PHYSICS HIGH SCHOOL

A boy cycles a distance of 960 m from home to school in 6 minutes. Calculate his average speed for the journey. Write your answer in m/s.

Answers

Answer 1

Answer:

The average speed of the boy was 2,67m/s.

The average speed is found when we divide the distance traveled (Δx) by the travel time (Δt).

The formula is:

$\Huge\boldsymbol{V_(av)=(\Delta x)/(\Delta t)}$

Solving:

Data:

Distance: 960m

Time: 6min ⇒ (6 · 60) ⇒360s

We have:

$\LARGE\text{$V_(av)=(960)/(360)$}\n\n\n\n\Huge\boldsymbol{V_(av)\approx2,67m/s}$

The average speed of the boy for his journey is approximately2,67m/s.

_________

Know more:

About speed:

Hope this helps!

Answer 2

Answer: To calculate the average speed of the boy's journey, you can use the formula:

Average Speed (in m/s) = Distance (in meters) / Time (in seconds)

First, you need to convert the time from minutes to seconds because 1 minute equals 60 seconds:

6 minutes = 6 * 60 seconds = 360 seconds

Now, you can calculate the average speed:

Average Speed = 960 meters / 360 seconds = 2.67 m/s

So, the boy's average speed for the journey is approximately 2.67 meters per second.

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The time, t, required to drive a fixed distance varies inversely as the speed, r. It takes 9 hr at a speed of 20 km/h to drive a fixed distance. How long will it take to drive the same distance at a speed of 23 km/h?

If the current in the circuit above is 10 amps and the resistance is 3 ohms, what is the voltage?

Answers

It's really difficult to make out the circuit above. Quite frankly, your
question leaves me to wonder how far 'above' it may be.
The best I can do will be to try and fabricate an answer based on the
information given in the text of the question, augmented only by my own
training, chutzpah, and life experiences.

If the circuit ... wherever it is ... consists entirely of the single 3-ohm
resistance and no other components, and the current through the
resistance is 10 Amperes, then

Voltage = (Current) x (resistance) = 30 volts .

What is meant by the following statement? "Inertia is directly proportional to mass." Inertia and mass are the same thing. Inertia and mass are the same size. Inertia increases as mass decreases. Inertia increases as mass increases.

Answers

Inertia increases as mass increases.

Explanation:

Inertia is the resistance of an object to any change in motion. Inertia is proportional the mass of the object: in fact, as we experience in common situations, the larger the mass of an object, the more difficult it is to change its motion.

A simple example: while it is quite easy to stop a tennis ball thrown towards us, we know that it is not so easy to stop a large truck travelling towards us with the same speed: the reason for that is that the truck has much more mass than the tennis ball, so it has much more inertia. Therefore, inertia increases as mass increases.

inertia increases as mass increases. In fact, mass is what causes inertia

A 9.0 volt battery is connected to four resistors in a parallel circuit. The resistors have 7.0 Ω, 5.0 Ω, 4.0 Ω, and 2.0 Ω respectively. What is the total current in the circuit?

Answers

series,effective resistance =R₁+R₂+R₃...
parallel,effective resistance 1/R=1/R₁ +1/R₂ +1/R₃...

Here,effective resistance 1/R =1/7 +1/5+ 1/4+1/2
=1.092
R = 1/1.092 =0.915Ω
voltage V=9 V
current I=V/R
I=9 / 0.915
=9.83 A

parallel resistance = $(1)/(7)$ + $(1)/(5)$ + $(1)/(4)$ + $(1)/(2)$
= $(140)/(153)$

now , V= 9V
V = IR
I = $(V)/(R)$
I = $(9)/(140)$ x 153
I = 9.835714 A

There are three main types of clouds. the high cirrus clouds, the layered stratus clouds, and what third type of puffy clouds?

Answers

The third type of cloud is the cumulus cloud

A motorcycle traveling at a speed of 44.0 mi/h needs a minimum of 44.0 ft to stop. If the same motorcycle is traveling 79.0 mi/h, determine its minimum stopping distance (in ft), assuming the same rate of acceleration.

Answers

Answer:

141.78 ft

Explanation:

When speed, u = 44mi/h, minimum stopping distance, s = 44 ft = 0.00833 mi.

Calculating the acceleration using one of Newton's equations of motion:

$v^2 = u^2 + 2as\n\nv = 0 mi/h\n\nu = 44 mi/h\n\ns = 0.00833 mi\n\n=> 0^2 = 44^2 + 2 * a * 0.00833\n\n=> 1936 = -0.01666a\n\na = -116206.48 mi/h^2 or -14.43 m/s^2$

Note: The negative sign denotes deceleration.

When speed, v = 79mi/h, the acceleration is equal to when it is 44mi/h i.e. -116206.48 mi/h^2

Hence, we can find the minimum stopping distance using:

$v^2 = u^2 + 2as\n\nv = 0 mi/h\n\nu = 79 mi/h\n\na = -116206.48 mi/h\n\n=> 0^2 = 79^2 + (2 * -116206.48 * s)\n\n6241 = 232412.96s\n\ns = (6241)/(232412.96) \n\ns = 0.0268531 mi = 141.78 ft$

The minimum stopping distance is 141.78 ft.

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Answers

Answer:

legislative branch

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