MATHEMATICS COLLEGE

Help please i need all

Answers

Answer 1

Answer:

Answer:

What grade are you in?

Step-by-step explanation:

6. 16 divided by 4 is 4

Then your keep going like 8 is 25 divided by 5 which is 5.

9. 120 divided by 4 is 30

10. 36 divided by 6 is 6

Answer 2

Answer: If you use a calculator it will be easier

Related Questions

Consider the initial value problem:y' + 5/3y =1 - 1/5t, y(0)= yoWhat equation expresses the requirement that the solution touches the t-axis?a. y(t)= 0b. y'(t)= 0c. y''(t)= 0
What is the equation of the line through (-6,-5) and (-4,-4) in slope-intercept form?
Tom is the deli manager at a grocery store.He needs to schedule employees to staff the deli department at least 260 person-hours per week.Tom has one part-time employee who works 20 hours per week.Each full-time employee works 40 hours per week.Write an inequality to determine f, the number of full time employees Tom must schedule, so that his employees will work at least 260 person-hours per week. Solve and graph. !PLEASE HELP!
14V + 5 − 5V = 4(V + 15)
What'd the greatest common factor (GCF) for each pair of numbers. 25, 55 The GCE IS

Is the red line a radius or diameter of the circle

Answers

The diameter of the circle would be a line going through the center of the circle connecting to both sides.

The radius of a circle would be a line only going to the the center, or in other words, half the circle.

I hope this makes sense!

European car company advertises that theircar gers 9.4 Kilometers per liter of gasoline. Convert
this figure to miles per galllon

Answers

Answer:

22.11 miles per gallon

Step-by-step explanation:

1 km = 0.621371 miles

1 litre = 0. 264172 gallon

Given

Mileage of car = 9.4 Milometers per liter of gasoline

Mileage of car = 9.4 Km/ litres

now we will use 0.621371 miles for Km and 0. 264172 gallon for litres

Mileage of car = 9.4 * 0.621371 miles/ 0. 264172 gallon

Mileage of car = 9.4 * 2.3521 miles/ gallon

Mileage of car = 22.11 miles/ gallon

Thus, 9.4 Km/litres is same as 22.11 miles per gallon.

Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evaluation is reports of the average student reading test score in each classroom. You also know that across the whole school, the average student reading score was 80 points and the standard deviation in scores was 10 points. Determine:
(a) If each class has 25 students in it, what is the standard error of the classroom average score?
(b) In what range do you expect the average classroom test score to fall 95% of the time?
(c) What is the approximate probability that a classroom will have an average test score of 79 or higher?
(d) Do you think the probability that a classroom has an average test score of 79 or higher would be greater or smaller if there were only 15 students in a class? Explain your answer in 2-3 sentences.
(e) Do you think the probability that a classroom has an average test score of 79 or higher would be greater or smaller if the standard deviation of individual student reading scores was only 5 points (instead of 10)?

Answers

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

$\sigma_m=(\sigma)/(√(n))=(10)/(√(25))=(10)/(5)=2$

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

$MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 80-3.92=76.08\n\nUL=M+t \cdot s_M = 80+3.92=83.92$

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

$z=(X-\mu)/(\sigma)=(79-80)/(2)=(-1)/(2)=-0.5$

Then, the probability of getting a average score of 79 or higher is:

$P(X>79)=P(z>-0.5)=0.69146$

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

I need help on question 6

Answers

Answer:

The 4th option is correct.

The equation of the line is: (y + 3) = 3 (x - 4)

Step-by-step explanation:

The equation of a line using two points, (x₁, y₁) and (x₂, y₂) is:

$(y-y_(1))=m(x-x_(1))$

Here m is the slope of the line.

The formula to compute slope is:

$m=(y_(2)-y_(1))/(x_(2)-x_(1))$

Given: The two points are (4, -3) and (5, 0)

The equation of the line passing through the points (4, -3) and (5, 0) is:

$(y-y_(1))=m(x-x_(1))\n(y-y_(1))=(y_(2)-y_(1))/(x_(2)-x_(1))(x-x_(1))\n(y-(-3))=(0-(-3))/(5-4)(x-4)\n(y+3)=3(x-4)$

Thus, the line passing through the points (4, -3) and (5, 0) is (y + 3) = 3 (x - 4).

The one above is correct

lled a 12:3:112:3:1 ratio. Such a model can provide the basis for the null hypothesis in a significance test. A cross of white and green summer squash plants gives the number of squash in the second generation F2:131F2:131 white squash, 3434 yellow squash, and 1010 green squash. Are these data consistent with a 12:3:112:3:1 dominant epistatic model of genetic inheritance( white being dominant)? The null hypothesis for the chi‑square goodness‑of‑fit test is

Answers

Here is the full question:

When a species has several variants of a phenotype passed on from generation to generation, we can form a hypothesis about the genetics of the trait based on Mendelian theories of genetic inheritance. For example, in a two-gene dominant epistatic model, the first gene masks the effect of the second gene, leading to the expression of three phenotype variants. Crossing the dominant and recessive homozygote lines would result in a second generation represented by a mix of dominant, intermediate, and recessive phenotype variants in the expected proportions: and respectively, also called a 12:3: 1 ratio.

Such a model can provide the basis for the null hypothesis in a significance test. A cross of white and green summer squash plants gives the number of squash in the second generation F2: 131 white squash, 34 yellow squash, and 10 green squash. Are these data consistent with a 12: 3: 1 dominant epistatic model of genetic inheritance( white being dominant)?

The null hypothesis for the chi-square goodness-of-fit test is

Answer:

The null hypothesis for the chi-square goodness-of-fit test is :

$\mathbf{H_o:p_(white) = (12)/(16), p_(yellow) = (3)/(16); p_(green) = (1)/(16) }$

Step-by-step explanation:

The objective of this question is to state the null hypothesis for the chi-square goodness-of-fit test.

Given that:

There are three colors associated with this model . i,e White , yellow and green and they are in the ratio of 12:3:1

The total number of these color traits associated with this model = 12 + 3 + 1 = 16

Thus ;

The null hypothesis for the chi-square goodness-of-fit test is :

$\mathbf{H_o:p_(white) = (12)/(16), p_(yellow) = (3)/(16); p_(green) = (1)/(16) }$

Chan receives a bonus from his job. He pays 30% taxes, pays 30% charity and 25% debt. Has $600 remaining from his bonus. What was the total amount of chains bonus?

Answers

Answer:

b = $4000

Step-by-step explanation:

Let b represent the bonus amount.

Then the bonus, b, less the three deductions, is represented by

b - 0.30b - 0.30b - 025b, and this comes to $600. Find the value of b.

b - 0.85b = $600, or

0.15b = $600

Then b = $4000

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