What occurs in both fusion and fission reactions?(1) Small amounts of energy are converted into
large amounts of matter.
(2) Small amounts of matter are converted into
large amounts of energy.
(3) Heavy nuclei are split into lighter nuclei.
(4) Light nuclei are combined into heavier nuclei

Answers

Answer 1
Answer:

Fusion and fission are nuclear reactions that convert a small amount of matter into a large amount of energy.

The fusion reaction is the reaction in which the molecules combine and form energy. The fission reaction is the decomposition nuclear reaction where the matter is degraded into a small entity and the energy is released.

The energy is not converted into matter in both reactions. There is no splitting or combination of nuclei in both reactions.

Thus, the small amount of matter is converted into a large amount of energy is correct.

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Answer 2
Answer: I believe the correct answer from the choices listed above is option 2. Small amounts of matter are converted into
large amounts of energy occurs in 
both fusion and fission reactions. They are nuclear reactions where a change in the identity or characteristics of an atomic nucleus results when it is bombarded with an energetic particle, as in fission, fusion, or radioactive decay.

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The state of matter that is able to be compressed is gas

liquid

solid

Answers

Gases are easily compressible

The answer would be gas.

Which conclusion was drawn from the results ofthe gold foil experiment?
(1) An atom is electrically neutral.
(2) An atom is mostly empty space.
(3) The nucleus of an atom is negatively
charged.
(4) The electrons in an atom are located in
specific shells.

Answers

Answer;

-(2) An atom is mostly empty space.

Experiment

-Rutherford conducted the "gold foil" experiment where he shot alpha particles at a thin sheet of gold. The conclusion that can be drawn from these experiment is that an atom is mostly empty space.

-Rutherford found that a small percentage of the particles were deflected, while a majority passed through the sheet. This caused Rutherford to conclude that the mass of an atom was concentrated at its center, as the tiny, dense nucleus was causing the deflections.

Answer;

(2) An atom is mostly empty space.

Experiment

-Rutherford conducted the "gold foil" experiment where he shot alpha particles at a thin sheet of gold. The conclusion that can be drawn from these experiment is that an atom is mostly empty space.

-Rutherford found that a small percentage of the particles were deflected, while a majority passed through the sheet. This caused Rutherford to conclude that the mass of an atom was concentrated at its center, as the tiny, dense nucleus was causing the deflections.

A beaker contains three solids: flour, sugar, and baking soda. Whichdescribes the contents of the beaker? *

Answers

Answer: It is a Heterogeneous mixture.

Final answer:

The beaker contains a mixture of three solids, namely flour, sugar, and baking soda. These components retain their properties in the mixture and are not chemically combined.

Explanation:

The contents of the beaker can be described as a mixture. A mixture is a combination of two or more substances that are not chemically combined. In this case, the beaker contains flour, sugar, and baking soda. These are solid substances that maintain their own properties in the mixture. They're simply combined in the same space (the beaker), but they are not interacting on a molecular level to form a new substance.

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What action could slow a chemical reaction rate?a. lowering the pressure
b. raising the temperature
c. increasing the concentration
d. adding more of a substance to a mixture

Answers

The action that could slow a chemical reaction rate is adding more of a substance to a mixture. The answer is letter d. It does not give time for the rest of the reactants to be consumed because you are adding more of it causing to slow the reaction.

A sample of an unknown substance has a mass of 0.158 kg. If 2,510.0 J of heat is required to heat the substance from 32.0°C to 61.0°C, what is the specific heat of the substance?

Answers

The specific of the unknown substance that underwent a change in temperature is 0.567 J/g-C. This was solved using the equation for heat transfer which is:

U = mCp(Tf-Ti)

where:
U = heat absorbed or released in joules
m = mass in grams
Cp = specific heat in J/g-C
Tf = final temperature
Ti = initial temperature

Substituting values and converting 0.158 kg to grams gives the value 0.567 J/g-C. You can use a table of specific heat values to determine what the substance is as well.

Answer: 0.469 J / g°C

Explanation:

1) Data:

m = 0.158 kg

Q = 2,150.0 J

ΔT = 61.0°C - 32.0°C

Cs = ?

2) Formula:

Q = m×Cs×ΔT

3) Solution

i) Solve for Cs: Cs = Q / [m×ΔT]

ii) Plug in the data and compute

Cs = 2,150.0 J / [158 g × (61.0°C - 32.0°C) ] = 0.469 J / g°C

What is the chemical formula of iron (III) sulfide?
A. FeS
B. Fe2S3
C. Fe2(SO3)3

Answers

Chemical formula of iron (III) sulfide is Fe₂S₃.

What is chemical formula?

A chemical formula is a way of presenting information about the chemical proportions of atoms that constitute a particular chemical compound or molecule, using chemical element symbols, numbers, and sometimes also other symbols, such as parentheses, dashes, brackets, commas and plus and minus signs.

We can write a chemical formula by following steps-

1. Write both the atoms that are present in the chemical compound.

2. Write the valencies of both the atoms that are present in the chemical compound.

3. Now cross multiply both the atoms such that 1 atom's valency goes to the subscript of another atom and vice versa.

Given,

oxidation state of Fe = +3

Valency of Fe = 3

Valency of sulphide ion = 2

When we cross multiply both the atom's valencies we get chemical formula of iron (III) sulfide as Fe₂S₃.

Therefore, chemical formula of iron (III) sulfide is Fe₂S₃.

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the answer is i think B