Earth’s layers are determined by their physical properties and chemical composition. In the lesson, you learned about each of Earth’s layers, what the layers are made of, and why they are important to the Earth. In the space below, write about how the atmosphere may be classified. Would it be part of the lithosphere, or a separate layer? Explain your answer.

Explanation:

It is known that elements which contain same number of valence electrons when present in their neutral state then they tend to show similar chemical properties.

This is because only the valence electrons actively participate in a chemical reaction. As a result, these valence electrons determine their reactivity.

This is why, elements of same group tend to show similar chemical properties.

For example, element X and element Z have same number of valence electrons.

Therefore, we can conclude that both elements X and Z are most likely to have similar properties.

Answer:

The answer to your question is below

Explanation:

a. The hydrogen atoms of a water molecule have a partial positive charge.  True.

b. The oxygen atom of a water molecule is more electronegative than a hydrogen atom.  True

c. The hydrogen atoms of a water molecule have a partial negative charge.  False

d. The hydrogen atom of one water molecule is attracted to the oxygen atom of a different water molecule.  True

e. The hydrogen atom of a water molecule is attracted to the oxygen atom of the same water molecule.  False,

f. The oxygen atom of a water molecule has a partial positive charge.  True

g The oxygen atom of a water molecule has a partial negative charge. True

Percentage % yield = 91.8%

Given:

20 g NaCl

45 g AgCl

To find:

% yield=?

The balanced chemical equation will be:

NaCl + AgNO₃ ⇒ AgCl + NaNO₃

First, we need to calculate moles of NaCl.

Then, calculate moles of AgCl from equation:

Mass AgCl(theoretical) :

Now, calculate for percentage yield.

The percentage yield will be 91.8%.

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%yield = 91.8

Further explanation

Given

20 g NaCl

45 g AgCl

Required

%yield

Solution

Reaction

NaCl + AgNO₃ ⇒ AgCl + NaNO₃

mol NaCl :

= mass : MW

= 20 g : 58,44 g/mol

= 0.342

mol AgCl from equation :

= 1/1 x mol NaCl

= 1/1 x 0.342

= 0.342

Mass AgCl(theoretical) :

= mol x MW

= 0.342  x 143,32 g/mol

= 49.02 g

%yield = (actual/theoretical) x 100%

%yield = (45/49.02) x 100%

%yield = 91.8

Answer:

- The structural formula for Freon-12 (CCl2F2)

      F

       |

Cl - C - Cl

       |

      F

It has the same structure as methane (CH4) with Hydrogen atoms replaced by Chlorine and Fluorine

- Freon-12 and Freon-14 belong halocarbons, a compound in which the Hydrogen of a hydrocarbon is replaced by halogens, like Chlorine and Fluorine.

Final answer:

By utilizing stoichiometry, we can determine that the given volume and molarity of acetic acid (HC2H3O2) would produce approximately 3.65 grams of carbon dioxide (CO2). The calculation involves determining the moles of HC2H3O2 used, which equals the moles of CO2 produced, and converting that to grams using the molar mass of CO2.

Explanation:

The amount of carbon dioxide produced can be determined through stoichiometry, using the provided balanced chemical equation and molarity (M) of the acetic acid HC2H3O2. According to the balanced chemical equation, one mole of NaHCO3 reacts with one mole of HC2H3O2 to produce one mole of CO2. In other words, the moles of HC2H3O2 used equals the moles of CO2 produced.

First, calculate the moles of HC2H3O2 by multiplying the given volume (0.100 L) by its molarity (0.83 mol/L): 0.100L x 0.83 mol/L = 0.083 mol.

So, according to the stoichiometric ratio, 0.083 mol of HC2H3O2 would produce 0.083 mol of CO2. If you want your answer in grams, note that the molar mass of CO2 is approximately 44.01 g/mol. Multiply the moles of CO2 by its molar mass: 0.083 mol x 44.01 g/mol = 3.65g.

So, the amount of CO2 produced would be 3.65 grams.

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