CHEMISTRY HIGH SCHOOL

What is the chemical formula for zinc carbonate?(1) ZnCO3(2) Zn(CO3)2
(3) Zn2CO3
(4) Zn3CO3

Answers

Answer 1
Answer: The chemical formula for Zinc Carbonate is ZnCO3.

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An element X belongs to 4th period and 17th group. Write the formula of the compound formed when it reacts with Y( atomic no.-13, mass no.27.)

Answers

all element in group 17th have their oxidation number to be -1 and for the other element its shell configuration should be 2,8,3...therefore its oxidation number should be +3
therefore the formular should be YX3

Most of the time, combustion reactions occur when hydrocarbons react with what element?

Answers

Answer:

Explanation:

Combustion means the process by which the burning of any substance, whether gaseous, liquid or solid, occurs. In this process, the fuel oxidizes and gives off heat, and, frequently, light.

Combustion reactions are reactions where oxygen intervenes as a reagent. Oxygen has the ability to combine with various elements to produce oxides, where then oxidation is the combination of oxygen with another substance. There are oxidations that are extremely slow, but when oxidation is rapid it is called combustion.

When a substance containing carbon and hydrogen (a hydrocarbon) undergoes complete combustion, or burning, oxygen is consumed and carbon dioxide is produced, and water. Incomplete combustion can also occur when part of the fuel does not react completely because oxygen is not enough.
In a complete combustion reaction compound reacts with an oxidizing element, such as oxygen or fluorine, and the products are compounds of each element in the fuel with the oxidizing.

A new potential heart medicine, code-named X-281, is being tested by a pharmaceutical company, Pharma-pill. As a research technician at Pharma-pill, you are told that X-281 is a monoprotic weak acid, but because of security concerns, the actual chemical formula must remain top secret. The company is interested in the drug's Ka value because only the dissociated form of the chemical is active in preventing cholesterol buildup in arteries.To find the pKa of X-281, you prepare a 0.089 M test solution of X-281 at 25.0 ∘C. The pH of the solution is determined to be 2.40.
a. What is the pKa of X-281? Express your answer numerically.
At 25∘C, for any conjugate acid-base pair
pKa + pKb = 14.00
b. What is pKb of the conjugate base of X-281? (Assume 25 ∘C.) Express your answer numerically.

Answers

Answer:

a. pka = 3,73.

b. pkb = 10,27.

Explanation:

a. Supposing the chemical formula of X-281 is HX, the dissociation in water is:

HX + H₂O ⇄ H₃O⁺ + X⁻

Where ka is defined as:

ka = ([H_3O^+][X^-])/([HX])

In equilibrium, molar concentrations are:

[HX] = 0,089M - x

[H₃O⁺] = x

[X⁻] = x

pH is defined as -log[H₃O⁺]], thus, [H₃O⁺] is:

[H_3O^+]} = 10^(-2,40)

[H₃O⁺] = 0,004M

Thus:

[X⁻] = 0,004M

And:

[HX] = 0,089M - 0,004M = 0,085M

ka = ([0,004][0,004])/([0,085])

ka = 1,88x10⁻⁴

And pka = 3,73

b. As pka + pkb = 14,00

pkb = 14,00 - 3,73

pkb = 10,27

I hope it helps!

The compound known as butylated hydroxytoluene, abbreviated as BHT, contains carbon, hydrogen, and oxygen. A 1.376 g sample of BHT was combusted in an oxygen rich environment to produce 4.122 g of CO 2 ( g ) and 1.350 g of H 2 O ( g ) . Insert subscripts to complete the empirical formula of BHT.

Answers

Answer:

C15H24O

Explanation:

TO GET THE EMPIRICAL FORMULA, WE NEED TO KNOW THE MASSES AND CONSEQUENTLY THE NUMBER OF MOLES OF EACH OF THE INDIVIDUAL CONSTITUENT ELEMENTS.

FIRSTLY, WE CAN GET THE MASS OF THE CARBON FROM THAT OF THE CARBON IV OXIDE. WE NEED TO KNOW THE NUMBER OF MOLES OF CARBON IV OXIDE GIVEN OFF. THIS CAN BE CALCULATED BY DIVIVDING THE MASS BY THE MOLAR MASS OF CARBON IV OXIDE. THE MOLAR MASS OF CARBON IV OXIDE IS 44G/MOL

HENCE, THE NUMBER OF MOLES OF CARBON IV OXIDE IS 4.122/44 WHICH EQUALS 0.094. SINCE THERE IS ONLY ONE ATOM OF CARBON IN CO2 THEN THEY HAVE EQUAL NUMBER OF MOLES AND THUS THE NUMBER OF MOLES OF CARBON IS 0.094. WE CAN THEN PROCEED TO CALCULATE THE MASS OF CO2 PRESENT. THIS CAN BE CALCULATED BY MULTIPLYING THE NUMBER OF MOLES BY THE ATOMIC MASS UNIT. THE ATOMIC MASS UNIT OF CARBON IS 12. HENCE, THE MASS OF CO2 PRESENT IS 12 * 0.094 = 1.128g

