CHEMISTRY HIGH SCHOOL

a cylinder with a moveable piston contains 0.553 mol of gas and has a volume of 253 ml. what is its volume if has 0.365 mol of gas in the cylinder. (assume constant temperature and pressure.)

Answers

Answer 1
Answer:

Answer:

V = 0.167L

Explanation:

We can use the ideal gas law:

PV = nRT

where P, V, and T are pressure, volume, and temperature (Kelvin only).  R is the gas constant and n is the moles of gas.

We want the volume of gas when the moles changes.  Let's set up two equations, 1 for each state.  Since both temperature and pressure are constant, we can simply use the terms P and T both states.

 Initial (0.553 moles and 253 ml)):  P*(0.253L) = (0.553 moles)RT

Second (0.365 moles, unknown volume, V):  P*V = (0.365 moles)RT

P*(0.253L) = (0.553 moles)RT

P*V = (0.365 moles)RT

  Lets set these up as a ratio:

      P*(0.253L)/P*V = ((0.553 moles)RT)/((0.365 moles)RT)

P, T and R all cancel to 1, and the moles unit cancels:

    (0.253L)/V = (0.553)/((0.365)

The ratio of the volumes is in direct proportion with the ratio of the moles.

Rearrange and solve:

        (0.253L) = (0.553)/((0.365)V

        (0.253L)*(0.365/0.553) = V

            V = 0.167L

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