Color corresponds to the ______________ of light waves..A. Wave Speed

B. Cycles

C. Wavelength

Answers

Answer 1
Answer:

The correct answer is

C.wavelength



In fact, the colour of visible light depends on the wavelength of the wave. The visible light spectrum goes approximately from wavelength of 380 nm (corresponding to violet light) to 750 nm (corresponding to red light), and the different colours in between correspond to different wavelengths. For instance, blue light has wavelength of 450-500 nm, while yellow light has wavelength of 570-590 nm.

Answer 2
Answer: Color corresponds to the wavelength of light waves.
The shortest light waves are "violet", the longest light waves are "red".

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The age of the universe is thought to be about 14 billion years. Assuming two significant figures, write this in powers of ten in years

Answers

14x10^9 remember to hit that thanks button and rate 5 stars please!!!!

How much amount of heat is required to raise the temperature of 20 grams of water from 10°C to 30°C? The specific heat of water is 4.18 J/g°C.

Answers

The amount of heat:
Q = m c ΔT
m = 20 g,  c = 4.18 J/g°C,  ΔT = 30° - 10° = 20° C
Q = 20 g · 4.18 J/g°C · 20°C = 1672 J
Answer: C ) 1700 J

Answer : The amount of heat is required is, 1672 J

Solution :

Formula used :

Q= m* c* \Delta T

Q= m* c* (T_(final)-T_(initial))

Q= heat gained

m= mass of the substance = 20 g

c = heat capacity of water = 4.18 J/g ° C

T_(final) = final temperature = 30^oC

T_(initial) = initial temperature = 10^oC

Now put all the given values in the above formula, we get the heat required.

Q= (20g)* (4.18 J/g^oC)* (30-10)^oC

Q = 1672 Joules

Therefore, the amount of heat is required is, 1672 J

A man travellers 10 km to the east 20 km to the north. Find distance moved displacement

Answers

x^2=10^2+20^2\n x^2=100+400\n x^2=500\n x=√(500)=10\sqrt5 \approx22.36\hbox{ km}

I need some help, anything will help, I just need a better understanding of this

Answers

Answer:

12 meters

Explanation:

to find this we look at the 8 on the horizontal line this is 8 seconds, you then look upwards to see the height at that point in time

a 1.0 kg ball is thrown into the air with an initial velocity of 30 m/s. How much kinetic energy does the ball have?

Answers

KE=.5mv^2
KE=.5(1)(30^2)
KE=(.5)(900)
KE=450
Assuming no air resistance....

Final answer:

The kinetic energy of a 1.0 kg ball thrown with an initial velocity of 30 m/s is calculated using the formula KE = 1/2 mv^2, resulting in an energy of 450 Joules.

Explanation:

The question you've asked pertains to calculating the kinetic energy of a ball thrown into the air. To find the kinetic energy (KE) of a 1.0 kg ball thrown with an initial velocity of 30 m/s, you can use the formula KE = ½ mv², where m is the mass of the ball and v is the velocity. Plugging in the values, you get KE = ½ × 1.0 kg × (30 m/s)² = 0.5 × 1.0 × 900 = 450 J. Therefore, the kinetic energy of the ball is 450 Joules.

Learn more about kinetic energy here:

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A drowsy cat spots a flowerpot that sails first up and then down past an open window. The pot is in view for a total of 0.66 s, and the top-to-bottom height of the window is 1.80 m. How high above the window top does the flowerpot go? (Assume that in both sailing upward and then falling downward, the flowerpot is seen to span the full vertical height of the window.)

Answers

Answer:

Height covered after crossing window top = 0.75 m

Explanation:

In the question,

The height of the window pane = 1.8 m

Time for which the flowerpot is in view = 0.66 s

So,

The time for which it was in view while going up is = 0.33 s

Time for which it was in view while going down = 0.33 s

So,

Let us say,

The initial velocity of the flowerpot = u m/s

So,

Using the equation of the motion,

s=ut+(1)/(2)at^(2)\n1.8=u(0.33)-(1)/(2)(9.8)(0.33)^(2)\n1.8=0.33u-0.5336\n0.33u=2.33\nu=7.07\,m/s

So,

Velocity at the top of the window pane is given by,

v=u+at\nv=7.07-(9.8)(0.33)\nv=3.836\,m/s

Now,

Let us say the height to which the flowerpot goes after crossing the window pane is = h

So,

Using the equation of motion,

v^(2)-u^(2)=2as\n(0)^(2)-(3.836)^(2)=2(-9.8)h\nh=(14.714)/(19.6)\nh=0.75\,m

Therefore, the height covered by the flowerpot after window is = 0.75 m