Compare and contrast, in detail, at least two types of pluralism. Do you think the United States is becoming more pluralistic? Why or why not? How do ethnic enclaves relate to pluralism in the US?

Answers

Answer 1

Answer:

a. There are two main types of pluralism: cultural and political

b. Yes, the United States is becoming more pluralistic

c. Ethnic enclaves can be both a positive and negative aspect of pluralism in the US.

a. Pluralism refers to the coexistence of multiple cultures, religions, and ethnicities within a society. There are two main types of pluralism: cultural and political. Cultural pluralism emphasizes the preservation of distinct cultural traditions, while political pluralism emphasizes the equal representation of different groups within the political system.

Cultural pluralism is often associated with the idea of multiculturalism, which recognizes and celebrates the diversity of different cultures. This type of pluralism acknowledges the importance of cultural differences and encourages individuals to maintain and express their cultural identities. In contrast, political pluralism emphasizes the importance of equal representation of different groups within the political system. This can take the form of proportional representation in government or equal access to political power for different groups.

b. The United States is becoming more pluralistic, as the population becomes more diverse and the importance of multiculturalism and political pluralism is increasingly recognized. The country is home to many different ethnic and cultural groups, and these groups are increasingly visible in politics and society. This is evident in the increasing number of ethnic and cultural enclaves, which are areas where different ethnic groups live in close proximity to one another.

c. Ethnic enclaves can be both a positive and negative aspect of pluralism in the US. On the one hand, they allow individuals to maintain their cultural traditions and create supportive communities. On the other hand, they can also lead to segregation and exclusion, as different groups may be reluctant to interact with one another. In order to promote a positive form of pluralism, it is important to encourage interaction and understanding between different groups, while also respecting and celebrating their distinct cultural identities.

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Two charged metallic spheres of radii, R = 10 cms and R2 = 20 cms are touching each other. If the charge on each sphere is +100 nC, what is the electric potential energy between the two charged spheres?

Answers

Answer:

$200* 10^(-6)j$

Explanation:

We have given the radius of first sphere is 10 cm and radius of second sphere is 20 cm

So the potential of first sphere will be greater than the potential of the second sphere, so charge will flow from first sphere to second sphere

Let q charge is flow from first sphere to second sphere and then potential become same

So $V=(K(100-q))/(r_1)=(K* 100)/(r_2)$

200-100=2q+q

$q=(100)/(3)=33.33nC$

So $V=(K(100-q))/(r_1)=(9* 10^(9)* (100-33.33)* 10^(-9))/(10* 10^(-2))=6003V$

We know that potential energy U=qV $=33.33* 10^(-9)* 6003=200* 10^(-6)j$

Answer:

The electric potential energy between the two charged spheres is $199.9*10^(-6)\ J$

Explanation:

Given that,

Radius of first sphere $R_(1)=10\ cm$

Radius of second sphere $R_(2)=10\ cm$

Charge Q= 100 nC

We know charge flows through higher potential to lower potential.

Using formula of potential

$V=(k(Q-q))/(R_(1))$ ...(I)

$V=(k(Q+q))/(R_(2))$ ...(II)

From equation (I) and (II)

$(k(Q-q))/(R_(1))=(k(Q+q))/(R_(2))$

Put the value into the formula

$((100-q))/(10*10^(2))=((100+q))/(20*10^(-2))$

$(100-q)*20*10^(-2)=(100+q)*10*10^(-2)$

$q=(1000)/(30)$

$q=(100)/(3)$

$q=33.33\ nC$

So, the potential at R₁ and R₂

Using formula of potential

$V=(k(Q-q))/(R_(1))$

Put the value into the formula

$V=(9*10^(9)(100-33.33)*10^(-9))/(10*10^(-2))$

$V=6000.3\ Volt$

We need to calculate the electric potential energy between the two charged spheres

