Rule 2: hydrogen ---ate becomes ____________ acid

Answers

Answer 1
Answer:

Answer:

Binary Acid

Explanation:

But an acid with 2 hydrogens is called polyprotic acid


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What sample size (grams) of Na3PO4 (FW 164.00) known to be 50.00% pure should be used to consume exactly 40.00 mL of 0.1000 M HCl to reach the 2nd end point

Answers

Answer:

0.109 g.

Explanation:

Equation of the reaction:

Na3PO4 + 3HCl --> 3NaCl + H3PO4

Number of moles of HCl = molar concentration × volume

= 0.1 × 0.04

= 0.004 mol.

By stoichiometry, 1 mole of Na3PO4 neutralises 3 moles of HCl. Therefore, number of moles of Na3PO4 = 0.004/3

= 0.0013 mol

Mass of Na3PO4 = molar mass × number of moles

= 0.0013 × 164

= 0.219 g

Since 50% of Na3PO4 was present in the sample. Let 100 g be the total mass of the substance

= 0.219 × 50 g/100 g

= 0.109 g.

A 50.0-gram block of copper at 10.0°C is carefully lowered into 100.0 grams of water at 90.0°C in an insulated container. Which statement describes the transfer of heat in this system?(1) The water loses heat to the block until both are at 10.0°C.
(2) The block gains heat from the water until both are at 90.0°C.
(3) The water loses heat and the block gains heat until both are at the same temperature that is between 10.0°C and 90.0°C.
(4) The water gains heat and the block loses heat until both are at the same temperature that is between 10.0°C and 90.0°C.

Answers

First consider and take note of the following: 
1. When 2 or more finite amounts of substances are mix together (with different temperature) the final temperature is never equivalent to the initial temperature of any of the substances involved. 
2. The substances meet at an equilibrium temperature. 
3. Heat transfers from a higher temperature to a lower temperature. 

Only choice (3) satisfies the conditions. 

Final answer:

Heat transfers from the water to the copper block until both reach an equilibrium temperature.

Explanation:

The transfer of heat in this system can be described by (4) The water gains heat and the block loses heat until both are at the same temperature that is between 10.0°C and 90.0°C.

This is because heat always flows from the object with higher temperature to the object with lower temperature. In this case, the water at 90.0°C has a higher temperature than the copper block at 10.0°C. As a result, heat will transfer from the water to the copper block, causing the water to cool down and the copper block to heat up. Eventually, both objects will reach an equilibrium temperature somewhere between 10.0°C and 90.0°C.

Learn more about Heat Transfer here:

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Which of these solutions has the highest freezing point?1.0 M molecular sucrose (C12H22O11)
1.0 M ionic sodium chloride (NaCl)
1.0 M ionic calcium bromide (CaBr2)
1.0 M ionic aluminum bromide (AlBr3)
1.0 M ionic potassium chloride (KCl)

Answers

Answer: 1.0 M molecular sucrose (C₁₂H₂₂O₁₁).


Explanation:


1) The depression of the freezing point of a solvent when you add a solute is a colligative property.


2) Colligative properties are those physical properties of solutions that depends on the number of solute particles dissolved into the solution.


3) The relation between the number of solute particles and the depresson of the freezing point is proportional: the greater the number of solute particles the greater the freezing point depression.


4) You need to find the solution with the highest freezing point, this is the solution in which the freezing point decreased the least.


5) Then, that is the solution with least number of solute particles.


6) Since all the given solutions have the same molarity (1.0 M), you only have to deal with the possible ionization of the different solutes.


7) NaCl, CaBr₂, AlBr₃, and KCl are ionic compounds, so each unit of them will ionize into two, three, four, and two ions, respectively, while sucrose, being a covalent compound does not dissociate.


Then, 1.0 M solution of sucrose will have less solute particles than the others, and will exhitibit the lowest freezing point depression, meaning that it will have the highest freezing point of the given solutions.



The right answer for the question that is being asked and shown above is that: "1.0 M ionic aluminum bromide (AlBr3)." the solution that has the highest freezing point is that 1.0 M ionic aluminum bromide (AlBr3)

Which of the following is NOT a produce of the neutralization reaction between hydrochloric acid and sodium carbonate?A. Sodium chloride
B. Carbon dioxide
C. Water
D. Sodium hydroxide

Answers

Answer: D. Sodium hydroxide

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

Neutralization reaction is a type of double displacement reaction where an acid reacts with base to produce salt and water.

HCl+Na_2CO_3\rightarrow NaCl+H_2O+CO_2

Thus on reacting hydrochloric acid and sodium carbonate we get sodium chloride, water and carbon dioxide as products.

Hope this helps, have a nice day ahead!

One hundred students were surveyed about who they would vote for. What isthe best way to display the results? Explain your answer.

Answers

Hey hope this helps ⬇️

HELP 2. The Kinetic Energy of a particle can be represented by _______________.
(2 Points)
A. mass x speed
B. 1/2 mass x velocity
C. mass x velocity
D. 1/2 mass x velocity squared

Answers

Answer:

D

Explanation: