CHEMISTRY HIGH SCHOOL

Propane (C3H8) reacts with oxygen gas to produce carbon dioxide & water. How many grams of oxygen are needed to oxidize 12.5g of propane (C3H8)? a) 1.8

b) 22.7

c) 55.6

d) 31.8

e) 45.5

Answers

Answer 1
Answer:

The amount of oxygen needed to oxidize 12.5g of propane is 45.5g.

What is stoichiometry in chemistry?

Stoichiometry is the calculation of the quantitative relationships between the amounts of reactants and products in chemical reactions.

The balanced chemical equation for the combustion of propane is:

C3H8 + 5O2 → 3CO2 + 4H2O

To calculate the amount of oxygen needed to react with 12.5g of propane, we need to use stoichiometry and the molar mass of propane. The molar mass of propane is 44.1 g/mol.

First, we need to convert the mass of propane to moles:

12.5 g C3H8 × (1 mol C3H8 / 44.1 g C3H8) = 0.283 mol C3H8

According to the balanced equation, 5 moles of oxygen are required to react with 1 mole of propane. So, we can calculate the amount of oxygen needed as follows:

0.283 mol C3H8 × (5 mol O2 / 1 mol C3H8) = 1.415 mol O2

Finally, we can convert the moles of oxygen to grams using the molar mass of oxygen, which is 32.0 g/mol:

1.415 mol O2 × 32.0 g O2/mol = 45.1 g O2

Therefore, the answer is e) 45.5 g of oxygen is needed to oxidize 12.5g of propane (C3H8).

Learn more about Stoichiometry here:

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Answers

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Answer:

use a scale and record the weight in N.

Explanation:

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B. remain in the negatively charged body.
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Answers

I think the correct answer is A. If one body is positively charged and another body is negatively charged, free electrons tend to move from the negatively charged body to the positively charged body. This happens because they have different charges and therefore electrons are more attracted to the positive or its opposite charge.

Answer:

A. move from the negatively charged body to the positively charged body.

Explanation:

because this is the correct answer

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