Help me question 5 ASAP
Help me question 5 ASAP - 1

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Answer 1
Answer: I think it’s B.
I might be wrong, I’m just kinda going off based a little research and it says that it only happens in reptiles and teleost fish. The only option on there that’s related to it is the leatherback turtle.

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Need help ASAP!!!!!!!

The activiation energy required for a chemical reaction can be decreased by? A) increasing the surface area of the reactant.
B) increasing the temperature of the reactant.
C) adding a catalyst to the reaction.
D)adding more reactant​

Answers

Answer:

C)

Explanation:

C) adding a catalyst to the reaction.

HELP if water vapor condense on a cold surface is the initial and final energy thermal, phase, or chemical?

Answers

My answer to this great question would be thermal

Pls help ASAP I will give brainliest

Answers

Answer:

Lemon

HCI

Blood

Saliva

Bleach

NaOH

Explanation:

Blood 7.35-7.45

Bleach 12.6

Saliva 6.2-7.6

Lemon 2-3

HCI 3.01

NaOH 13

The vapor pressure of carbon disulfide is 355.6 torr at 25°C. What is the vapor pressure of a solution prepared by dissolving 10.60 g naphthalene (C10H8, Molar Mass = 128.2 g/mol) in 155 mL CS2 liquid (Molar Mass = 76.14 g/mol, density = 1.261 g/mL)? Assume the solution obeys Raoult's law, and treat naphthalene as a nonvolatile solute.

Answers

The vapor pressure of the solution would be as follows:

344.5764 torr

Given that,

Vapor pressure of Carbon Disulfide = 355.6 torr

volume = 155mL ;

density = 1.261 g/mL

Naphthalene's mass = 10.60 g

Naphthalene's molar mass= 128.2g/mol

Now,

We know that

Number of moles= mass/molar mass

Mass= density × volume

Number of moles =(density × volume) / molar mass

So,

Number of moles of Carbon Disulfide = (1.261 × 155) / 76.14

= (195.455 / 76.14)

= 2.567 moles of Carbon Disulfide

Number of moles of Naphthalene:

Number of moles= 10.60 / 128.2

= 0.083

Now,

Total number of moles :

2.567 + 0.083

= 2.65 moles

Mole fraction of each compound in solution :

Carbon Disulfide:

2.567 / 2.65

= 0.969

Naphthalene

0.083 / 2.65

= 0.031

According to Raoult's:

Psolution = Xsolvent × Posolvent

Carbon Sulfide = Solvent

Xsolvent =Mole fraction of solvent

Posolvent =Vapour  pressure of the pure solvent

Psolution= 0.969 × 355.6 torr

= 344.5764 torr

Thus, "344.5764 torr" is the correct answer.

Learn more about "Pressure" here:

brainly.com/question/23358029

Answer:

344.5764 torr

Explanation:

Molar mass of naphthalene = 128.2g/mol

Mass of naphthalene = 10.60 g

Carbon disulfide:

Molar mass= 76.14g/mol ;

volume = 155mL ;

density = 1.261 g/mL

Vapour pressure = 355.6 torr

Number of moles = mass / molar mass

CS2:

Mass = density × volume

Number of moles = (density × volume) / molar mass

Number of moles = (1.261 * 155) / 76.14 = (195.455 / 76.14) = 2.567 moles of CS2

Number of moles of C8H10:

Number of moles = 10.60 / 128.2 = 0.083 C8H10

Total number of moles :

2.567 + 0.083 = 2.65 moles

Mole fraction of each compound in solution :

CS2 :

2.567 / 2.65 = 0.969

C8H10:

0.083 / 2.65 = 0.031

According to Raoult's:

Psolution = Xsolvent × Posolvent

CS2 = solvent

Xsolvent = Mole fraction of solvent

Posolvent = Vapour pressure of pure solvent

Psolution = 0.969 × 355.6 torr = 344.5764 torr

What is the speed of a basketball that is thrown 18meters in 4 seconds?

Answers

Answer:

4.5m/s

Explanation:

speed = distance/time

speed = 18/4

speed = 4.5m/s

The mass of a water balloon is 2 kilograms. The speed that the water ballon is traveling when it hits the ground is 20 meters/second.What is the total kinetic energy of a water balling that hits the ground after it is dropped from a balcony ?

Answers

Answer:

400 Joules

Explanation:

From the question,

The total kinetic energy of the water balling when hits the ground is given as

K.E = 1/2mv².................. Equation 1

Where K.E = Kinetic Energy of water ballon, m = mass of water balloon, v = velocity of water ballon

Given: m = 2 kilograms, v = 20 meters/second.

Substitute these values into equation 1

K.E = (2×20²)/2

K.E = 2×400/2

K.E = 400 Joules