How many grams of NaBr must he measure out to have 4.20 moles?

Answers

Answer 1
Answer:

Answer: 432 grams

Explanation:NaBr must he measure out to have 4.20 moles.


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Classify each type of matter as an element, a compound, a heterogeneous mixture, or a homogeneous mixture. drag each item to the appropriate bin. sugar air hot tea salt water

Answers

Answer :

Sugar : Compound

Air : Homogeneous mixture

Hot tea : Homogeneous mixture

Salt water : Homogeneous mixture

Explanation :

Element : It is a pure substance which is composed of atoms of similar elements.

Compound : It is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.

Heterogeneous mixtures : It is a mixture that has non-uniform composition throughout the solution and the particle size or shapes are also different.

There is a physical boundary between the dispersed phase and dispersion medium.

Homogeneous mixtures : It is a mixture that has uniform composition throughout the solution and the particle size or shapes are not different.

There is no physical boundary between the dispersed phase and dispersion medium.

As per question,

Sugar : It is a compound that is made from atoms of different elements combined together in a fixed ratio by mass.

Air : It is a homogeneous mixture of the gaseous substances of nitrogen, oxygen, and smaller amounts of other substances.

Hot tea : It is a homogeneous mixture because its composition is the same throughout the solution.

Salt water : It is a homogeneous mixture because its composition is the same throughout the solution.

Sugar compound

Air Homogeneous mixture

Hot tea Homogeneous mixture

Salt water Homogeneous mixture

 

Element:

An element is a simplest type of a pure substance which is composed of only one type of matter. For examples; silver, gold platinum etc.

Pure substance:

A compound is a pure substance which is composed of two or more type of matter in definite proportion. For examples; water which is composed by Hydrogen and oxygen etc.

Mixture:

A mixture is made from two or more type of matter in any proportion. Mixture are generally two types:

1. Homogeneous mixture

This is also known as solution, in which the composition of the substances is uniform.

Lemon-flavored water is an example of homogeneous mixture because in this the composition of the substances is uniform.

2. Heterogeneous mixture

In this form of mixture the composition of substance are not uniform and the component of mixture also visible.

Stuffed mushrooms is an example of Heterogeneous mixture because in this form of mixture the composition of substance are not uniform and the component of mixture also visible.


Which is the limiting reactant when 5.00g of H2 and 10.00g of O2 react and form water?​

Answers

Explanation:

The reaction expression is given as:

           2H₂  +   O₂    →    2H₂O

The limiting reactant is the reactant in short short supply in the given reaction.

To find the limiting reactant we use the number of moles.

    Mass of H₂  = 5g

    Mass of O₂   = 10g

  Number of moles  = (mass)/(molar mass)  

       Molar mass of H₂   = 2(1) = 2g/mol

       Molar mass of O₂  = 2(16)  = 32g/mol

Number of moles  H₂ = (2)/(5)   = 0.4mole

Number of moles O₂ = (10)/(32)   = 0.3mole

   From the balanced reaction equation:

           2 mole of H₂ reacts with 1 mole of O₂

          0.4 mole of H₂ reacts with  0.2 mole of O₂

But we are given 0.3 moles of O₂, so the limiting reactant is H₂ because oxygen gas is in excess

Final answer:

To find the limiting reactant between hydrogen (H₂) and oxygen (O₂) for water (H₂O) formation, convert given masses to moles, compare with the stoichiometry of the balanced equation, and identify that oxygen (O₂) is the limiting reactant as it has fewer moles available than required.

Explanation:

Finding the Limiting Reactant

To determine the limiting reactant in a chemical reaction between hydrogen (H₂) and oxygen (O₂) to form water (H₂O), we must first balance the chemical equation. The balanced reaction is:

2H₂(g) + O₂(g) → 2H₂O(l)

Next, we will calculate the molar masses and use them to find the moles of each reactant:


  •  
  • Molar mass of H₂ = 2.02 g/mol

  •  
  • Molar mass of O₂ = 32.00 g/mol

Now, we convert the given masses to moles:


