Kendra hasn’t missed a day of school in 245 days. This is twenty days less than five times the number of days it has been since Brandon has missed a day of school. How many days has it been since Brandon missed a day of school?

Answers

Answer 1

Answer: The equation would be 5x+20=245
X=the number of days Brandon missed.
Subtract 20 from both sides; 5x=225
Then divide by 5; x=45
It has been 45 days since Brandon missed school.

Answer 2

Answer:

Answer:

The answer is 53

245 = 5y - 20 | y = 53

Step-by-step explanation:

subtracting 20 ( - 20) represents "twenty days less"

5y represents "five times the number of days"

This is all being compared to Kendra's 245 days of perfect attendance which is why it's "245 ="

Plug it in! & don't forget PEMDAS ----> 5(53) - 20 = 245

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The chart below shows the number of cakes Jenny bakes each month.What is the mean number of cakes Jenny bakes in a month?

Answers

Since you didn't put any chart above, then I'll just give an idea on how to find the mean. You simply compute for the sum of the cakes Jenny bakes each month. Then, you proceed to dividing the number of cakes by the number of months indicated in the chart. You should have the mean by now.

Answer: 480

Step-by-step explanation:

460 was in August

320 was in September

440 was in October

560was in November

620 was in December

Add all together: 460+320+440+560+620=2400

2400:5(five months)=480

Andrew is looking into prices for cable for his new home. He received the following breakdown for monthly prices.Basic Cable: $35.99
Cable boxes: $3.49 per cable box
HD Service: $9.99 per cable box
DVR: $14.99 per cable box
Installation Fee: $120.00 (one-time fee)

The total cost for 12 months of cable service with b cable boxes is represented by the expression below.
$551.88 + $341.64b

Which statement best describes the coefficient of "B"?

A. It is the cost for basic cable for one month and the installation fee.

B. It is the cost for basic cable for one year and the installation fee.

C. It is the cost for one cable box with DVR and HD service for one month.

D. It is the cost for one cable box with DVR and HD service for one year.

Answers

Given:

551.88 + 341.64b

The coefficient of "B" is 341.64, the best statement that applies to it is:

D. It is the cost for one cable box with DVR and HD service for one year.

Cable boxes: $ 3.49 per cable box
HD Service: $ 9.99 per cable box
DVR: $ 14.99 per cable box
Total : $ 28.47
multiply 12 months
Annual cost $341.64

The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain?{5, 8}
{-5, -8}
{3, 8}
{4, 7}
{4, 8}

Answers

Answer:

Hence, the domain of the function is:

{4,7}

Step-by-step explanation:

We are given the range of the function:

$f(k)=k^2+2k+1$ as {25,16}

The function f(k) could also be written as:

$f(k)=k^2+2k+1=k^2+k+k+1\n\nf(k)=k(k+1)+1(k+1)\n\nf(k)=(k+1)(k+1)\n\nf(k)=(k+1)^2$

The range is the value of the function at some k.

if f(k)=25 then we have to find the value of k.

$f(k)=25=5^2=(k+1)^2$

on taking square root on both side we have:

$k+1=5\n\nk=5-1\n\nk=4$

if f(k)=64 then we have to find the value of k.

$f(k)=64=8^2=(k+1)^2$

on taking square root on both side we have:

$k+1=8\n\nk=8-1\n\nk=7$

Hence, the domain of the function is:

{4,7}

The domain of a function contains the x-values of the function while the range of the function contains the y-values of the function. In this case, we substitute 25 and 64 to y. Then,
25 = k2 + 2 k + 1 (k-4) * (k+6) = 0
64 = k2 + 2 k + 1 (k-7) * (k+9) = 0
hence the domain is {-9,-6, 4,7}

What single decimal multiplier would you use to increase by 4% followed by a 3% increase

Answers

Answer:

1.0712

Step-by-step explanation:

if you increase by 4%, it means you will have a new total of 104%. In decimals it is 1.04 (divide your percentage by 100) after that you do the same with the 3% increase. you'll have a new total of 103%. In decimals 1.03. If you want to know what single multiplier you can use, you need to multiply the both decimals. So you get 1.04 x 1.03 = 1.0712

hope this will help you, have a nice day!

If any two sides and any angle are congruent in two triangles, then the triangles must be congruent. is it true or false?

Answers

Answer:

FALSE

Step-by-step explanation:

To Find: True or False

If any two sides and any angle are congruent in two triangles, then the triangles must be congruent.

It is not always true according to rule of congruence. If two sides are equal then angle between them must be equal for SAS property.

It is false

Total possible congruence for two sides and one angle : SSA , A-SS, SAS

Only three possible property.

SAS is only true for concurrency of triangle.

SSA and A-SS are false for any two side and any one angle.

Please find the attachment for difference in three property.

Hence, The given statement is false.

Well, It is False. The sides must form the angle, i.e. /_ <- the angle formed, and the two sides must be in this position. its the ASA postulate.

I hope this helps!

Throughout this activity, the scale factor, n, has been a positive value. However, a scale factor for dilations can also be negative. When a set of coordinates on a preimage is multiplied by -n instead of n, the coordinates of the image rotate about the center of dilation by 180°. Consider all the potential intervals of n in the table. Enter information in the table to indicate whether the scale factor produces an enlargement, a reduction, or no size change. Also indicate whether the image rotates 180° about the center of dilation. The first one has been done for you.

Answers

Answer:

Step-by-step explanation:

Answer:

Interval Enlargement, reduction, or no size change? Does the image rotate 180° about the center of dilation?

0 < n < 1 reduction no

n = 1 no size change no

n > 1 enlargement no

-1 < n < 0 reduction yes

n = -1 no size change yes

n < -1 enlargement yes

Step-by-step explanation:

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