Hypervitaminosis is a serious health threat associated with excessive amounts of ingested fat-soluble vitamins. why do water-soluble vitamins not commonly pose the same threat?

Answers

Answer 1

Answer:

Answer:

Hypervitaminosis is a serious health issue which is associated with the accumulation of the vitamins in the body. This problem is mainly associated with the fat soluble vitamins.

This is because the fat soluble vitamins gets accumulated in the fatty cells of the body. Whereas, in case of water soluble vitamins it gets dissolved in water and gets eliminated from the body.

So, there is very rare chance that the water soluble vitamin not cause hypervitaminosis.

Answer 2

Answer:

Final answer:

Hypervitaminosis does not typically occur with water-soluble vitamins because excess amounts are excreted in urine rather than stored in the body, preventing a harmful build-up that could lead to toxicity.

Explanation:

Hypervitaminosis is indeed a health threat associated with excessive intake of fat-soluble vitamins, but water-soluble vitamins do not typically pose this risk because of how our bodies process them. Fat-soluble vitamins, which include vitamins A, D, E, and K, can be stored in our bodies, specifically in our liver and fat tissues. Therefore, consuming them in excessive amounts can lead to accumulation, resulting in toxic effects known as hypervitaminosis.

On the other hand, water-soluble vitamins, which include vitamins B and C, cannot be stored in the body for a long duration. Any excess intake of these vitamins is typically excreted in urine, preventing a harmful build-up in the body, thus reducing the risk of hypervitaminosis.

Learn more about Vitamin intake here:

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PLEASE HELP!! Perform the following
mathematical operation, and
report the answer to the
appropriate number of
significant figures.
5.1 – 2.3685 = [?]

Answers

Answer: 2.7 is the real answer if you follow the right rules!

Answer:

$5.1 - 2.3685 = 2.7315 \n$

The acid-dissociation constant, Ka, for benzoic acid is 6.5 × 10-5. Which will you use to calculate the base-dissociation constant, Kb, for the conjugate base of benzoic acid?

Answers

Answer:

The base-dissociation constant, Kb,for the conjugate base of benzoic acid is :

$K_(b)=1.54* 10^(-10)}$

Explanation:

The product of acid dissociation constant and base dissociation constant is equal to the water dissociation constant.The general formula for the reaction is:

$K_(w)=K_(a)K_(b)$

For the acid dissociation reaction:

$HA + H_(2)O\rightleftharpoons H^(+)+A^(-)$

The conjugate base for the acid is A-

The acid is HA . and its Ka is given.

The value of Kw is fixed at a given temperature , which is equal to:

$K_(w)=10^(-14)$

$K_(a)=6.5* 10^(-5)$

$K_(b)=(10^(-14))/(6.5* 10^(-5))$

$K_(b)=1.54* 10^(-10)}$

Answer:

Ka*kb=kw

Explanation:Got it right

Which describes the relationship between [H+] and [OH−] ?

Answers

There are quite a fewrelationships between [H+] and [OH−]ions. And because there is a large range of number between 10 to 10-15M, the pH is used. pH = -log[H+] and pOH = -log[OH−]. In aqueous solutions, [H+][OH- ] = 10-14. From here we can derive the values of each concentration.

-log[H+ ] + -log[OH- ] = -log[10-14]
pH + pOH = 14
So pH = 14 – pOH and pOH = 14 –pH

A neutral solution occurs when pH= pOH = 7. It is an acid solution when [H+ ] > [OH- ], pH < 7 and basic when [H+ ] < [OH- ], pH> 7.

H+ is for an acid, which has a pH of 1-7. OH- is for a base, called hydroxide, and has a pH of 7-14.

pH 7 is neutral.

We can also use the equation for enthalpy change for physical phase changes. Consider the phase change H2O(l) → H2O(g). Calculate ΔHrxn.Use ΔHf values from the table above.

ΔHrxn = _____

Answers

Answer: The value of enthalpy of the given reaction is 44.000 kJ/mol , that is energy is supplied to water to change into water vapors

Explanation:

$H_2O(l)\rightarrow H_2O(g),\Delta H_(rxn)=?$

Enthalpy of formation of water in liquid state, $\Delta H_(f,H_2O(l))=-285.820 kJ/mol$

Enthalpy of formation of water in gaseous state, $\Delta H_(f,H_2O(g))=-241.820 kJ/mol$

$\Delta H_(rxn)=\sum \Delta H_f \text{of products}-\sum \Delta H_f \text{of reactants}$

$\Delta H_(rxn)=(-241.820 kJ/mol)-(-285.820 kJ/mol)=44.000 kJ/mol$

The value of enthalpy of the given reaction is 44.000 kJ/mol, that is energy is supplied to water to change into water vapors.

Standard molar enthalpy:
H2O ( liquid water ) : - 285.8 KJ/mole
H2O ( water vapor ) : - 241.8 KJ / mole.
ΔHrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0
Answer: B ) 44.0 KJ

If salt is dissolved in water, water serves as the:a. solute.
b. solvent.
c. dissolved medium.
d. none of the above

Answers

b. solvent

solute is the substance being dissolved

Which element (Na or Cl) is more likely to steal an outer electron from the other?

Answers

Answer:

Cl is more likely to than Na

Explanation:

The question asks for the element more take up an electron from the other

The ability of an atom to take take or give electrons in a chemical reaction, depends on its electron affinity and ionization energy, respectively

Chlorine, Cl, has the highest electron affinity in the periodic table which makes it attract electrons more towards itself

Sodium, Na, has a low ionization energy (about 2/5 of that of chlorine) than chlorine, Cl, making sodium more readily able to give its valence electron in a reaction

Therefore, Cl is more likely to take up an outer electron from Na.

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