Using formula of the electric potential energy

$U=qV$

$U=33.33*10^(-9)*6.0003*10^(3)$

$U=199.9*10^(-6)\ J$

Hence, The electric potential energy between the two charged spheres is $199.9*10^(-6)\ J$

Suppose that we are designing a cardiac pacemaker circuit. The circuit is required to deliver pulses of 1ms duration to the heart, which can be modeled as a 500 ohm resistance. The peak amplitude of the pulses is required to be 5 V. However, the battery delivers only 2.5 V. Therefore, we decide to charge two equal value capacitors in parallel from the 2.5V battery and then switch the capacitors in series with the heart during the 1ms pulse. What is the minimum value of the capacitances required so the output pulse amplitude remains between 4.9 V and 5.0 V throughout its 1ms duration

Answers

Answer:

Minimum capacitance = 200 μF

Explanation:

From image B attached, we can calculate the current flowing through the capacitors.

Thus;

Since V=IR; I = V/R = 5/500 = 0.01 A

Maximum charge in voltage is from 5V to 4.9V. Thus, each capacitor will have 2.5V. Hence, change in voltage(Δv) for each capacitor will be ; Δv = 0.05 V

So minimum capacitance will be determined from;

i(t) = C(dv/dt)

So, C = i(t)(Δt/Δv) = 0.01[0.001/0.05]

C = 0.01 x 0.0002 = 200 x 10^(-6) F = 200 μF

The graph to the right shows the change in Canada‘s harvest of Atlantic cod from 1950-2004 what year shows the clearest evidence of a collapse of fishing stocks?A.1965
B.1985
C.1995
D.2005

Answers

The correct answer is C. 1995

Explanation:

The graph shows the changes in the harvest of Atlantic cod. In general, this graph illustrates how the peak occurred in the 1980s but then there was a sudden and sharp decline in 1995. Indeed, 1995 is the year with the lowest number of harvested cod as in this year there were approximately least than 10 thousand metric tonnes of cods. Also, this year shows the collapse of fishing stocks or that the population of this fish collapsed, which made it impossible to harvest as many fish as in previous years. According to this, the year that shows the collapse of fishing stocks is 1995.

a painting in an art gallery has height h and is hung so that its lower edge is a distance d above the eye of an observer. How far from the wall should the observer stand to get the best view?

Answers

Solution:

With reference to Fig. 1

Let 'x' be the distance from the wall

Then for $\Delta$ DAC:

$tan\theta = (d)/(x)$

⇒ $\theta = tan^(-1) (d)/(x)$

Now for the $\Delta$ BAC:

$tan\theta = (d + h)/(x)$

⇒ $\theta = tan^(-1) (d + h)/(x)$

Now, differentiating w.r.t x:

$(d\theta )/(dx) = (d)/(dx)[tan^(-1) (d + h)/(x) - tan^(-1) (d)/(x)]$

For maximum angle, $(d\theta )/(dx)$ = 0

Now,

0 = [/tex]\frac{d}{dx}[tan^{-1} \frac{d + h}{x} - tan^{-1} \frac{d}{x}][/tex]

0 = $(-(d + h))/((d + h)^(2) + x^(2)) -(-d)/(x^(2) + d^(2))$

$(-(d + h))/((d + h)^(2) + x^(2)) = \frac{{d}{x^(2) + d^(2)}$

After solving the above eqn, we get

x = $\sqrt{(d)/(d + h)}$

The observer should stand at a distance equal to x = $\sqrt{(d)/(d + h)}$

Final answer:

For optimum viewing of a painting in a gallery, an observer should position themselves a distance away from the painting calculated using Pythagoras theorem, forming a right-angled triangle with the painting and the floor. This distance can be expressed as c = √[(h/2 + d)² + (h/2)²], where h is the height of the painting and d is the height from the observer's eye to the bottom of the painting.

Explanation:

In the physics of optics, the viewer should position themselves to where they form a right-angled triangle with the ceiling and the painting leading to the best viewing experience. This is widely known as the 'normal viewing distance'.

