What are two components that make up force?

Answers

Answer 1

Answer: the answer is mass and acceleration

Answer 2

Answer: gravity and energy hope this helps bro

Related Questions

Contrast the movement of charges in a series circuit and in a parallel circuit.
Which statement represents how charges interact? (2 points)A.Negative charges are attracted to negative charges.B.Neutral charges are attracted to neutral charges.C.Opposite charges are not attracted to each other.D.Positive charges are attracted to negative charges.
Any clue on this one please help
What is the center of atom called??
Question 6 (1 point)Which fundamental force has not been successfully united with the others in aparticle accelerator?- weak nuclear force- electromagnetism - strong nuclear force- gravity

(b) Lorna then built a different circuit as shown below. How could Lorna get both bulbs to light at the same time in this circuit?

Answers

Lorna should close the switches S3 and S4,and leave them closed.
Then, both bulbs are controlled by S5.
When it's closed, they both light. When it's open, they're both off (dark).

The magnitude of the gravitational field on the surface of a particular planet is 2g. The planet’s mass is half the mass of the Earth. What is the planet’s radius in terms of the radius Rg of Earth?

Answers

Final answer:

To find the planet's radius in terms of the radius Rg of Earth, use the equation g = GM/R^2 and substitute 2g for g. Solve for R to get R = sqrt(1/(2gMg)) * Rg.

Explanation:

To find the planet's radius in terms of the radius Rg of Earth, we need to understand the relationship between the gravitational field and the mass and radius of a planet. The magnitude of the gravitational field on the surface of a planet is given by g = GM/R2, where G is the gravitational constant, M is the mass of the planet, and R is its radius. For the planet in question, we are told that the magnitude of the gravitational field is 2g and its mass is half the mass of Earth. Since the gravitational field is 2g, we can substitute g with 2g in the equation and solve for R in terms of Rg:

2g = GM/R2 → 2gR2 = GM → 2gR2 = (GMg)/(2Rg) → R2/Rg = 1/(2gMg) → R = sqrt(1/(2gMg)) * Rg

Learn more about Gravitational field here:

brainly.com/question/36891747

#SPJ12

Final answer:

To find the radius of a planet with a gravitational field twice that of Earth's and half the mass, the radius is calculated to be half of Earth's radius.

Explanation:

The magnitude of the gravitational field strength g on a planet is given by the equation g = G(M/R^2), where G is the universal gravitation constant, M is the planet's mass, and R is the planet's radius. Given that the gravitational field on the surface of the particular planet is 2g where g is Earth's gravitational field, and the planet's mass is half of Earth's mass, we can derive the planet's radius in terms of Earth's radius Rg. Setting up the proportion (G(1/2M_Earth)/(R^2)) / (G(M_Earth)/(Rg^2)) = 2, and simplifying, we find that R^2 = (1/4)Rg^2. Taking the square root of both sides gives us the final relation R = (1/2)Rg.

Learn more about gravitational field strength here:

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Which object below involves two energy transformations when used?a) A radio plugged into an electrical outlet

b) A toaster

c) A battery-operated remote control car

d) A blender

Answers

A battery-operated remote control car

How is Ohm's Law related to house fires?

Answers

I got my bachelor's degree in Electrical Engineering in 1973, and
I have worked with electricity and electronics during the 43 years
since then. Maybe I'm missing something obvious, but I can't think
of any connection between Ohm's Law and house fires. I'm really sorry.

Calculate the density of a sample of gas with a mass of 30 g and volume of 7500 cm3.

Answers

By definition we have that the density is given by:

Where,

M: mass of the sample

V: volume occupied by the sample

Therefore, substituting values in the given equation we have:

$D = 0.004 (g)/(cm^3)$

Answer:

the density of a sample of gas with a mass of 30 g and a volume of 7500 cm3 is:

$D = 0.004 (g)/(cm^3)$

The density of the sample of gas is $\boxed{4*10^(-3)\text{ g}/\text{cm}^3}$ or $\boxed{0.004\text{ g}/\text{cm}^3}$ .

Further Explanation:

Density of any kind of matter is defined as the total mass of that substance present in the volume occupied by it in the region of space.

Example (1) : If we consider equal amounts of tungsten and iron, then tungsten is heavier than iron because tungsten occupies lesser volume or lesser empty spaces inside it for a particular mass as compared to iron. Therefore, tungsten has density higher than that of iron.

Example (2): If we take 2 cubes of similar size (same volume) of tungsten and gold then the cube of gold will be heavier because its density is more than that of tungsten.

Given:

The mass of the sampleof the gas is $30\text{ g}$ .

The volume of the sample of the gas is $7500\text{ cm}^3$ .

Concept:

The density of the substance is defined as the ratio of the mass and volume.

$\boxed{\rho=(m)/(V)}$ ......(1)

Here, $\rho$ is the density of the sample ofthe gas, $m$ is the mass of the sample of the gas and $V$ is the volume occupied by the gas.

Substitute the value of $m$ and $V$ in equation (1).

$\begin{aligned}\rho&=\frac{30\text{ g}}{7500\text{ cm}^3}\n&=4*10^(-3)\text{ g}/\text{cm}^3\end{aligned}$

Thus, the density of the sample of gas is $\boxed{4*10^(-3)\text{ g}/\text{cm}^3}$ or $\boxed{0.004\text{ g}/\text{cm}^3}$ .

Learn More:

1. Wind and solar energy are the examples of brainly.com/question/1062501

2. Which of the following is not a component of a lever brainly.com/question/1073452

3. A 30kg block being pulled on a carpeted floor brainly.com/question/7031524

Answer Details:

Grade: middle school

Subject: Physics

Chapter: Matter

Keywords:

Density, sample of gas, 30g gas, volume, 7500 cm3, 7500 cm^3, mass, matter, volume occupied, sample, ratio,grams per centimeter cube

Will a cart rolling up and down a ramp have a faster or slower acceleration than a ball being thrown straight up into the air? (Assume up the ramp is positive and the origin is the starting point of the cart)

Answers

a ball being thrown straight up would excel faster.

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