Ruby walks from 0.3 m to -45.5 m over the course of 2.2 minutes. what is her average velocity?

Answers

Answer 1
Answer:

Answer:

Explanation:

velocity=distance/time

velocity=x

distance=45.8 meters

time=2.2 minutes

x=45.8/2.2

x=0.34 m/s


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The precision of a voltmeter is ±0.005 V. The accepted value for a measurement is 9.016 V. Which measurement is in the accepted range?

Answers

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Calculate the maximum kinetic energy of photoelectrons emitted from this plate when light of wavelength (λ) 520nm is directed at the metal surface.Work function (Ф) of the plate = 1.1 × 10⁻¹⁹ J
Planck's constant (h) = 6.63 × 10⁻³⁴ Js
Frequency (f) = c ÷ λ
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Wavelength must be in metres, so it'll be 590×10⁻⁹

I've worked this out and gotten two different answers so I thought I'd check to see which one is right.

Answers

Well for a start, 520nm is 520 nanometres and for some reason you've called it 590 x10^-9 (590 isn't standard form) where it's actually 5.2 ×10^-7 metres.
Put that into the equations:

f = c/λ = 3.0 x10^8/5.2 ×10^-7 = 5.77 x10^14 (3 s.f.)
(5.77 x10^14) x (6.63 x10^-34) - (1.1 x10^-19) =
2.73 x10^-19 J

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Answers

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Which method of calculating volume would you use if the object is irregulary shaped?

Answers

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Why mirrors show texts in reverse order?

Answers

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Each of 100 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first block is pulled with a force of 100 N. What is the tension in the string connecting block 100 to block 99? What is the tension in the string connecting block 50 to block 51?

Answers

We have that for the Question "What is the tension in the string connecting block 100 to block 99? What is the tension in the string connecting block 50 to block 51?"

it can be said that

  • The tension in the string connecting block 100 to block 99 = 1N
  • The tension in the string connecting block 50 to block 51 = 50N

From the question we are told

Each of 100 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first block is pulled with a force of 100 N.

Assuming mass of each block is 1 kg

The equation for the force is given as

F = ma\n\na = (F)/(m)\n\n = (100)/(100*1)\n\n = 1 m/s^2

Now, between block 100 and 99,

F = ma\n\nF = 1*1 \n\n= 1 N

Now between block 50 and 51. There are 50 blocks behind 51 st block,  so,

m = 50 Kg\n\na = 1 m/s2 (assuming all blocks accelerate at same rate)\n\nF = 50 * 1\n\nF= 50 N

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Answer:

The tension in the string connecting block 50 to block 51 is 50 N.

Explanation:

Given that,

Number of block = 100

Force = 100 N

let m be the mass of each block.

We need to calculate the net force acting on the 100th block

Using second law of newton

F=ma

100=100m* a

ma=1\ N

We need to calculate the tension in the string between blocks 99 and 100

Using formula of force

F_(100-99)=ma

F_(100-99)=1

We need to calculate the total number of masses attached to the string

Using formula for mass

m'=(100-50)m

m'=50m

We need to calculate the tension in the string connecting block 50 to block 51

Using formula of tension

F_(50)=m'a

Put the value into the formula

F_(50)=50m* a

F_(50)=50*1

F_(50)=50\ N

Hence, The tension in the string connecting block 50 to block 51 is 50 N.