Mr. Matinews and Mr. Peters are scuba diving. Mr. Matthews started out 12 feet belowthe surface. He descended 8 feet, rose 7 feet, and descended 13 more feet. Then he
rested. Mr. Peters started out at the surface. He descended 25 feet, rose 8 feet and
descended another 6 feet. Then he rested. Which person rested at a greater depth?
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Check work/answer

Answers

Answer 1
Answer:

Answer:

Mr.Matthews

Step-by-step explanation:

Mr.Matthews: Started at -12

-12 - 8 + 7 - 13 = -20 + 7 - 13 = -13 - 13 = -26

Mr. Peters: Started at -25

-25 + 8 - 6 = -17 - 6 = -23

In this case, -26 is greater than -23.

Mr.Matthews rested at a greater depth.

Hope this helps :)


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Question 2 Unsaved
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Answers

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If each of the numbers in the following data set were multiplied by 22, what would be the new median of the data set? 14, 20, 18, 58, 71, 36

Answers

The new median of the data set will be 616.

What is Multiplication?

To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.

Given that;

The data set is,

⇒ 14, 20, 18, 58, 71, 36

Now,

Since, The data set is,

⇒ 14, 20, 18, 58, 71, 36

Multiply by 22 in each number , we get;

⇒ 14 × 22, 20 × 22, 18 × 22, 58 × 22, 71 × 22, 36 × 22

⇒ 308, 440, 396, 1276, 1562, 792

Arrange the number is ascending order we get;

⇒ 308, 396, 440, 792, 1276, 1562

So, The median of data set = (440 + 792) / 2

                                          = 1232/2

                                          = 616

Thus, The new median of data set = 616

Learn more about the median visit:|

brainly.com/question/452652

#SPJ2

Answer:

If each of the numbers in the following data set were multiplied by 31, what would be the median of the data set?

28, 58, 20, 14, 18, 71, 36

A. 558

B. 1116

C. 434

D. 868

answer

D.868

Amy goes to a pumpkin patch and picks out a pumpkin that weighs 3,550 grams. If 1 gram = 0.0352 ounces, how many ounces does the pumpkin weigh? A) 124.56 ounces
B) 124.96 ounces
C) 125.56 ounces
D) 125.96 ounces

Answers

9514 1404 393

Answer:

  B) 124.96 ounces

Step-by-step explanation:

To find ounces, multiply the number of grams by the number of ounces in each gram.

  3550 × 0.0352 = 124.96 . . . ounces

Your office is raising money for charity by collecting aluminium cans for recycling. They get 36p per kilo of cans. A kilo is approximately 72 cans. They have collected 8645 cans How much money have they raised?

Answers

8645 cans divided by 72 per kilo is 120.069 kilos of cans
120.069 kilos times 0.36 pounds= 43.22 pounds raised

Answer:

£43.23

Step-by-step explanation:

8645 cans divided by 72 per kilo is 120.069 kilos of cans

120.069 kilos times 0.36 pounds

Rounded up to 43.23

The length of a rectangle is 12 m.Its width is 15 m.
Find the area and perimeter of this rectangle.

Answers

Answer:

for perimeter you add all sides. so Lenth x2 + width x2 is 24+30 which would equal 54

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One thousand tonnes (1000 t, one t equals 10 cubed kg) of sand contains about a trillion (10 super 12) grains of sand. How many tonnes of sand are needed to provide 1 mol of grains of sand? (b) Assuming the volume of a grain of sand is 1.0 mm3 and the land area of the continental United States is 3.6 multiplication 10 super six square miles, how deep would the sand pile over the United States be if this area were evenly covered with 1.0 mol of grains of sand?

Answers

Answer with Step-by-step explanation:

Since 1 mole of sand will contain Avagadro's Number of sand particles (by definition of 1 mole)

Thus we have

1 mole of sand = 6.022* 10^(23) sand particles

Thus in number of trillion sand particles we have no of trillion sand particles in 12 mole is

(6.022* 10^(23))/(10^(12))=6.022* 10^(11)

Now since it is given that mass of 1 trillion sand particles is 1000 tonnes Thus the mass of 6.022* 10^(11) trillion sand particles is

Mass=1000* 6.022* 10^(11)=6.022* 10^(14)tonnes

Part 2)

Since it is given that volume of 1 sand particle is 1.0mm^(3) thus the volume of 1 mole of sand is volume of 6.022* 10^(23) sand particles

Thus volume of 1 mole is V=1.00* 10^(-18)km^(3)* 6.022* 10^(23)=6.022* 10^(5)km^(3)

Now since the Area of united states is A=3.6* 10^(6)mile^(2)=5.8* 10^(6)km^(2)

Thus the depth of the sand pile is

Depth=(Volume)/(Area)=(6.022* 10^5)/(5.8* 10^6)=0.10387km=103.8meters