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What is the wavelength of the green light radiation that has a frequency of 6.26 x 10^14 Hz?
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Answers

Answer 1
Answer:

The wavelength of the green light radiation that has a frequency of 6.26 x 10¹⁴ Hz is 4.8 x 10⁻⁷.

What is wavelength?

Wavelength is defined as the distance between identical points or adjacent crests in the adjacent cycles of a waveform signal propagated in the space or wires.

Frequency is defined as the number of waves that passes a fixed place in a given amount of time.

It is also defined as how often something repeats.

As, c = ∧ v

So, ∧ = c / v

     ∧ = 3.00 x 10⁸ / 6.26 x 10¹⁴

     ∧ = 4.8 x 10⁻⁷    

Thus, the wavelength of the green light radiation that has a frequency of 6.26 x 10¹⁴ Hz is 4.8 x 10⁻⁷.

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Answer 2
Answer: To find out wavelength, divide speed of light with frequency: λ = c/ν

So,
λ=(3.00 x 10^8)/(6.26 x 10^14)

Answer= 0.48 x 10^-7

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Benadryl is used to treat itchy skin in dogs. The recommended dosage is 1 mg per pound. What mass of Benadryl, in milligrams, should be given to a dog that weighs 29.5 kg?

Answers

Answer:

65 mg

Explanation:

We are given the dosage per pound but have the weight of the dog in kilograms, thus we should convert the 29.5 kg to punds ( 1 pound = 0.454 kg):

29.5 kg  x 1 lb / 0.454 kg = 64.7 lbs

So now can answer our question:

( 1 mg / lb ) x 64.7 lb = 64.7

rounding to 65 mg

Final answer:

To treat itchy skin in a dog that weighs 29.5 kg, the dog should be given 65 mg of Benadryl.

Explanation:

To calculate the mass of Benadryl to give to a dog that weighs 29.5 kg, we need to use the recommended dosage of 1 mg per pound. First, we convert the weight of the dog from kg to pounds by multiplying it by 2.2046. So, the weight of the dog is approximately 65 pounds. To find the mass of Benadryl, we multiply the weight of the dog in pounds by the recommended dosage. Therefore, the dog should be given 65 mg of Benadryl.

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MEASUREMENT AND MATTER Interconverting temperatures in Celsius and Kelvins The metal osmium becomes superconducting at temperatures below 655.mk Calculate the temperature at which osmium becomes superconducting in degrees Celsius. Be sure your answer has the correct number of significant digits. Ac

Answers

Answer: -272^0C.

Explanation:

Temperature of the gas is defined as the degree of hotness or coldness of a body. It is expressed in units like ^0C and K  

These units of temperature are inter convertible.

We are given:

Temperature of the gas = 655mK=0.655K    (1mK=0.001 K)

Converting this unit of temperature into ^0C by using conversion factor:

(t-273.15)^0C=tK

273.15K=0^0C

Thus 0.655K=(0.655-273.15)^0C=-272^0C

Thus the temperature is -272^0C.

Classify each substance based on the intermolecular forces present in that substance.A. Hydrogen bonding, dipole dipole, and dispersion
B. Dipole dipole and dispersion only
C. Dispersion only
1. H2O
2. CH4
3. CO
4. CH2Cl

Answers

               Intermolecular forces

  1. When H2O- Hydrogen bonding, dipole-dipole, and also dispersion
  2. Then CH4- Dispersion only
  3. After that CO- Dispersion only
  4. Then CH2Cl- Dipole-dipole and also dispersion only

Explanation:

  • When Dipole-dipole interactions exist only in molecules that have a dipole moment such as water and also that dichloromethane.
  • After that Water experiences intermolecular hydrogen bonding in addition to dipole-dipole interaction and also that dispersion forces due to the O-H bond in the molecule.
  • Thus, Nonpolar compounds only have dispersion forces acting between their molecules.

