ENGINEERING COLLEGE

Make a python code.Write a function named max that accepts two integer values as arguments and returns the value that is the greater of the two. For example, if 7 and 12 are passed as arguments to the function, the function should return 12. Use the function in a program that prompts the user to enter two integer values. The program should display the value that is the greater of the two. Write the program as a loop that continues to prompt for two numbers, outputs the maximum, and then goes back and prompts again
Here’s an example of program use
Input the first number: 10
Input the second number: 5
The maximum value is 10
Run again? yes
Input the first number: -10
Input the second number: -5
The maximum value is -5
Run again? no
Function max():
Obtain two numbers as input parameters: max(num1, num2):
if num1 > num2 max_val = num1, else max_val = num2
return max_val
Main Program:
Initialize loop control variable (continue = ‘y’)
While continue == ‘y’
Prompt for first number
Prompt for second number
Call function "max," sending it the values of the two numbers, capture result in an assignment statement:
max_value = max (n1, n2)
Display the maximum value returned by the function
print(‘Max =’, max_val)
Ask user for if she/he wants to continue (continue = input(‘Go again? y if yes’)

Answers

Answer 1

Answer:

A loop is a control structure in programming that allows a block of code to be executed repeatedly.

How to write the python code?

Here is the Python code that implements the function and program described in the question:

def max(num1, num2):

if num1 > num2:

max_val = num1

else:

max_val = num2

return max_val

# Main program

continue = 'y'

while continue == 'y':

n1 = int(input("Input the first number: "))

n2 = int(input("Input the second number: "))

max_val = max(n1, n2)

print("The maximum value is", max_val)

continue = input("Run again? ")

Loops are an important programming construct that allow you to perform the same task multiple times with minimal code. They are often used to process data, perform calculations, and perform repetitive tasks.

To Know More About Loops, Check Out

brainly.com/question/29313454

#SPJ4

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Answers

Answer:

......................

Explanation:

The cost of hiring new employees outpaces the raises for established employees is A.
Salary compression

B.
Occupational based pay

C.
Merit pay

D.
Need for Achievement

Answers

Answer:

do you have to make the right decisions to be a person who has been a member who is not the first time a great person who has a job in a day of his life or

Calculate the angle of banking on a bend of 100m radius so that vehicles can travel round the bend at 50km/hr without side thrust on the tyres.

Answers

Answer:

11.125°

Explanation:

Given:

Radius of bend, R = 100 m

Speed around the bend = 50 Km/hr = $(5)/(18)*50$ = 13.89 m/s

Now,

We have the relation

$\tan\theta=(v^2)/(gR)$

where,

θ = angle of banking

g is the acceleration due to gravity

on substituting the respective values, we get

$\tan\theta=(13.89^2)/(9.81*100)$

$\tan\theta=0.1966$

θ = 11.125°

or a bronze alloy, the stress at which plastic deformation begins is 267 MPa and the modulus of elasticity is 115 GPa. (a) What is the maximum load (in N) that may be applied to a specimen having a cross-sectional area of 164 mm2 without plastic deformation

Answers

Answer:

The maximum load (in N) that may be applied to a specimen with this cross sectional area is $F=43788 N$

Explanation:

We know that the stress at which plastic deformation begins is 267 MPa.

We are going to assume that the stress is homogeneously distributed. As a definition, we know that stress (P) is force (F) over area(A), as follows:

$P=(F)/(A)$ (equation 1)

We need to find the maximum load (or force) that may be applied before plastic deformation. And the problem says that the maximum stress before plastic deformation is 267 MPa. So, we need to find the value of load when P= 267 MPa.

Before apply the equation, we need to convert the units of area in $m^(2)$ . So,

$A[m^(2)]=A[mm^(2) ]((1 m)/(1000 mm)) ^(2)\nA[m^(2)]=164 mm^(2)((1 m)/(1000 mm))^(2) \nA[m^(2)]=0.000164 m^(2)$

And then, from the equation 1,

$F=PA\nF=(267 MPa)(0.000164 m^(2))\nF=(267x10^(6) Pa)(0.000164 m^(2))\nF=(267x10^(6) N/m^(2))(0.000164 m^(2))\nF=43788 N$

Whats are the best choice of cooling towers for electeic generating power plant and why?

Answers

Answer:

Cooling tower using the "Induced draft tower" mode of operation.

Explanation:

Electric generating power plant generates a lot of steam and heat. On the efficiency aspect of the cooling tower with respect to the operation of the power plant, a cooling tower with its fan at the end of the airstream leaving the tower is best applied considering the pressure of steam coming out of the turbine. On the maintenance angle, it is easier to maintain.

A 78-percent efficient 12-hp pump is pumping water from a lake to a nearby pool at a rate of 1.5 ft3/s through a constant-diameter pipe. The free surface of the pool is 32 ft above that of the lake. Determine the irreversible head loss of the piping system, in ft, and the mechanical power used to overcome it. Take the density of water to be 62.4 lbm/ft3.