  •  
  • Moles of H₂ = 5.00 g H₂ × (1 mol H₂ / 2.02 g) = 2.48 mol H₂

  •  
  • Moles of O₂ = 10.00 g O₂ × (1 mol O₂ / 32.00 g) = 0.313 mol O₂

According to the stoichiometry of the balanced equation, we need 2 moles of H₂ for every 1 mole of O₂ to react completely. Therefore, the moles needed for the given moles of O₂ are:

Moles of H₂ needed = 0.313 mol O₂ × (2 mol H₂ / 1 mol O₂) = 0.626 mol H₂

Since we have 2.48 mol H₂ and only need 0.626 mol to react with all the available O₂, we can see that we have excess H₂ and not enough O₂. Hence, O₂ is the limiting reactant.

Learn more about Limiting Reactant here:

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Which phase changes will result in an increase in energy of the substance

Answers

Answer:

when gas condenses to liquid the quantity of energy converts.

Explanation:

two phase changes where the heat in energy is released

potential energy. During a phase change, the heat added (PE increases) or released (PE decreases) will allow the molecules to move apart or come together. Heat absorbed causes the molecules to move farther apart by overcoming the intermolecular forces of

Consider the following chemical equilibrium: C(s) + 2H2 (g) <------> CH4 (g)
Now write an equation below that shows how to calculate Kp from Kc for this reaction at an absolute temperature T. You can assume T is comfortably above room temperature. If you include any common physical constants in your equation be sure you use their standard symbols, found in the ALEKS Calculator.

Answers

Answer:

Kp = [CH₄(g)]/[H₂(g)]²(RT)⁻¹

Explanation:

C(s) + 2H₂(g) => CH₄(g)

Kp = Kc(RT)ⁿ

n= change in molar volumes of gas = 1 - 2 = -1

R = 0.08206 L·Atm/mol·K (gas constant)

T = Kelvin Temperature (arbitrary in problem) K =°C + 273

Kc = [CH₄(g)]/[H₂(g)]²  (measured values need to be in moles/L)

Kp = [CH₄(g)]/[H₂(g)]²(RT)⁻¹

An aqueous solution is 4.44 M nitric acid and the density of the solution is 1.42 g/mL. Calculate the mole fraction of this solution.

Answers

The mole fraction of HNO3 is  0.225

Explanation:

1.Given data

Density = 1.429 /ml

Mass% = 63.01 g HNO3 / 100g of solution

The mass of 63.01 g is in 100 / 1.142 /ml of solution

Or 63.01 g in 55.7 mL

Molarity = 15.39 moles / L

Mass of water in 100g = 100 - 63.01=36.99 g

So 63.01 grams in 36.99 grams of water

So mass of HNO3 in 1000grams of water = 63.01* x 1000 / 36.99 = 1703

Moles of HNO3 in 1000g = 1703 / 63.01 = 27.03 moles

Molality = 27.03 molal (mole / Kg)

Mole fraction = Mole of HN03 / Moles of water + mole of HNO3

Mole of water = 62/ 18 = 3.44

Moles of HNO3 = 63.01 / 63.01 = 1.000

Mole fraction = 1.000 / 3.44 + 1.000 = 0.225

The mole fraction of HNO3 is  0.225

Fruits and vegetables exposed to air begin to brown because of a chemical reaction in their cells. This may result in these foods being thrown out. Some people have found that adding lemon juice (citric acid) to apple slices keeps them from turning brown. The prevention of browning is likely the result of *increasing the concentration of enzymes
increase in the temperature
slowing the rate of enzyme reaction
maintaining the pH

Answers

The prevention of fruits browning is the result of :

>slowing the rate of enzyme reaction

How is the browning of fruits prevented?

The browning of fruits can be slowed down by preventing the enzyme from working properly. Lemon juice contains an acid which can stop enzymes from working properly. For example, water and sugar in jam prevents oxygen in the air to reach enzymes and hence protects from browning.

Always keep cut fruits such as apples, pears and peaches from turning brown by coating them with an acidic juice such as lemon or orange.

The enzyme that is responsible for the browning is called polyphenol oxidase. PPO enzyme in the presence of oxygen changes substances known as phenolic compounds, through oxidation, into quinones.

To know more about enzymes, refer

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Answer:

slowing the rate of enzyme action

Explanation: