9. In the graph below, what is the force being exerted onthe 16-kg cart?
A. 4N
C. 16N
B. 8N
D. 32 N

Answers

Answer 1

Answer:

Final answer:

The force being exerted on the 16-kg cart is 32N.

Explanation:

The force being exerted on the 16-kg cart can be determined using Newton's second law of motion, which states that force is equal to mass multiplied by acceleration. In the given graph, the cart is accelerating at a rate of 2 m/s2. Therefore, the force can be calculated as:

force = mass x acceleration

force = 16 kg x 2 m/s2 = 32 N

The 16-kg cart experiences a force of 32N, determined by applying Newton's second law of motion. According to this law, force equals mass multiplied by acceleration. In this scenario, the cart accelerates at a rate of 2 m/s². Substituting the values into the equation, the force exerted on the cart can be calculated as 16 kg multiplied by 2 m/s², resulting in a force of 32 N. This fundamental principle in physics establishes a quantitative relationship between force, mass, and acceleration.

Learn more about Newton's second law of motion

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Answer 2

Answer:

Answer:

Explanation:

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A 50n brick is suspended by a light string from a 30kg pulley which may be considered a solid disk with radius 2.0m. the brick is released from rest and falls to the floor below as the pulley rotates. it takes 4 seconds for the brick to hit the floor. i) what is the tension in newtons in the string well the brick is falling? ii) what is the magnitude of the angular momentum in kg*m^2/s of the pulley at the instant the brick hits the floor?

Answers

Brick is held at a position which is at height 2 m from the floor

Now it is released from rest and hit the floor after t = 4 s

Now the acceleration of the brick is given by

$y = v_i* t + 0.5 at^2$

$2 = 0 + 0.5 * a * 4^2$

$a = 0.25 m/s^2$

Now in order to find the tension in the string

we can use Newton's law

$F_(net) = ma$

$mg - T = ma$

$50 - T = (50)/(9.8)*0.25$

$T = 48.72 N$

part b)

Now for the pulley

moment of inertia= $(1)/(2)mr^2$

m = 30 kg

R = 2 m

I = $(1)/(2)*30*2^2$

I = 60 kg m^2

Now the angular speed just before brick collide with the floor

$w = (v)/(r)[\tex]</p><p>here we have</p><p>[tex]v = v_i + a* t$

$v = 0 + 0.25 * 4$

v = 1 m/s

Now we will have

L = angular momentum = I w = $I*(v)/(R)$

L = 60 * $(1)/(2)$

L = 30 kg m^2/s

In the study of sound, one version of the law of tensions is:f1= f2 √ (F1/F2)

If f1= 300, F2= 60, and f2=260, find f1 to the nearest unit.

Answers

Answer:

F1 = 80

Explanation:

f1= f2 √ (F1/F2)

Where f1 = 300, f2 = 260 and F2 = 60

Putting in the above formula

300 = 260√(F1/60)

Dividing both sides by 260

=> 1.15 = √(F1/60)

Squaring both sides

=> 1.33 = F1/60

Multiplying both sides by 60

=> F1 = 80

The aorta pumps blood away from the heart at about 40 cm/s and has a radius of about 1.0 cm. It then branches into many capillaries, each with a radius of about 5 x 10−4 cm carrying blood at a speed of 0.10 cm/s.How many capillaries are there?

Answers

Answer:

n = 1.6*10^9 capillaries

Explanation:

In order to calculate the number of capillaries, you take into account that the following relation must be accomplished:

$A_1v_1=nA_2v_2$ (1)

A1: area of the aorta

v1: speed of the blood in the aorta = 40cm/s

n: number of capillaries = ?

A2: area of each capillary

v2: speed of the blood in each capillary

For the calculation of A1 and A2 you use the formula for the cross sectional area of a cylinder, that is, the area of a circle:

$A=\pi r^2\n\nA_1=\pi r_1^2=\pi(1.0cm)^2=3.1415 cm^2\n\nA_2=\pi r_2^2=\pi (5*10^(-4)cm)^2=7.85*10^(-7)cm^2$

Where you have used the values of the radius for the aorta and the capillaries.

Next, you solve the equation (1) for n, and replace the values of all parameters:

$n=(A_1v_1)/(A_2v_2)=((3.1415cm^2)(40cm/s))/((7.85*10^(-7)cm^2)(0.10cm/s))=1.6*10^9$

Then, the number of capillaries is 1.6*10^9

A electromagnetic wave of light has a wavelength of 500 nm. What is the energy (in Joules) of the photon representing the particle interpretation of this light?

Answers

Answer:

Energy, $E=4.002* 10^(-19)\ J$

Explanation:

It is given that,

Wavelength of the photon, $\lambda=500\ nm=5* 10^(-7)\ m$

We need to find the photon representing the particle interpretation of this light. it is given by :

$E=(hc)/(\lambda)$

$E=(6.67* 10^(-34)* 3* 10^8)/(5* 10^(-7))$

$E=4.002* 10^(-19)\ J$

So, the energy of the photon is $4.002* 10^(-19)\ J$ . Hence, this is the required solution.

At a stop light, a truck traveling at 10.5 m/s passes a car as it starts from rest. The truck travels at constant velocity and the car accelerates at 3 m/s2. How much time does the car take to catch up to the truck?

Answers

Answer:

t = 7 sec.

Explanation:

As the car and the truck travel the same distance, assuming a constant acceleration, we can describe the movement of the truck and the car with these equations for this same displacement:

x(truck) = v*t (1)

x(car) = $(1)/(2)*a*t^(2) (2)$

As the left sides of (1) and (2) are equal each other, the same must be true for the right sides:

v*t = $(1)/(2)*a*t^(2)$

Solving for t, replacing v= 10.5 m/s and a= 3 m/s², we have:

$t = (2*v)/(a) = (2*10.5 m/s)/(3 m/s2) = 7 sec.$

⇒ t = 7 sec.

If you want to play a tune on wine glasses, you’ll need to adjust the oscillation frequencies by adding water to the glasses. This changes the mass that oscillates (more water means more mass) but not the restoring force, which is determined by the stiffness of the glass itself. If you need to raise the frequency of a par- ticular glass, should you add water or remove water?