CHEMISTRY HIGH SCHOOL

Which of the following is not capable of reacting with molecular oxygen?A. SO₂
B. SO₃
C. NO
D. N₂O
E. P₄O₆

Answers

Answer 1
Answer: I think letter b were you put the letters so

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True or False: Since baking soda is a powder, all the substances it breaks down intoare also powders.

Answers

False; Sodium hydrogen carbonate (also known as sodium bicarbonate or bicarbonate of soda) has the chemical formula NaHCO3. When it is heated above about 80°C it begins to break down, forming sodium carbonate, water and carbon dioxide. This type of reaction is called a thermal decomposition.

Which has should only be produced in a fume hood?a. Cl2
b. CO2
c. H2
d. H2O

Answers

The gas that should only be produced in a fume hood is a. Cl2.
Chlorine gas is toxic gas. Upon inhalation, it irritates the pulmonary tract and damages the respiratory tract. Both short term and long term exposure to Cl2 gas are known to have destructive effects.

Carbon-14 has a half-life of 5,730 y. How much of a 144g sample of carbon-14 will remain after 1.719x10 ^4 y.

Answers

To determine how much of a 144g sample of carbon-14 will remain after 1.719 x 10^4 years, you can use the formula for exponential decay:

\[N(t) = N_0 \cdot \left(\frac{1}{2}\right)^{\frac{t}{T}}\]

Where:

- \(N(t)\) is the remaining amount after time \(t\).

- \(N_0\) is the initial amount.

- \(t\) is the time that has passed.

- \(T\) is the half-life.

In this case, \(N_0\) is 144g, \(t\) is 1.719 x 10^4 years, and \(T\) is the half-life of carbon-14, which is 5,730 years.

Plug these values into the formula:

\[N(t) = 144g \cdot \left(\frac{1}{2}\right)^{\frac{1.719 \times 10^4\text{ years}}{5,730\text{ years}}}\]

Now, calculate:

\[N(t) = 144g \cdot \left(\frac{1}{2}\right)^{\frac{3}{2}}\]

\[N(t) = 144g \cdot \left(\frac{1}{2} \cdot \frac{1}{2} \cdot \frac{1}{2}\right)\]

\[N(t) = 144g \cdot \frac{1}{8}\]

Now, multiply 144g by 1/8 to find the remaining amount:

\[N(t) = \frac{144g}{8} = 18g\]

So, after 1.719 x 10^4 years, only 18g of the 144g sample of carbon-14 will remain.

What is the molar mass of a substance

Answers

Explanation:

An atom or object that occupies space also has mass. Molar mass or molecular weight is the mass of 1 mole of a substance.

The formula to calculate molar mass is as follows.

            Molar mass = (mass in grams)/(mole)

For example, molar mass of Na_(2)CO_(3) will be as follows

       2 * mass of sodium atom + 1 *s mass of carbon atom + 3 * mass of oxygen atom

     =  (2 * 22.99 + 1 *s 12.01 + 3 * 16.00)  g/mol

    = (45.98 + 12.01 + 48.00) g/mol

    = 105.99 g/mol

Therefore, it can be concluded that the sum of mass of all the atoms in grams make up 1 mole of a particular molecule. This mass is known as the molar mass or molecular weight.
Molar mass is the mass of one mole of that substance. atomic mass of an element in atomic mass units is equal to the molar mass of that substance in grams.

Which two gases make up most of the atmosphere?

Answers

nitrogen wich comprises 78% of the atmosphere and oxygen wich accounts for 21%

What is the limiting reactant if 4.0 g of Nh3 react with 8.0 g of oxygen?

Answers

Answer : The limiting reagent is O_2.

Solution : Given,

Mass of NH_3 = 4.0 g

Mass of O_2 = 8.0 g

Molar mass of NH_3 = 17 g/mole

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of NH_3 and O_2.

\text{ Moles of }NH_3=\frac{\text{ Mass of }NH_3}{\text{ Molar mass of }NH_3}=(4.0g)/(17g/mole)=0.24moles

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=(8.0g)/(32g/mole)=0.25moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

4NH_3+5O_2\rightarrow 4NO+6H_2O

From the balanced reaction we conclude that

As, 5 mole of O_2 react with 4 mole of NH_3

So, 0.25 moles of O_2 react with (0.25)/(5)* 4=0.20 moles of NH_3

From this we conclude that, NH_3 is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Hence, the limiting reagent is O_2.
NH3-The limiting reactant is the reactant that get completely used up in a reaction
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