A solution containing 1000g of an unknown substance in 12.3g of naphthalene was found to freeze at 1.2∘C. What is the molar mass of the unknown substance?

Answers

Answer 1
Answer:

Answer: Therefore, the molar mass of the unknown substance is 68.4 g/mol.

Explanation: We can use the freezing point depression equation to solve for the molar mass of the unknown substance:

ΔT = Kf × m

where ΔT is the change in freezing point, Kf is the freezing point depression constant of the solvent (naphthalene), and m is the molality of the solution.

First, we need to calculate the molality of the solution:

molality = moles of solute / mass of solvent (in kg)

We don't know the number of moles of the unknown substance, but we can assume that the naphthalene does not contribute significantly to the total mass of the solution (since its mass is much smaller than the mass of the unknown substance). Therefore, we can use the entire mass of the solution (1000g + 12.3g = 1012.3g) as the mass of solvent.

mass of solute = 1000g

mass of solvent = 12.3g

mass of solution = 1012.3g

molality = (1000g / molar mass) / (12.3g / 1000g) = 81.3 / molar mass

Next, we need to calculate the change in freezing point:

ΔT = 1.2∘C

Finally, we can use the freezing point depression constant of naphthalene to solve for the molar mass of the unknown substance:

Kf for naphthalene = 6.8∘C/m

ΔT = Kf × m

1.2 = 6.8 × (81.3 / molar mass)

molar mass = 68.4 g/mol

Therefore, the molar mass of the unknown substance is 68.4 g/mol.


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How many moles of oxygen will be released when 250.0 grams of KClO3 is thermally decomposed ? 2KClO3 --> 2KCl+3O2<br /><br /> (Must be made to fit into this chart)

Answers

Molar mass KClO₃ = 122.5 g/mol and O₂ = 32.0 g/mol

2 KClO₃ ----------------> 2 KCl + 3 O₂

2 * 122.5 g KClO₃ ---------> 3 * 32 g O₂
250.0 g KClO₃ ------------> ?

mass of O₂ = 250.0 * 3 * 32 / 2 * 122.5

mass of O₂ = 24000 / 245

mass of O₂ = 97.959 g

number of moles O₂ :

1 mole --------- 32.0 g
? mole -------- 97.959 g

moles = 97.959 * 1 / 32.0

= 97.959 / 32.0

= 3.061 moles of O₂

hope this helps!

Which formula represents lead(II) chromate?(1) PbCrO4 (3) Pb2CrO4
(2) Pb(CrO4)2 (4) Pb2(CrO4)3

Answers

The formula that represents Lead (II) Chromate is PbCrO4. It is a chemical compound with a strong yellow color. 

Lead chromate and lead sulfate are found in the crystal Pb(Cr, S)O₄, which is a changeable solid mixed phase. This material is the end product of a co-precipitation reaction between lead and chrome salts (see the chapter on production and usage for further information). The correct option is 1.

Water does not dissolve lead chromate, which is produced by the double decomposition process. It is also used as a pigment and is referred to as chrome yellow. In a media that has been buffered with a solution of acetic acid and lead acetate, the lead precipitates as chrome.

There may be significant amounts of water-soluble lead compounds in lead chromate pigments. The formula that represents Lead (II) Chromate is PbCrO₄.

Thus the correct option is 1.

To know more about lead(II) chromate, visit;

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What is the pressure in a gas container that is connected to an open-end u-tube manometer if the pressure of the atmosphere is 742 torr and the level of mercury in the arm connected to the container is 8.60 cm higher than the level of mercury open to the atmosphere?

Answers

First, know that 8.60 cm = 86.0 mm, which is equivalent to an 86.0 torr pressure difference between the atmosphere and the container. 

In this situation the pressure in the container is less than the atmosphere.  

742 - 86 = 656 torr

Answer: 656 mmHg

Explanation:

Manometers are used to measure the pressure in a container by comparing it to normal atmospheric pressure.

First convert the atmospheric pressure to mmHg

1 torr = 1 mmHg

Therefore, the atmospheric pressure = 742 mmHg

Since the arm connected is higher than the level of the Mercury open to the atmosphere, then the gas pressure is lower than the atmospheric pressure.

Hence,

Pgas = Patm - change in height

Pgas = 742 mmHg - 8.6 cmHg

Balance the unit: 10 mm = 1 cm

Then,

Pgas = 742 mmHg - 86 mmHg

Pgas = 656 mmHg

The gas pressure in the container is 656 mmHg.

A solution has a pOH of 8.7 so what is the pH of the solution? Is the solution acidic, basic, or neutral?

Answers

pOH scale is used to determine the basicity of a solution

pH scale is used to determine the acidity of a solution

pH and pOH are related in the following formula

pH + pOH = 14

once pOH is known we can calculate pH

pOH = 8.7

pH = 14 - 8.7

pH = 5.3


pH of the solution is 5.3


when pH is less than 7 the solution is said to be acidic

when pH is equal to 7 then solution is neutral

when pH is more than 7 then solution is basic

the pH of the solution here is 5.3 which is less than 7, therefore solution is acidic

acidic solution with pH of 5.3

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 8.7

pH = 5,3

This solution is acidic.

If pH<7 - acidic
If pH=7 - neutral
If pH>7 - basic

How do we know that caramelizing sugar is a chemical change ?

Answers

Chemical transformation: it's all transformation changes the composition of matter, i.e. that matter produces a new substance with different initial properties burning sugar to make caramel, we cannot retrieve the initial sugar.

hope this helps!

3. Rank each of the following in order of DECREASING atomic radius
a. Cl, Br, Ga

Answers

Answer:

Br,Ga,Cl?

Explanation: