Which of the following was NOT a conclusion of Rutherford’s gold foil experiment? a. The atom is mainly empty space
b. The nucleus has a negative charge
c. The atom has a dense nucleus
d. Alpha particles can pass through a thin sheet of gold foil
e. All of the above are correct regarding the gold foil experiment

Answers

Answer 1

Answer: The answer is b.) The nucleus has a negative charge

It was not a conclusion because it is neutral. It is not positive nor negative.

Related Questions

Write a chemical equation for the following decomposition reaction.Nickel(II) hydroxide(s) decomposes to produce nickel(II) oxide(s) and water.
A solution containing 1000g of an unknown substance in 12.3g of naphthalene was found to freeze at 1.2∘C. What is the molar mass of the unknown substance?
1. Jack consumes two slices of pizza and drinks two large glasses of soda. Half an hour later, he complains of a stomachache. What is the most likely reason for Jack's upset stomach?A. Soda and lactose from the cheese combined and slowed enzyme activity. B. Soda mixed with the pizza sauce and sped up digestive enzyme activity. C. Soda raised the pH in his stomach and sped up digestive enzyme activity. D. Soda lowered the pH in his stomach and slowed digestive enzyme activity. 2. Which factor decreases the rate of a chemical reaction? A. An inhibitor B. A co-factor C. Increased substrate D. Cold temperature 3. Which component decreases the activation energy of a chemical reaction? A. An inhibitor solution B. Presence of an enzyme C. Lower substrate concentration D. Neutral pH levels 4. A biologist adds a vitamin solution to an enzyme/substrate solution that requires co-factors. What will happen to the substrate? A. The vitamins will bond to the enzymes and increase their reactivity with the substrates. B. The vitamins will bond to the enzymes and decrease their reactivity with the substrates. C. The substrate molecules will bond to the vitamin molecules and inhibit bonding of the enzyme. D. The substrate molecules will bond to the vitamin molecules and stimulate bonding of the enzyme. 5. Jennifer stews peaches to make peach jelly. She believes the homemade jelly will make a healthy treat full of vitamins and enzymes her body needs. Which of the following disproves her prediction? A. The peaches don't contain enzymes. B. The jelly has too much sugar to be healthy. C. The enzymes in the peaches have denatured. D. The vitamins in the peaches will inhibit the enzymes. 6. What statement best describes what happens during the catalytic cycle? A. The enzyme breaks the substrate apart to prepare for the reaction. B. The enzyme positions the substrate to increase access during a reaction. C. The substrate uses enzyme energy to start the reaction. D. The active site releases the substrate and replaces it with an inhibitor.
Can someone how to do these problems!!
Which substance below will exhibit hydrogen bonding between the molecules of the substance? a. CH₄ b. HBr c. HCl d. H₂O e. H₂

A saline solution with a mass of 400 g has 30 g of NaCl dissolved in it. What is the mass/mass percent concentration of the solution?

Answers

(g solute/g solution)*100 = % mass/mass

30 g / 400 * 100

0,075 * 100

= 7,5% w/w

hope this helps!

A laboratory requires 2.0 L of a 1.5 M solution of hydrochloric acid (HCl), but the only available HCl is a 12.0 M stock solution. How could you prepare the solution needed for the lab experiment? show all work to find your answer

Answers

Answer: The volume of stock HCl solution required to make laboratory solution will be 0.25L

Explanation:

To calculate the volume of stock solution required to make the laboratory solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of stock solution.

$M_2\text{ and }V_2$ are the molarity and volume of laboratory solution.

We are given:

$M_1=12M\nV_1=?L\nM_2=1.5M\nV_2=2L$

Putting values in above equation, we get:

$12* V_1=1.5* 2\n\nV_1=0.25L$

Hence, the volume of stock HCl solution required to make laboratory solution will be 0.25L

The amount of the solute is constant during dilution. So the mole number of HCl is 2*1.5=3 mole. The volume of HCl stock is 3/12=0.25 L. So using 0.25 L stock solution and dilute to 2.0 L.

How many moles of copper are equivalent to 3.44 × 1023 atoms of copper?

Answers

3.44x10^23 divided by 6.02x10^23 equals 0.571 mol Cu.

A lahar is a type of mudflow that occurs

Answers

after a volcanic eruption is the answer

Mudflows of volcanic eruptions are the most dangerous, and are called lahars

Water that has condensed and formed water droplets on the ground, grass, and other outdoor objects is known as _____.a. fog
b. dew
c. groundwater
d. surface runoff

Answers

The correct answer is B. Water that has condensed and formed water droplets on the ground, grass, and other outdoor objects is known as dew. It is water formed due to condensation in early morning or evening. It is formed when the temperature of the objects reach below the dew point of the air around.

Answer:

The answer is B. Dew Hopefully this helps!

Is the following a chemical change or a physical change? A pencil is sharpened in a pencil sharpener, leaving behind shaving. Physical Change Chemical Change

Answers

This is an example of physical change, because the pencil's chemical composition does not change.

*Physical Change.*
A physical change in a substance doesn't change what the substance is.
A Chemical change, there is a chemical reaction, a new substance is formed and energy is either given off or absorbed.

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After reading a book about parrots, Tani wants to learn more about them. Which question could be answered through scientific investigation?A. Which bird’s eggs taste the best? B. What substances make up an eggshell? C. Which birds have the most beautiful feathers? D. Which type of bird makes the best pet in an apartment?

The rock record indicates that photosynthesis began on Earth about 3.5 million years ago. a. Trueb. False

How many moles are in 136.9 g of Ba(OH)2?

What is the formula for carbon tetrachloride?a. CCl b. CCl2 c. CCl3 d. CCl4