula:

C1V1 = C2V2

Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Plugging in the given values, we get:

(0.335 M)(300.0 mL) = C2(700.0 mL)

Solving for C2, we find the new concentration of the solution to be 0.144 M.

Learn more about concentration of a solution here:

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What experimental evidence led Rutherford to conclude that an atom is mostly space?

Answers

Thomson concluded that electrons must be parts of the atoms of all elements. Millikan determined the charge and mass of the electron. What experimental evidence led Rutherford to conclude that an atom is mostly empty space? The majority of the alpha particles passed straight through the gold foil.

Consider an element Z that has two naturally occurring isotopes with the following percent abundances: the isotope with a mass number of 19.0 is 55.0% abundant; the isotope with a mass number of 21.0 is 45.0% abundant. What is the average atomic mass for element Z?Average atomic mass of Z = [mass]

Answers

Answer:

Average atomic mass = 19.9 amu

Explanation:

Isotopes can be defined as two or more forms of a chemical element that are made up of equal numbers of protons and electrons but different numbers of neutrons.

Generally, the isotopes of a chemical element have the same chemical properties because of their atomic number but different physical properties due to their atomic weight (mass number).

Given the following data;

Relative abundance of Z-19 = 55%

Relative abundance of Z-21 = 45%

Atomic mass of Z-19 = 19 amu

Atomic mass of Z-21 = 21 amu

To find the average atomic mass;

Average atomic mass = 19 * (55/100) + 21 * (45/100)

Average atomic mass = 19*0.55 + 21*0.45

Average atomic mass = 10.45 + 9.45

Average atomic mass = 19.9 amu

Therefore, the average atomic mass for element Z is 19.9 amu.

PLZZZZZZZZZZZZ HELPPPPPPPPP BRAINLIEST FOR WHO GETS IT RIGHTTTTTTWhat is the mass of reactants in the following equation?N2 + 3H2 ----> 2NH3
Question 3 options:


34.05 amu


31.03 amu


30.02 amu


15.01 amu

Answers

Answer: 34.05

Explanation:

2N and 6H = abt 34