MATHEMATICS HIGH SCHOOL

Determine whether AB and C D are parallel, perpendicular, or neither.A (8,4), B (4, 3), C (4, -9), and D (2, -1)

Answers

Answer 1
Answer:

Answer:

To determine whether AB and CD are parallel, perpendicular, or neither, we need to analyze their slopes.

The slope of a line passing through two points (x1, y1) and (x2, y2) can be calculated using the slope formula:

slope = (y2 - y1) / (x2 - x1)

Let's calculate the slopes of AB and CD:

AB:

Point A (8, 4)

Point B (4, 3)

slope of AB = (3 - 4) / (4 - 8) = -1 / -4 = 1/4

CD:

Point C (4, -9)

Point D (2, -1)

slope of CD = (-1 - (-9)) / (2 - 4) = 8 / -2 = -4

Now, let's analyze the slopes:

1. If the slopes of AB and CD are equal, then the lines are parallel.

In this case, the slope of AB is 1/4 and the slope of CD is -4. Since the slopes are different, AB and CD are not parallel.

2. If the product of the slopes is -1, then the lines are perpendicular.

In this case, the product of the slopes of AB and CD is (1/4) * (-4) = -1. Since the product is -1, AB and CD are perpendicular.

Therefore, AB and CD are perpendicular to each other.

In summary, AB and CD are perpendicular lines.

Step-by-step explanation:

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If (7, m) is on a circle with center C(−2, 2) and radius 9, what is the value of m?

Answers

First thing I did was check the distance between the point and the center of the circle on the x-axis, because that was the information already given. Turns out that 7 - (-2) = 9, and so m is equal to the y-value of the center of the circle.

m = 2

Hope that helps!

What is the value of (6a-2)

Answers

It totally depends on the value of 'a', and if 'a' changes, then (6a-2) immediately changes too. Whatever 'a' is at the moment, (6a-2) is 2 less than 6 times 'a'.

(5y^4-3y^3+2y^2-6y+5)+(-3y^+6y^3-4y^2-4y-8)

can someone simplify that

Answers

assuming in the second bracket, 3y is to the power of 4:
you put each power seperatly:
5y^4+(-3y^4)
-3y^3+6y^3
2y^2+(-4y^2)
-6y+-4y
5+(-8)

you get:
2y^4
3y^3
-2y^2
-10y
-2

so the answer is 2y^4+3y^3-2y^2-10y-2

Classify the triangle by its sides and then by its angle

Answers

Answer:

equilateral right triangle

Step-by-step explanation:

7^2+7^2=c^2

49+49=c^2

c^2=98

c=10

Therefore, equilateral right triangle

Macky wants to open a checking account. He is examining different banks and banking accounts. Then he will choose a bank account for his needs. Which of the following statements should not be one of Macky’s reasons for choosing a bank?a.
Being more informed leads to being better prepared to make financial decisions.
b.
Banks could have charges that Macky does not know about until reading carefully.
c.
The first bank Macky considered offered a chance to win a prize upon opening an account.
d.
He will become more aware of how well banks meet his particular needs.

Answers

Answer:

Option C is the correct answer.

Step-by-step explanation:

The following statement should not be one of Macky’s reasons for choosing a bank - The first bank Macky considered offered a chance to win a prize upon opening an account.

Rest all options should be considered as they are very important. Proper information is needed before anyone opens an account and it is the responsibility of the bank person to inform you about every detail. You should also read all the terms and conditions carefully.
I believe the answer is C 

P^2-4p-32/p+4A. –p + 8; p ≠ –4
B. p – 8; p ≠ –4
C. –p – 8; p ≠ –4
D. p + 8; p ≠ –4

Answers

The answer is B. p – 8; p ≠ –4

The expression is: ( p^(2)-4p-32)/(p+4)
Since the the divisor cannot be zero, that means that p+4 cannot be zero:
p + 4 ≠ 0
⇒ p ≠ -4

Let's simplify this expression:
( p^(2)-4p-32)/(p+4) = ( (p+4)(p-8))/(p+4)

Now, cancel out (p+4) and you will get:
( (p+4)(p-8))/(p+4) = p-8
p^2-4p-32=(p-8)(p+4)

(p^2-4p-32)/(p+4)= ((p-8)(p+4))/(p+4)=p-8
and p must not be equal to -4


B is answer
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