Find out more information about dispersion here:

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Answer:

H2O- Hydrogen bonding, dipole dipole, and dispersion

CH4- Dispersion only

CO- Dispersion only

CH2Cl- Dipole dipole and dispersion only

Explanation:

Dipole- dipole interactions exist only in molecules that have a dipole moment such as water and dichloromethane. Water experiences intermolecular hydrogen bonding in addition to dipole-dipole interaction and dispersion forces due to the O-H bond in the molecule.

Nonpolar compounds only have dispersion forces acting between its molecules.

What reaction conditions most effectively conver a cabocxylic acid to a methly ester?

Answers

Answer:

Esterification reaction

Explanation:

When we have to go from an acid to an ester we can use the esterification reaction. On this reaction, an alcohol reacts with a carboxylic acid on acid medium to produce an ester and water. (See figure).  

In this case, we need the methyl ester, therefore we have to choose the appropriate alcohol, so we have to use the methanol as reactive if we have to produce the methyl ester.

You have a copper cylinder at room temperature (20ºC). You find that the diameter of the copper cylinder is 3.52 cm and the mass of the cylinder is 94.6754 g. What is the length (h) of the copper cylinder in mm? The density of copper is 8.96 g/cm3. (2 points) 4. You

Answers

Answer:

10.8 mm

Explanation:

Step 1: Calculate the volume (V) of the copper cylinder

The cylinder has a mass of 94.6754 g and a density of 8.96 g/cm³. The volume of the cylinder is:

94.6754 g * (1cm^(3) )/(8.96g) = 10.6 cm^(3)

Step 2: Calculate the length (h) of the copper cylinder

The diameter (d) of the copper cylinder is 3.52 cm. We can calculate the length using the following expression.

V = \pi * ((d)/(2))^(2) * h\nh = (4V)/(\pi * d^(2) ) = (4(10.6cm^(3) ))/(\pi * (3.52cm)^(2) ) = 1.08 cm

Step 3: Convert the length to millimeters

We will use the relationship 1 cm = 10 mm.

1.08cm * (10mm)/(1cm) = 10.8 mm

Complete and balance the equation for the following acid-base neutralization reaction. If water is used as a solvent, write the reactants and products as aqueous ions. In some cases, there may be more than one correct answer, depending on the amount of reactants used.(a)Mg(OH)2 + HClO4?
(b)SO3 + H2O? (Assume an excess of water and that the product dissolves)
(c) SrO + H2SO4?

Answers

Explanation:

A balanced equation is defined as the one that has equal number of atoms of all the elements present on both reactant and product side.

(a) Mg(OH)_(2) + HClO_(4) \rightarrow Mg(ClO_(4))_(2) + H_(2)O

Number of atoms on reactant side are as follows.

Mg = 1

O = 6

H = 3

Cl = 1

Number of atoms on product side are as follows.

Mg = 1

O = 9

H = 2

Cl = 2

So, to balance this equation we multiply Mg(OH)_(2) by 2 on reactant side and multiply H_(2)O by 2 on product side.

Therefore, the balanced reaction equation is as follows.

       2Mg(OH)_(2) + HClO_(4) \rightarrow Mg(ClO_(4))_(2) + 2H_(2)O  

(b)  SO_(3) + H_(2)O \rightarrow H_(2)SO_(4)

Number of atoms on reactant side are as follows.

S = 1

O = 4

H = 2

Number of atoms on product side are as follows.

S = 1

O = 4

H = 2

Therefore, this equation is balanced as it has same number of atoms on both reactant and product side.

(c)  SrO + H_(2)SO_(4) \rightarrow SrSO_(4) + H_(2)O

Number of atoms on  reactant side are as follows.

Sr = 1

O = 1

H = 2

S = 1

O = 4

Number of atoms on product side are as follows.

Sr = 1

O = 1

H = 2

S = 1

O = 4

Therefore, this equation is balanced.
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