What can you say about density if volume increase and mass stays the same

Answers

Answer 1
Answer: Density = mass
              volume 

For the sake of explanation, let's pretend the mass is 2g and the volume is 1 ml

Density = 2 g = 2 g/ml
              1 ml

Now if we increase the volume, and leave the mass the same then mass is still 2g, but we can increase the volume to 2 ml 

Density = 2 g   = 1 g/ml
              2 ml

Therefore we can say that if volume increases and mass stays the same, then density will decrease.
Answer 2
Answer: Well we know that density is equal to mass by volume, written scientifically as such:
ρ = m/v
Let's plug in some numbers to see how this looks, we'll say the object weighs 1 kg and it's volume is 2 cm^3
Thus, ρ = 1 kg / 2 cm^3
So, density in this case is equal to 1/2 kg for every cm^3.
Now let's increase the volume and keep the mass. We'll double the volume.
ρ = 1 kg / 4 cm^3
Now the density comes out to 1/4 kg for every cm^3, which is obviously less. 
We've come to the conclusion, then, that as volume increases and mass stays the same, density decreases. Therefore volume and density are inversely proportioned.

This makes sense mathematically, but does it make sense if we just think about it? It invariably does.
What is density? Density is just how much mass is stuck in a certain space. As such, when you increase that space, but keep the mass, the mass will be more sparsely distributed.
Think of it like this, you've a small room filled to the brim with toys, should you increase the room size, but keep the same amount of toys, then the toys would be further spread apart.
It is the same way with mass and volume.
Hope this helps :)

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Which of the following combinations would result in the largest attractionbetween particles?
Large charges close together
Small charges close together
Large charges far apart from each other
OSmall charges far apart from each other

Answers

Answer:

Explanation:

Large charges close together maybe

A catalyst is added to a system at equilibrium. If the temperature remains constant, the activation energy of the forward reaction(1) decreases(2) increases(3) remains the same

Answers

When a catalyst is added to a system the equilibrium concentration remains unchanged. A catalyst increases the activation energy of the forward reaction. The correct option is 2.

What is a catalyst?

A substance which increases the rate of a reaction without itself undergoing any permanent change chemically or quantitatively is defined as the catalyst and the phenomenon is known as the catalysis. It is believed that a catalyst usually participates in the chemical reaction and it speeds up.

In short, the catalyst lowers the energy barrier and thereby provides a different path of lower activation energy for the reaction so that the rate of the reaction increases.

A catalyst speeds up both the forward and backward reactions to the same extent and does not alter equilibrium constant. Thus it speeds up the attainment of equilibrium faster.

Thus the correct option is 2.

To know more about catalyst, visit;

brainly.com/question/1565029

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The catalyst would increase the rate of the forward reaction...

And increase the rate of the backward to the same extent thus not affecting equilibrium.



Does anyone know the redox equation for galvanic corrosion that occurs between copper and iron?(basically the corrosion of the statue of liberty)

Answers

I'm not completly sure but this might be it. Fe-> Fe2+ + 2e-

Both renewable and non renewable give us what?

Answers

Answer: Both heat and energy.

Explanation:

1-Propanol is combusted to provide heat. The equation and the enthalpy change for the process are shown below. C₃H₇​OH(l)+4.5O₂​( g)→3CO₂​( g)+4H₂​O(l)ΔH=−2,021 kJ Below is a list of sentences that describe a chemical process. Choose all of the sentences that apply to the above rea Check all that apply. a This process is exothermic. b The enthalpy change for 2C₃H₇​OH(l)+9O₂​( g)→6CO₂​( g)+8H₂​O(l) is 2,021 kJ c The enthalpy change for 2C₃H₇​OH(l)+9O₂​( g)→6CO₂​( g)+8H₂​O(l) is −4,042 kJ d The enthalpy change for 2C₃H₇​OH(l)+9O₂​( g)→6CO₂​( g)+8H₂​O(l) is −2,021 kJ e This chemical process transfers heat from the surroundings to the system. f The enthalpy change for 2C₃H₇​OH(l)+9O₂​( g)→6CO₂​( g)+8H₂​O(l) is 4,042 kJ g This process is endothermic. h This chemical process transfers heat from the system to the surroundings.

Answers

Explanation:

Let's analyze the statements one by one:

a) This process is exothermic.

True. The negative enthalpy change (-2,021 kJ) indicates that heat is released during the reaction, making it exothermic.

b) The enthalpy change for 2C₃H₇OH(l)+9O₂(g)→6CO₂(g)+8H₂O(l) is 2,021 kJ.

False. The balanced chemical equation and enthalpy change given are for the combustion of 1 mole of propanol, not 2 moles.

c) The enthalpy change for 2C₃H₇OH(l)+9O₂(g)→6CO₂(g)+8H₂O(l) is -4,042 kJ.

False. This statement suggests a doubled enthalpy change value in the wrong direction. The correct direction is negative (exothermic), but the magnitude is not doubled.

d) The enthalpy change for 2C₃H₇OH(l)+9O₂(g)→6CO₂(g)+8H₂O(l) is -2,021 kJ.

False. This statement suggests the correct direction but doubles the magnitude. The correct magnitude is -2,021 kJ for 1 mole of propanol.

e) This chemical process transfers heat from the surroundings to the system.

False. The process is exothermic, which means it releases heat from the system to the surroundings.

f) The enthalpy change for 2C₃H₇OH(l)+9O₂(g)→6CO₂(g)+8H₂O(l) is 4,042 kJ.

False. This statement suggests the correct magnitude but in the wrong direction. The correct direction is negative (exothermic).

g) This process is endothermic.

False. The process is exothermic, as indicated by the negative enthalpy change.

h) This chemical process transfers heat from the system to the surroundings.

True. An exothermic process like this releases heat from the system to the surroundings.

So, the correct statements are:

a) This process is exothermic.

e) This chemical process transfers heat from the surroundings to the system.

h) This chemical process transfers heat from the system to the surroundings.

What is the volume of 70.0 g of ether if density os 0.70 g/mL

Answers

D = m / V

0.70 g/mL = (70.0g)/(V)

V = (m)/(D)

V = (70.0g)/(0.70g/mL)

V = 100 mL

hope this helps!