Given that the painting has a height h and its lower edge is at a distance d above the observer's eye, the observer should stand a distance away from the wall, which can be calculated using Pythagoras' theorem in right triangles, which states that the square of the hypotenuse (c) is equal to the sum of the square of the other two sides (a and b), i.e., c² = a² + b²

Since the painting height and viewer height forms the right-angle in this case, we have: a = (h/2 + d), and b = h/2. Substituting a and b in Pythagoras equation, we can solve for c which is the required distance: c = √[(h/2 + d)² + (h/2)²]

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Air enters an adiabatic compressor at 104 kPa and 292 K and exits at a temperature of 565 K. Determine the power (kW) for the compressor if the inlet volumetric flow rate is 0.15 m3/s. Use constant specific heats evaluated at 300 K.

Answers

Answer:

$\dot W_(in) = 49.386\,kW$

Explanation:

An adiabatic compressor is modelled as follows by using the First Law of Thermodynamics:

$\dot W_(in) + \dot m \cdot c_(p)\cdot (T_(1)-T_(2)) = 0$

The power consumed by the compressor can be calculated by the following expression:

$\dot W_(in) = \dot m \cdot c_(v)\cdot (T_(2)-T_(1))$

Let consider that air behaves ideally. The density of air at inlet is:

$P\cdot V = n\cdot R_(u)\cdot T$

$P\cdot V = (m)/(M)\cdot R_(u)\cdot T$

$\rho = (P\cdot M)/(R_(u)\cdot T)$

$\rho = ((104\,kPa)\cdot (28.02\,(kg)/(kmol)))/((8.315\,(kPa\cdot m^(3))/(kmol\cdot K) )\cdot (292\,K))$

$\rho = 1.2\,(kg)/(m^(3))$

The mass flow through compressor is:

$\dot m = \rho \cdot \dot V$

$\dot m = (1.2\,(kg)/(m^(3)))\cdot (0.15\,(m^(3))/(s) )$

$\dot m = 0.18\,(kg)/(s)$

The work input is:

$\dot W_(in) = (0.18\,(kg)/(s) )\cdot (1.005\,(kJ)/(kg\cdot K))\cdot (565\,K-292\,K)$

$\dot W_(in) = 49.386\,kW$

An electron moving at 3.94 103 m/s in a 1.23 T magnetic field experiences a magnetic force of 1.40 10-16 N. What angle does the velocity of the electron make with the magnetic field? There are two answers between 0° and 180°. (Enter your answers from smallest to largest.)

Answers

Answer:

10.4⁰ and 169.6⁰

Explanation:

The force experienced by the moving electron in the magnetic field is expressed as F = qvBsinθ where;

q is the charge on the electron

v is the velocity of the electron

B is the magnetic field strength

θ is the angle that the velocity of the electron make with the magnetic field.

Given parameters

F = 1.40*10⁻¹⁶ N

q = 1.6*10⁻¹⁹C

v = 3.94*10³m/s

B = 1.23T

Required

Angle that the velocity of the electron make with the magnetic field

Substituting the given parameters into the formula:

1.40*10⁻¹⁶ = 1.6*10⁻¹⁹ * 3.94*10³ * 1.23 * sinθ

1.40*10⁻¹⁶ = 7.75392 * 10⁻¹⁹⁺³sinθ

1.40*10⁻¹⁶ = 7.75392 * 10⁻¹⁶sinθ

sinθ = 1.40*10⁻¹⁶/7.75392 * 10⁻¹⁶

sinθ = 1.40/7.75392

sinθ = 0.1806

θ = sin⁻¹0.1806

θ₁ = 10.4⁰

Since sinθ is positive in the 1st and 2nd quadrant, θ₂ = 180-θ₁

θ₂ = 180-10.4

θ₂ = 169.6⁰

Hence, the angle that the velocity of the electron make with the magnetic field are 10.4⁰ and 169.6⁰

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