A soccer ball is stationary, and gravity is pulling a soccer ball with a force of 25 N. You kick the ball with a force of 40 N. What is the net force? Is the force balanced or unbalanced?

Answers

Answer 1

Answer: To determine the net force acting on the soccer ball, we need to calculate the difference between the force applied by gravity and the force applied by your kick.
Force due to gravity: 25 N
Force applied by your kick: 40 N
The net force is calculated by subtracting the force due to gravity from the force applied by your kick:
Net force = Force applied by your kick - Force due to gravity
= 40 N - 25 N
= 15 N
The net force acting on the soccer ball is 15 N.
Since the net force is not equal to zero, the forces are unbalanced.

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The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How many carbon atoms are in 3.50 g of butane?

Answers

First convert grams to molesusing molar mass of butane that is 58.1 g

3.50g C4H10 x (1 molC4H10)/(58.1g C4H10) = 0.06024 mol C4H10

Now convert moles to molecules by using Avogadro’s number

0.06024 mol C4H10 x (6.022x10^23 molecules C4H10)/(1 molC4H10) = 3.627x10^22 molecules C4H10

And there are 4 carbon atoms in 1 molecule of butane, so usethe following ratio:

3.627 x 10^22 molecules C4H10 x (4 atoms C)/(1 moleculeC4H10)
= 1.45 x 10^23 atoms of carbon are present

$\boxed{{\text{1}}{\text{.45}} * {\text{1}}{{\text{0}}^{{\text{23}}}}{\text{ atoms}}}$ of carbon is present in 3.50 g of butane.

Further Explanation:

Mole is a measure of the amount of substance. It is defined as the mass of a substance that has the same number of fundamental units as there are atoms in 12 g of carbon-12. Such fundamental units can be atoms, molecules or formula units.

Avogadro’s number is the number of units that are present in one mole of the substance. Its value is equal to ${\text{6}}{\text{.022}}*{\text{1}}{{\text{0}}^{{\text{23}}}}\;{\text{units}}$ per mole of substance. These units can be electrons, atoms, molecules or ions.

The formula to calculate the moles of butane is as follows:

${\text{Moles of butane}}=\frac{{{\text{Given mass of butane}}}}{{{\text{Molar mass of butane}}}}$ ......(1)

The given mass of butane is 3.50 g.

The molar mass of butane is 58.12 g/mol.

Substitute these values in equation (1).

$\begin{aligned}{\text{Moles of butane}}&=\left({{\text{3}}{\text{.50 g}}} \right)\left( {\frac{{{\text{1 mol}}}}{{{\text{58}}{\text{.12 g}}}}}\right)\n&={\text{0}}{\text{.060220234 mol}}\n&\approx {\text{0}}{\text{.0602 mol}}\n\end{aligned}$

The molecules of butane are calculated as follows:

${\text{Molecules of butane}}=\left({{\text{Moles of butane}}}\right)\left( {{\text{Avogadro's Number}}}\right)$ ......(2)

The moles of butane is 0.060220234 mol.

The value of Avogadro’s number is ${\text{6}}{\text{.022}}*{\text{1}}{{\text{0}}^{{\text{23}}}}\;{\text{molecules}}$ .

Substitute these values in equation (2).

$\begin{aligned}{\text{Molecules of butane}}{\mathbf&{ = }}\left({0.060220234{\text{ mol}}} \right)\left( {\frac{{{\text{6}}{\text{.022}} *{\text{1}}{{\text{0}}^{{\text{23}}}}{\text{ molecules}}}}{{{\text{1 mol}}}}}\right)\n&={\text{3}}{\text{.62646}}*{\text{1}}{{\text{0}}^{{\text{22}}}}{\text{ molecules}}\n&\approx {\text{3}}{\text{.626}}*{\text{1}}{{\text{0}}^{{\text{22}}}}{\text{molecules}}\n\end{aligned}$

One molecule of butane has four carbon atoms. So the number of carbon atoms in ${\text{3}}{\text{.62646}}* {\text{1}}{{\text{0}}^{{\text{22}}}}{\text{ molecules}}$ of butane is calculated as follows:

${\text{Atoms of carbon}}=\left( {{\text{Molecules of butane}}}\right)\left( {\frac{{{\text{4 carbon atoms}}}}{{{\text{1 butane molecule}}}}}\right)$

.......(3)

Substitute ${\text{3}}{\text{.62646}}*{\text{1}}{{\text{0}}^{{\text{22}}}}{\text{ molecules}}$ for the molecules of butane in equation (3).

$\begin{aligned}{\text{Atoms of carbon}}&=\left( {{\text{3}}{\text{.62646}}* {\text{1}}{{\text{0}}^{{\text{22}}}}{\text{ molecules}}}\right)\left({\frac{{{\text{4 carbonatoms}}}}{{{\text{1 molecule}}}}} \right)\n&= 1.45 * {\text{1}}{{\text{0}}^{{\text{23}}}}{\text{ atoms}}\n\end{aligned}$

Therefore the number of atoms of carbon is ${\mathbf{1}}{\mathbf{.45 * 1}}{{\mathbf{0}}^{{\mathbf{23}}}}{\mathbf{ atoms}}$ .

Learn more:

1. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: brainly.com/question/3064603

2. Calculate the moles of ions in the solution: brainly.com/question/5950133

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Mole concept

Keywords: mole, atoms of carbon, molecules of butane, carbon-12, 12 g, Avogadro’s number, butane, moles of butane, electrons, molecules, atoms.

