What are m and n in the rate law equation? Rate = k[A]^m[B]^n A. They are the coefficients obtained from the equation. B. They are the starting temperatures of the reactants. C. They are the molar masses of the reactants. D. They are experimentally determined exponents.
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I just did it, the correct answer is actually D. They are experimentally determined exponents.
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What is the empirical formula for a compound if a sample contains 3.72 g of P and 21.28 g of Cl?
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Drawing a conclusion derived from knowledge of an established principle is called deductive reasoning.True or false?
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The formation of these products usually involves THE FISCHER-TROPSCH PROCESS.
The Fischer-Tropsch process refers to a series of chemical reactions which convert hydrogen and carbon monoxide into liquid hydrocarbons in the presence of metal catalysts. The temperature utilized in the process is normally between 150 and 300 degree Celsius. The techniques was developed by Franz Fischer and Hans Tropsch in 1925. The technique is usually used to turn coal into liquid and to turn gases to liquid fuels.
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1m=1000mm
International System of Units (SI Units) are organized body of measurements for physical quantity. They are set to be the norm or global norm scaling for every physical quantity which includes kilogram, meter, second, ampere, kelvin, candela and mole. These measurements then can increase or decrease by the power of ten, multiplied or divided. As said and explained, the SI is helpful in describing objects because
1. They give us the idea of how much matter is contained in that single substance or the current state the matter is in or how hot or cold. We measure and can quantify the quality of the specific matter.
2. SI Units are a global set of measurement hence, we can communicate with ease from western to eastern countries with these measurements without having problems in terms of portraying or displaying a set of physical quantities.
Answer:hello
Explanation:
Task masters
Is correct! It should be answer(4) or (D)
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Answer:
The correct statement is that the concentration of the acid in the solution will increase.
Explanation:
On the basis of the given question, if one dissolves 10 milliliters of acid in a beaker of water, the acid will get diluted. As the number of moles of acid is not going to change, thus, one can use the formula:
M1V1 = M2V2
Here, M is the concentration of the acid in the solution,
V1 = 10 ml
V2 = V water + 10
If we supplement, an other 5 ml of acid, the new concentration of the acid will be:
M = M1 (5 ml) + M2 (Vwater + 10 ml) / (5 ml + V water + 10 ml)
Therefore, the concentration of the acid in the new solution will increase.
Answer:
the concentration of acid in the solution has been increased.
Explanation:
the answer is C on edge.
b. Oxygen
c. Hydrogen
d. Nitrogen
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Answer: The correct answer is Option d.
Explanation:
Dry air is composed of a mixture of gases like argon, oxygen, nitrogen, carbon dioxide and many other gases present in trace amount.
The percentage of these gases by volume in dry air is:
Carbon dioxide = 0.03%
Argon = 0.93%
Oxygen = 20.95%
Nitrogen = 78.09%
Hydrogen = Trace amounts
From the above percentage values, we can easily say that nitrogen has the highest percentage by volume in dry air. Hence, the correct option is d.
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Answers
Cl is chlorine. Since their is 5 of chlorine, we call it pentachloride. Penta means 5, as in the shape PENTAgon.
Compound Name: Phosphorus pentachloride
We can see here that the compound with the formula, is called phosphorus pentachloride.
What is a compound?
A compound is a substance that consists of two or more different elements chemically bonded together in fixed proportions. In a compound, the constituent elements lose their individual properties and form new chemical properties unique to the compound.
The study of compounds is central to chemistry, as it involves understanding the structure, composition, and reactivity of substances. Compound analysis and synthesis play vital roles in various scientific fields, such as materials science, pharmaceuticals, and environmental science.
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