The ending time is 10:08 and the elapsed time is 30 minutes what is the starting tome

Answers

Answer 1

Answer: Wouldn't you just count back 30 minutes from 10:08?
If you round up to 10:10, it's a little easier. Picture an analog clock in your head. Every big number is five minutes, and every two is ten minutes. If we put it back to the 12, that's ten minutes back. Twenty minutes earlier from that would be 9:40. Since we added two minutes to make it easier, we've got to subtract those two minutes. So, the starting time would be 9:38.
I hope this isn't too confusing.

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Which quadratic function has a leading coefficient of 2 and a constant term of –3? f(x) = 2x3 – 3 f(x) = –3x2 – 3x 2 f(x) = –3x3 2 f(x) = 2x2 3x – 3
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Which of the following is equivalent to 6x 2 + x - 12 ?A. (2x + 3)(3x - 4)
B. (2x - 3)(3x - 4)
C. (2x + 3)(3x + 4)
D. (6x + 3)(x - 12)
E. (x + 3)(2x - 12)
Please show me step by step how to solve this problem
Thanks

Answers

$6x^2+x-12=6x^2-9x+8x-12=3x(2x-3)+4(2x-3)\n\n=(2x-3)(3x+4)\n\nother\ method:\n\n6x^2+x-12\na=6;\ b=1;\ c=-12\n\Delta=b^2-4ac\to\Delta=1^2-4\cdot6\cdot(-12)=1+288=289\n\nx_1=(-b-\sqrt\Delta)/(2a);\ x_2=(-b+\sqrt\Delta)/(2a)\n\n\sqrt\Delta=√(289)=17$

$x_1=(-1-17)/(2\cdot6)=(-18)/(12)=-(3)/(2);\ x_2=(-1+17)/(2\cdot6)=(16)/(12)=(4)/(3)\n\n6x^2+x-12=6(x+(3)/(2))(x-(4)/(3))=2\cdot3(x+(3)/(2))(x-(4)/(3))\n\n=2(x+(3)/(2))\cdot3(x-(4)/(3))=(2x+3)(3x-4)$

Factor completely 6x^4y^3 + 21x^3y^2 − 9x^2y.3xy(2x^3y^2 + 7xy − 3x)
3x^2y(2x^2y^2 + 7xy − 3)
3x^2y3&(2x^2 + 7xy − 3)
3x^2y(2x^2y + 7xy − 3y)

Answers

Asking the Math Gods

=3x^2y(2x^2y^2+7xy-3)

Final answer:

The simplest factored form of the expression 6x^4y^3 + 21x^3y^2 − 9x^2y is 3x^2y(2x^2y^2 + 7xy - 3), derived by taking the greatest common factor (GCF) out from each term.

Explanation:

The task here is to completely factor the polynomial 6x^4y^3 + 21x^3y^2 − 9x^2y. Initially, you look for the greatest common factor (GCF) in the terms. In this case, the GCF is 3x^2y. So we factor that out from each term:

3x^2y(2x^2y^2 + 7xy - 3)

The factored form of the original expression is therefore 3x^2y(2x^2y^2 + 7xy - 3). This result represents the simplest factored form of the expression.

Learn more about Factoring Polynomials here:

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The steps below show the incomplete solution to find the value of x for the equation 5x – 3x – 5 = –3 + 23:Step 1: 5x – 3x – 5 = –3 + 23
Step 2: 5x – 3x – 5 = 20
Step 3: 2x – 5 = 20

Which of these is most likely the next step?

Answers

Maybe step 3 because you try to get rid of the x on both sides

Bugs Bunny wanted to buy some new signs to use to trick Daffy Duck. Each sign costs $12, and tax is only 6% in Looney Tune Land. How much would Bugs pay for three signs with tax?(Please show work too :) )

Answers

Answer:

$38.16

Step-by-step explanation:

12*3=36

36*0.06=2.16

36+2.16=38.16

Hope this helps! :)

Exponential functions exhibit exponential growth (or decay). What does this mean to the graphs of these functions? a.. the graph will rise or fall more dramatically than a polynomial graph. c.. the graphs represent the population of bacteria in your mouth. b.. the graph is three dimensional. d.. the exponent in the equation is less than one

Answers

Answer:

The correct option is:

Option: a

a. the graph will rise or fall more dramatically than a polynomial graph.

Step-by-step explanation:

The most basic exponential function is a function of the form

y=b^x

where b is a positive number.

When b>1

the function grows in a manner that is proportional to its original value. This is called exponential growth.

When 0>b>1

the function decays in a manner that is proportional to its original value. This is called exponential decay.

The graph of a exponential function increases or decreases rapidly as compared to a graph of a polynomial function.

Hence, option a is the correct answer.

a tree casts a shadow that is 20 ft long. the angle of elevation of the sun is 29°. how tall is the tree?

Answers

You can use the trig ratios. Draw a diagram to see which one is appropriate.
Tan would be used.
Tan29=x/20
20Tan29=x
Put this into your calculator and see what you get

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