What is scientific consensus?O a new scientific idea that was confirmed by the original researcher
an idea that has been changed due to new information
O a general agreement among scientists about a scientific idea
the understanding that knowledge in a particular area can be uncertain

Answers

The scientific consensus is a general agreement among scientists about a scientific idea. The correct option is C.

What is a scientific idea?

A scientific idea is the explanation or facts of science. It reveals the truth about the world. How the world works and the secrets of nature. It tells and gathers true information about the world.

The different aspects of life and the world are understood and studied by scientists. Different scientists work for different forms of life. The scientist's ideas change over the different evidence.

The generalized ideas of various scientists give and agree upon the different theories of the levels of science. The publication process and specialized field.

Thus, the correct option is C. a general agreement among scientists about a scientific idea.

To learn more about the scientific ideas, refer to the link:

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Answer:

it's C

Explanation:

got it right on EDG 2021

What is the name of the compound with the chemical formula (NH4)2S?A. ammonium sulfide
B. hydrogen sulfate
C. sulfur hydride
D. sulfuric acid

Answers

NH₄⁺ - ammonium cation
S²⁻ - sulfide anion

(NH₄)₂S - ammonium sulfide
The answer is A.

Final answer:

The compound with the chemical formula (NH4)2S is ammonium sulfide. This name signifies the presence of two ammonium ions and a single sulfide ion in the compound.

Explanation:

The compound with the chemical formula (NH4)2S is ammonium sulfide. In this compound, there are two ammonium ions (NH4) for every sulfide ion (S2-). The positive charge of the two ammonium ions balances the negative charge of the sulfide ion, forming a neutral compound. The prefixes and suffixes in the name of the compound indicate the elements present and their ratios.

Learn more about Ammonium Sulfide here:

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Which of the following measurements has three significant figures?A. 5100 m
B. 0.005 m
C. 0.510
D. 0.051

Answers

The correct answer is C: 0.510 m

N I C E - D A Y!

Answer:

Explanation:

a) has 2 sig. figures

b) has 1 sig. figures

c) has 3 sig. figures

d) has 2 sig. figures

What is the concentration of O2(g), in parts per million, in a solution that contains 0.008 gram of O2(g) dissolved in 1000. grams of H2O(l)?

Answers

concentration of O₂ dissolved in H₂O can be written as ppm

ppm stands for parts per million - mg/kg

the amount of mg in 1 kg of solution

the mass of O₂ - 0.008 g

1000 mg equivalent to 1 g

therefore mass of O₂ in mg - 0.008 g x 1000 mg/g = 8 mg

the mass of water is 1000 g

1000 g is equivalent to 1 kg

mass of water in kg - 1000 g / 1000 g/kg = 1 kg

there's 8 mg of O₂ in 1 kg of water

therefore concentration of O₂ is - 8 mg/kg

also can be written as 8 ppm

answer is 8 ppm

Answer : The concentration of $O2(g)$ in parts per million is, 8 ppm

Solution : Given,

Mass of oxygen gas (solute) = 0.008 g

Mass of water (solvent) = 1000 g

First we have to calculate the mass of solution.

Mass of solution = Mass of solute + Mass of solvent = 0.008 + 1000 = 1000.008 g

Now we have to calculate the concentration of $O2(g)$ in parts per million.

ppm : It is defined as the mass of solute present in one million $(10^6)$ parts by mass of the solution.

$ppm=\frac{\text{Mass of solute}}{\text{Mass of solution}}* 10^6$

Now put all the given values in this expression, we get

$ppm=(0.008g)/(1000.008g)* 10^6=7.99=8ppm$

Therefore, the concentration of $O2(g)$ in parts per million is, 8 ppm

A 1.540 gram sample of an alloy containing only tin and zinc was reacted with excess fluorine gas to produce 2.489 grams in total of a mixture of tin IV fluoride and zinc fluoride. Calculate the percent composition by mass of the two metals in the alloy.

Answers

Answer:

Tin: 54.3%

Zinc: 45.7%

Explanation:

The molar masses of the elements are:

Tin: Sn = 117.710 g/mol

Zinc: Zn = 65.409 g/mol

Fluorine: F = 18.998 g/mol

The fluorine gas in excess, so the reaction consumes all the alloy, and all the tin is converted to SnF₄ and all the zinc is converted to ZnF₂. The molar masses of the fluorides are:

SnF₄ = 117.710 + 4*18.998 = 193.702 g/mol

ZnF₂ = 65.409 + 2*18.998 = 103.405 g/mol

If we call x the number of moles of SnF₄, and y the number of moles of ZnF₂, the total mass can be calculated knowing that the mass is the number of moles multiplied by the molar mass:

193.702x + 103.405y = 2.489

The number of moles of Sn is the same as SnF₄ (1:1), and also the number of moles of Zn is the same as ZnF₂ (1:1), so the mass of the alloy:

117.710x + 65.409y = 1.540

if we multiply it by -1.581 and sum with the other equation:

117.710x*(-1.581) + 65.409y*(-1.581) + 193.702x + 103.405y = 1.540*(-1.581) + 2.489

7.60249x = 0.05426

x = 0.0071 mol of Sn

117.710*0.0071 + 65.409y = 1.540

65.409y = 0.704259

y = 0.0108 mol of Zn

The masses are the molar mass multiplied by the number of moles:

Sn: 117.710*0.0071 = 0.836 g