Write the symbols for the following isotopes: Its atoms contain 50 electrons and 70 neutrons
Answers
The symbol of an isotope that atom of its element contains 50 electrons and 70 neutrons is Tin (Sn).
What is Isotope?
The Isotope may be characterized as one of two or more types of atoms of a chemical element that significantly have the same number of protons but with different numbers of neutrons and therefore different atomic masses.
In a more simple sense, an isotope may be defined as an atom that has the same atomic number but different atomic mass and physical properties.
According to the question,
The number of electrons an atom possesses = 50.
The number of neutrons = 70.
Since, the number of electrons = the number of protons = the atomic mass of an atom = 50.
∴ According to the periodic table, an element having an atomic number of 50 is known as Tin (Sn).
Its atomic mass = the number of protons + the number of neutrons.
= 50 + 70 = 120 amu.
Therefore, the symbol of an isotope that the atom of its element contains 50 electrons and 70 neutrons is Tin (Sn).
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Is the following sentence true or false? The lower the ionization energy, the easier it is to remove an electron from an atom. A. True B. False
A change in which property of light will have no effect on whether or not the photoelectric effect occurs??? Frequently energy intensity and wavelength
Answers
72.7% is the percent by mass of oxygen in carbon dioxide. A percent is obtained by multiplying the result by 100.
One approach to show the concentration for an element within a compound or component in a combination is as a mass percentage. The mass percentage is computed by dividing the total weight of the combination by the mass of each component and multiplying the result by 100%. The mass percent is calculated by dividing the mass that contains the compound and solute by the mass for the element or solute.
Molar mass of oxygen = 32 g/mole
Molar mass of carbon dioxide = 44 g/mole
mass percentage of oxygen =(molar mass of oxygen/molar mass of carbon dioxide)× 100
=(32/44)× 100
=72.7%
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Answer : The percent by mass of oxygen in carbon dioxide is, 72.72%
Solution : Given,
Molar mass of oxygen = 16 g/mole
Molar mass of carbon dioxide = 44 g/mole
As we know that there are 2 atoms of oxygen and 1 atom of carbon present in the carbon dioxide.
So, the molar mass of oxygen, = 2 × 16 = 32 g/mole
Now we have to calculate the percent by mass of oxygen in carbon dioxide.
Now put all the given values in this expression, we get
Therefore, the percent by mass of oxygen in carbon dioxide is, 72.72%
(2) higher boiling point and lower freezing point
(3) lower boiling point and higher freezing point
(4) lower boiling point and lower freezing point
Answers
Explanation:
Colligative properties are those properties of solution that depend on the concentraion of the solute.
Increase of boling point and depression of freezing point are two of those colligative properties.
Regarding the boiling point, as some impurities (in this case the solute calcium chloride) are present in the solvent (water) ,at the same temperature, less molecules of water will reach the surface to escape, at a given temperature. Hence, you have to increase the temperature to manage that the number of molecules and their speed increase and so all the molecules can escape fro, the liquid phase to form the gas. So, the boiling point of the water with the salt in it will be higher than the boiling point of pure water.
As for the freezing point, in a solution the particles of solute interfere with the attractive forces between the molecules of water avoiding that the solvent passes to solid state at the normal freezing point. Hence, the temperature to freeze will be lower.
Answers
Answer:
Element Symbol Atomic Mass # of Atoms Mass Percent
Lead Pb 207.2 1 46.732%
Explanation:
c. colloids
b. suspensions
d. none of the above
Answers
Colloids have small non-dissolved particles that flow around in the mixture. These particles do not settle over time. When a light is shined on colloids the scattering characteristic of the Tyndall effect are visable.
Answers
The specific heat of liquid ethyl alcohol is 2.42 j/g C and its density of 0.7893 g/ml. The amount of silver used is 12.05 g.
What is specific heat?
Specific heat is defined as the amount of heat needed to raise the temperature of one gram of a substance by one degree Celsius.
It can also be defined as the quantity of heat energy necessary to raise a body's temperature per unit of mass.
Specific heat is expressed as
Q = mcΔT
As per the question
Q silver = Q alcohol
= m silver x Co silver x (T f - T silver) = m alcohol x C p alcohol ( T f -T alcohol)
= m silver x 0.24 x (23.5-95) = 25.6 x 0.7893 x 2.42 x (23.5 - 19.27)
= 25.6 x 0.7893 x 2.42 x (23.5 - 19.27) / (-0.24 x (23.5 - 95)
= 12.5 grams
Thus, the specific heat of liquid ethyl alcohol is 2.42 j/g C and its density of 0.7893 g/ml. The amount of silver used is 12.05 g.
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SOLUTION
25.6 (volume) * 0.7893 (density) = mass of the ethyl alcohol
If it was heated to 19.27 degrees Celsius, this translates to 292.27 Kelvin. The specific heat of liquid ethyl alcohol is 2.42 j/(g*C), which is the same as 2.42 j/(g*K), therefore it has in total 2.42 * 292.27 * 25.6 * 0.7893 Joules of heat.
The silver has x grams, and its specific heat is 0.24 J/g*C = 0.24 J/g*K. If it was heated up to 95 degrees, that means it was heated to 368 degrees Kelvin. Therefore it 368 * 0.24 * x Joules of heat.
If the final temperature was 23.5 degrees Celsius of the entire thing, than the ethyl alcohol had 2.42 * 296.5 * 25.6 * 0.7893 Joules of heat. Getting the difference of the first state and the second state, we get 2.42 * (296.5 - 292.27) * 25.6 * 0.7893 Joules. This was added to the silver, which now has 296.5 * 0.24 * x Joules of heat. Subtracting the first state from the second state we get (296.5-368) * 0.25 * x Joules. The absolute value of this equals 2.42 * (296.5 - 292.27) * 25.6 * 0.7893 Joules. Doing all the math out, 206.84155853 = 17.16x.
Therefore x = 12.05 grams.
There are 12.05 grams of silver.