WE CAN NOW GET THE MASS OF THE HYDROGEN BY MULTIPLYING THE NUMBER OF MOLES OF WATER BY 2 AND ALSO ITS ATOMIC MASS UNIT

TO GET THE NUMBER OF MOLES OF WATER, WE SIMPLY DIVIDE THE MASS BY THE MOLAR MASS. THE MOLAR MASS OF WATER IS 18g/mol.  The NUMBER OF MOLES IS THUS 1.350/18 = 0.075

THE NUMBER OF MOLES OF HYDROGEN IS TWICE THAT OF WATER SINCE IT CONTAINS 2 ATOMS PER MOLECULE OF WATER. ITS NUMBER OF MOLES IS THUS 0.075*2 = 0.15 MOLE

THE MASS OF HYDROGEN IS THUS 0.075 * 2 * 1 = 0.15g

WE CAN NOW FIND THE MASS OF OXYGEN BY SUBTRACTING THE MASSES OF HYDROGEN AND CARBON FROM THE TOTAL MASS.

MASS OF OXYGEN = 1.376-0.15-1.128 = 0.098g

THE NUMBER OF MOLES OF OXYGEN IS THUS 0.098/16 = 0.006125

WE CAN NOW USE THE NUMBER OF MOLES TO OBTAIN THE EMPIRICAL FORMULA.

WE DO THIS BY DIVIDING EACH BY THE SMALLEST NUMBER OF MOLES WHICH IS THAT OF THE OXYGEN.

C = 0.094/0.006125 = 15

H = 0.15/0.006125 = 24

O = 1

THE EMPIRICAL FORMULA IS THUS C15H24O

The combustion of 1.376 g of butylated hydroxytoluene (BHT) produced 4.122 g CO2 and 1.350 g H2O. Calculations yield an empirical formula of CH2O, indicating one carbon, two hydrogen, and one oxygen atom.

To determine the empirical formula of butylated hydroxytoluene (BHT), we can follow these steps:

1. **Find moles of CO2 and H2O produced:**

  \[ \text{moles of } CO_2 = \frac{\text{mass of } CO_2}{\text{molar mass of } CO_2} \]

  \[ \text{moles of } H_2O = \frac{\text{mass of } H_2O}{\text{molar mass of } H_2O} \]

2. **Find the mole ratio:**

  Divide the moles of each element (C, H, and O) in CO2 and H2O by the smallest number of moles.

3. **Write the empirical formula:**

  Use the mole ratios to write the empirical formula.

Let's perform the calculations:

\[ \text{Molar mass of } CO_2 = 12.01 \, \text{(C)} + 2 \times 16.00 \, \text{(O)} = 44.01 \, \text{g/mol} \]

\[ \text{Molar mass of } H_2O = 2 \times 1.01 \, \text{(H)} + 16.00 \, \text{(O)} = 18.02 \, \text{g/mol} \]

\[ \text{moles of } CO_2 = \frac{4.122 \, \text{g}}{44.01 \, \text{g/mol}} \approx 0.0938 \, \text{mol} \]

\[ \text{moles of } H_2O = \frac{1.350 \, \text{g}}{18.02 \, \text{g/mol}} \approx 0.0749 \, \text{mol} \]

Divide by the smallest number of moles (0.0749) to get a ratio close to 1:1:

\[ \text{C} : \text{H} : \text{O} \approx 1.25 : 1 : 1 \]

The ratio is approximately 1:1:1, so the empirical formula is CH2O.

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Why does chlorine have a higher ionization energy than aluminum

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Hi okay so the answer to question is

What is the relationship between concentration and rate of reaction

Answers

Reaction rate is affected by concentration. When the concentration of the reactants are raised, the rate of reaction is increased as well. Increase in concentration promotes more effective collisions. The exact relation of reaction rates on concentration is dependent on the mechanism of the reaction.

The relationship between concentration and rate of reaction is directly proportional. As the concentration of reactants increases, the rate of the reaction also increases.

What is the relationship between concentration and rate of reaction?

The rate of a chemical reaction is determined by the collision of reactant particles. When the concentration of reactants is higher, there are more particles per unit volume, increasing the likelihood of successful collisions. More collisions lead to more effective collisions, where the particles have sufficient energy and proper orientation to form products.

As a result, the reaction proceeds at a faster pace. This direct relationship between concentration and rate of reaction is described by the rate law of the specific reaction. The greater the concentration of the reactants, the more rapid the reaction will occur.

Concentration and rate of reaction are directly proportional; an increase in concentration leads to a corresponding increase in the reaction rate.

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