A wagon is pulled at a speed of 0.40 m/s by a horse exerting 1800 Newtons of horizontal Force. how much work was done by the horse

Answers

Answer 1
Answer:

The amount of work done per second by the horse exerting a force of 1800 N on a wagon moving with a speed of 0.4 m/s  is 720 J/s.

What is power?

Power is the workdone by a body in one second.

To calculate the work done by the horse in one seconds, we use the formula below

Formula:

  • P = Fv................ Equation 1

Where:

  • P = work done on the horse in one second
  • F = Force of the horse
  • v = Velocity of the wagon

From the question,

Given:

  • F = 1800 N
  • v = 0.4 m/s

Substitute these values into equation 1

  • P = 1800×0.4
  • P = 720 J/s

Hence, the amount of work done per second by the horse is 720 J/s.

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Complete question: A wagon is pulled at a speed of 0.40 m/s by a horse exerting 1800 Newtons of horizontal Force. how much work was done by the horse per second.


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Answers

Answer:

2.31 Ω

Explanation:

According to the Faraday's law of electromagnetic induction,

Induced emf = - N (dΦ/dt)

Emf = -N (ΔΦ/t)

where N = number of turns = 11

Φ = magnetic flux

ΔΦ = change in magnetic flux = 9.69 - 5.60 = 4.09 Wb

t = time taken for the change = 0.0657 s

Emf = 11(4.09/0.0657)

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Emf = IR

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R = 2.31 Ω

Hope this Helps!!

Explanation:

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Answers

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Answers

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Also the sun of upward forces must be equal to the sun of downward forces.

Theses are the conditions for static equilibrium.

Explanation:

The step by step solution can be found in the attachment below.

Thank you for reading this solution and I hope it is helpful to you.

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